A laser range finder records the distance from the laser to the base and from the laser to the top of a building as shown in Fig. P3.1. Find the angle θ and the height of the building.

Question

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Answer 1

Textbook Question

Chapter 3, Problem 1P

A laser range finder records the distance from the laser to the base and from the laser to the top of a building as shown in Fig. P3.1. Find the angle $θ$ and the height of the building.

Chapter 3, Problem 1P, A laser range finder records the distance from the laser to the base and from the laser to the top

Expert Solution & Answer

To determine

The angle $θ$ and the height of the building.

Answer to Problem 1P

The height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Explanation of Solution

Given:

The given figure representing the building top and range finder is shown below.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 1

Calculation:

Consider the below figure.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 2

First calculate an angle $θ$ ,

From the right angle triangle

$cosθ=Adjecent sideHypotenuse$

$cosθ=75100θ=cos−1( 75 100)=41.4°$

Therefore the angle $θ$

is $41.4°$ .

For the height of the building,

$sinθ=opposite sideHypotenuse$

$sin(41.4°)=h100$

$0.6614=h100$

$h=0.6614×100=66.14m$

Conclusion:

Thus, the height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

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03:54

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Answer 2

Textbook Question

Chapter 3, Problem 1P

A laser range finder records the distance from the laser to the base and from the laser to the top of a building as shown in Fig. P3.1. Find the angle $θ$ and the height of the building.

Chapter 3, Problem 1P, A laser range finder records the distance from the laser to the base and from the laser to the top

Expert Solution & Answer

To determine

The angle $θ$ and the height of the building.

Answer to Problem 1P

The height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Explanation of Solution

Given:

The given figure representing the building top and range finder is shown below.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 1

Calculation:

Consider the below figure.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 2

First calculate an angle $θ$ ,

From the right angle triangle

$cosθ=Adjecent sideHypotenuse$

$cosθ=75100θ=cos−1( 75 100)=41.4°$

Therefore the angle $θ$

is $41.4°$ .

For the height of the building,

$sinθ=opposite sideHypotenuse$

$sin(41.4°)=h100$

$0.6614=h100$

$h=0.6614×100=66.14m$

Conclusion:

Thus, the height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

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03:54

Answer 3

Textbook Question

Chapter 3, Problem 1P

A laser range finder records the distance from the laser to the base and from the laser to the top of a building as shown in Fig. P3.1. Find the angle $θ$ and the height of the building.

Chapter 3, Problem 1P, A laser range finder records the distance from the laser to the base and from the laser to the top

Expert Solution & Answer

To determine

The angle $θ$ and the height of the building.

Answer to Problem 1P

The height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Explanation of Solution

Given:

The given figure representing the building top and range finder is shown below.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 1

Calculation:

Consider the below figure.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 2

First calculate an angle $θ$ ,

From the right angle triangle

$cosθ=Adjecent sideHypotenuse$

$cosθ=75100θ=cos−1( 75 100)=41.4°$

Therefore the angle $θ$

is $41.4°$ .

For the height of the building,

$sinθ=opposite sideHypotenuse$

$sin(41.4°)=h100$

$0.6614=h100$

$h=0.6614×100=66.14m$

Conclusion:

Thus, the height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:54

Answer 4

Textbook Question

Chapter 3, Problem 1P

A laser range finder records the distance from the laser to the base and from the laser to the top of a building as shown in Fig. P3.1. Find the angle $θ$ and the height of the building.

Chapter 3, Problem 1P, A laser range finder records the distance from the laser to the base and from the laser to the top

Expert Solution & Answer

To determine

The angle $θ$ and the height of the building.

Answer to Problem 1P

The height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Explanation of Solution

Given:

The given figure representing the building top and range finder is shown below.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 1

Calculation:

Consider the below figure.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 2

First calculate an angle $θ$ ,

From the right angle triangle

$cosθ=Adjecent sideHypotenuse$

$cosθ=75100θ=cos−1( 75 100)=41.4°$

Therefore the angle $θ$

is $41.4°$ .

For the height of the building,

$sinθ=opposite sideHypotenuse$

$sin(41.4°)=h100$

$0.6614=h100$

$h=0.6614×100=66.14m$

Conclusion:

Thus, the height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:54

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

The angle $θ$ and the height of the building.

Answer to Problem 1P

The height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Explanation of Solution

Given:

The given figure representing the building top and range finder is shown below.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 1

Calculation:

Consider the below figure.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 2

First calculate an angle $θ$ ,

From the right angle triangle

$cosθ=Adjecent sideHypotenuse$

$cosθ=75100θ=cos−1( 75 100)=41.4°$

Therefore the angle $θ$

is $41.4°$ .

For the height of the building,

$sinθ=opposite sideHypotenuse$

$sin(41.4°)=h100$

$0.6614=h100$

$h=0.6614×100=66.14m$

Conclusion:

Thus, the height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Answer 8

Expert Solution & Answer

To determine

The angle $θ$ and the height of the building.

Answer to Problem 1P

The height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Explanation of Solution

Given:

The given figure representing the building top and range finder is shown below.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 1

Calculation:

Consider the below figure.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 2

First calculate an angle $θ$ ,

From the right angle triangle

$cosθ=Adjecent sideHypotenuse$

$cosθ=75100θ=cos−1( 75 100)=41.4°$

Therefore the angle $θ$

is $41.4°$ .

For the height of the building,

$sinθ=opposite sideHypotenuse$

$sin(41.4°)=h100$

$0.6614=h100$

$h=0.6614×100=66.14m$

Conclusion:

Thus, the height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

The angle $θ$ and the height of the building.

Answer 12

Answer to Problem 1P

The height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Answer 13

Explanation of Solution

Given:

The given figure representing the building top and range finder is shown below.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 1

Calculation:

Consider the below figure.

Introductory Mathematics for Engineering Applications, Chapter 3, Problem 1P , additional homework tip 2

First calculate an angle $θ$ ,

From the right angle triangle

$cosθ=Adjecent sideHypotenuse$

$cosθ=75100θ=cos−1( 75 100)=41.4°$

Therefore the angle $θ$

is $41.4°$ .

For the height of the building,

$sinθ=opposite sideHypotenuse$

$sin(41.4°)=h100$

$0.6614=h100$

$h=0.6614×100=66.14m$

Conclusion:

Thus, the height of the building is 66.14 m and the angle $θ$

is $41.4°$ .

Answer 14

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A laser range finder records the distance from the laser to the base and from the laser to the top of a building as shown in Fig. P3.1. Find the angle θ and the height of the building.

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Answer to Problem 1P

Explanation of Solution

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Chapter 3 Solutions

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