Stars and Galaxies (MindTap Course List)
10th Edition
ISBN: 9781337399944
Author: Michael A. Seeds
Publisher: Cengage Learning
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Textbook Question
Chapter 3, Problem 1P
Pretend the Moon’s orbit around Earth is a perfect circle. How long does it take in units of days for the Moon to move 90 degrees relative to the stars? Is this number dependent on the synodic period or the sidereal period?
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To find the acceleration from equation (a=v^2/r), the velocity of an object traveling in a circle is the distance traveled (i.e. the circumference, which is 2?r) divided by the travel time (i.e. the period T). The Moon’s sidereal period is 27.32 days. Convert this period into seconds. Complete Table 1 for the Moon to find its orbital period in seconds, its average velocity in meters per second and its acceleration in meters per second^2 where Orbital radius (m) = 3.84 x 10^8.
Chapter 3 Solutions
Stars and Galaxies (MindTap Course List)
Ch. 3 - Prob. 1RQCh. 3 - Prob. 2RQCh. 3 - Prob. 3RQCh. 3 - Prob. 4RQCh. 3 - Prob. 5RQCh. 3 - Prob. 6RQCh. 3 - Prob. 7RQCh. 3 - Prob. 8RQCh. 3 - Prob. 9RQCh. 3 - Prob. 10RQ
Ch. 3 - Prob. 11RQCh. 3 - Prob. 12RQCh. 3 - Prob. 13RQCh. 3 - Why do solar eclipses happen only at new moon? Why...Ch. 3 - Prob. 15RQCh. 3 - Prob. 16RQCh. 3 - What is the angular diameter of the Moon in the...Ch. 3 - Why cant the Moon be eclipsed when it is halfway...Ch. 3 - Prob. 19RQCh. 3 - Prob. 20RQCh. 3 - Prob. 21RQCh. 3 - Prob. 22RQCh. 3 - Pretend the Moons orbit around Earth is a perfect...Ch. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10PCh. 3 - Prob. 11PCh. 3 - Examine the list of upcoming lunar eclipses in...Ch. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - When will the eclipse described in Problem 15 next...Ch. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 1SPCh. 3 - Prob. 2SPCh. 3 - Prob. 1LLCh. 3 - Prob. 2LLCh. 3 - Prob. 3LLCh. 3 - Prob. 4LLCh. 3 - Prob. 5LLCh. 3 - Prob. 6LLCh. 3 - Prob. 7LLCh. 3 - Prob. 8LLCh. 3 - Prob. 9LLCh. 3 - Prob. 10LLCh. 3 - Prob. 11LL
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- In a part of Earth’s orbit where Earth is moving faster than usual around the Sun, would the length of the sidereal day change? If so, how? Explain.arrow_forwardThe earth revolves around the sun in exactly 365 1/4 days which is equivalent to 1 year. To make up for the loss of 1/4 day, the calendar was adjusted so that we have a leap year for every 4 years. If the earth were to speed in its motion slightly so that a year would be completed in exactly 365 days and 6 hours, how often would we need to have a leap year?arrow_forwardWhat would be the duration of the year, if the distance between the earth and the sun gets doubled ? (a) 129 days (b) 365 days (c) 556 days (d) 1032 dayşarrow_forward
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- The earth takes 365.256 days to go around the sun and 23 hours 56 min and 4.0905 s to revolve about its axis. These give the earth an orbital speed of 29.8 km/s and a rotational speed of 465 m/s at the equator, a 64:1 ratio. If the moon orbits the earth in a period of 29 d 12 h 44 min 2.9 s, has a sidereal period of 27.321582 days, a radius of 1737 km, and a mean distance from the earth of 384,000 km, what is the similar velocity ratio for the moon?arrow_forwardMars' period (its "year") was noted by Kepler to be about 687 days (Earth days), which is (687d / 365 d) = 1.88 yr. Determine the distance of Mars from the Sun using the Earth as reference. (The distance of Earth from the Sun is 1.50 x 10 m) !3! Thu TMS IMS TE TES TES TE 2 28 x 10 m TES yr After reading and understanding the concept Gravity, please do the following problems: 1. What keeps a satellite up in its orbit around the Earth?arrow_forwardCalculate the angle of (a) 10 (degree) (b) 1′ (minute of arc or arcmin) and (c) 1″(second of arc or arc second) in radians. Use 3600=2π rad, 10 =60′ and1′ = 60 ″arrow_forward
- The Earth covers about 1° per day in its orbit about the Sun, and the solar day is slightly longer than the sidereal day. If Earth spun in a retrograde direction like Venus but it still had the same sidereal period (23 hr 56 min), how long would the solar day be? The solar day would be 72 hr and min.arrow_forwardIf city is located in 2.8° north latitude and 46.0° east longitude. From there, you want to fly to a city in 7° north latitude and 52° east longitude. How much is the arc length of the big circle at 11000 m when the earth's radius is 6370 km? The arc length is 14223 km. Give your answer rounded to one kilmetre. Your last answer was interpreted as follows: 14223 XAnswer is incorrect. Keep centre of Earth as origin and define vectors to cities. Try again.arrow_forwardConsider a planet of radius 10 x 106 m for which the length of a sidereal day is 5 x 104 s. Calculate the speed you would have with respect to the center of the planet, in m/s, if you were at a latitude of 5 degrees north. (Please answer to the fourth decimal place - i.e 14.3225)arrow_forward
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