Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 3, Problem 15CQ
To determine
To fill:
The correct term in the given blank.
Introduction:
The hardness of the long-chain monomer is determined by the side branches. The high number of branches results in difficulty in the alignment of the atoms.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
In an engineering application, the material is a strip of iron with a fixed crystallographic structure subject to a tensile load during operation. The part
failed (yielded) during operation and needs to be replaced with a component with better properties. You are told that two other iron strips had failed
at yield stresses of 110 and 120 MPa, with grain sizes of 30 microns and 25 microns respectively. The current strip has a grain size of 20 microns. The
diameter of the rod is 1 mm and the load applied is 100 N. What is the yield stress of the new part C and would you recommend it for operation?
Select one:
Oa. 133.5 MPa, yes
O b.
OC.
Od
Oe.
120.5 MPa, no
129.5, yes
140.5, no
123.5 MPa, yes
Explain why the experimental strength of materials are lower than their theoretical strengths.
BI4
Pagr
Which of the following statements are true of dislocations?
Select one or more:
O a. Dislocations can move under stress
O b. Dislocations can arise due to shear deformation of the lattice
O C.
Dislocations can be viewed with high powered microscopy and not with the naked eye
Od. Dislocations primarily enable high stiffness in metals
Chapter 3 Solutions
Materials Science And Engineering Properties
Ch. 3 - Prob. 1CQCh. 3 - Prob. 2CQCh. 3 - Prob. 3CQCh. 3 - Prob. 4CQCh. 3 - Prob. 5CQCh. 3 - Prob. 6CQCh. 3 - Prob. 7CQCh. 3 - Prob. 8CQCh. 3 - Prob. 9CQCh. 3 - Prob. 10CQ
Ch. 3 - Prob. 11CQCh. 3 - Prob. 12CQCh. 3 - Prob. 13CQCh. 3 - Prob. 14CQCh. 3 - Prob. 15CQCh. 3 - Prob. 16CQCh. 3 - Prob. 17CQCh. 3 - Prob. 18CQCh. 3 - Prob. 19CQCh. 3 - Prob. 20CQCh. 3 - Prob. 21CQCh. 3 - Prob. 22CQCh. 3 - Prob. 23CQCh. 3 - Prob. 24CQCh. 3 - Prob. 25CQCh. 3 - Prob. 26CQCh. 3 - Prob. 27CQCh. 3 - Prob. 28CQCh. 3 - Prob. 29CQCh. 3 - Prob. 30CQCh. 3 - Prob. 31CQCh. 3 - Prob. 32CQCh. 3 - Prob. 33CQCh. 3 - Prob. 1ETSQCh. 3 - Prob. 2ETSQCh. 3 - Prob. 3ETSQCh. 3 - Prob. 4ETSQCh. 3 - Prob. 5ETSQCh. 3 - Prob. 6ETSQCh. 3 - Prob. 7ETSQCh. 3 - Prob. 1DRQCh. 3 - Prob. 2DRQCh. 3 - Prob. 3DRQCh. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10PCh. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14P
Knowledge Booster
Similar questions
- Which of the following statements are true of dislocations? Select one or more: a. Dislocations can be viewed with high powered microscopy and not with the naked eye b. Dislocations can move under stress c. Dislocations can arise due to shear deformation of the lattice Od. Dislocations primarily enable high stiffness in metalsarrow_forwardMatch the defects to their labels in the Crystal Structure below A- B D E -Grain Boundary -Interstitial/Impurity -Vacancy -Phase Boundary -Substitution A I Choose] B | Choose ] [ Choose | [ Choose 1 E [ Choose ]arrow_forwardThe constant a for a steel material having an ultimate strength of 106.5 ksi isarrow_forward
- Normal stress of alumiarrow_forwardQ7> Ductile-to-brittle transition temperature (DBTT) is a very important parameter in the design of metallic materials for engineering applications. It has been well known that most of BCC and HCP metals show the DBT phenomenon; however, there is no DBTT in FCC metals. (a) Explain the reason in terms of deformation and fracture. You must compare the BCC and FCC. (b) The ductile fracture surface consists of many dimples. Explain their formation mechanism from the concept of point defects. (c) There are two types in the brittle fracture. Explain and Compare them.arrow_forwardA cylindrical specimen of cold-worked steel has a Brinell hardness of 240. If the specimen remained cylindrical during deformation and its original radius was 11.8 mm, determine its radius after deformation. For steel, the dependence of tensile strength on percent cold work is shown in Animated Figure 7.19b. i mmarrow_forward
- Narrow bars of aluminum are bonded to the two sides of a thick steel plate as shown. Initially, at T₁ = 70°F, all stresses are zero. Knowing that the temperature will be slowly raised to T₂ and then reduced to T₁, determine (a) the highest temperature T₂ that does not result in residual stresses, (b) the temperature T₂ that will result in a residual stress in the aluminum equal to 58 ksi. Assume aa = 12.8 x 10-6/°F for the aluminum and a = 6.5 × 10-6/°F for the steel. Further assume that the aluminum is elastoplastic with E = 10.9 × 106 psi and ay = 58 ksi. (Hint: Neglect the small stresses in the plate.) Fig. P2.121arrow_forwardWhich one is a linear defect in the crystalline materials? (A) external surfaces B) vacancies (c) dislocations (D) grain boundariesarrow_forwardAn iron specimen is plastically deformed in shear by 1%, and it has u dislocation density of 1 10 14 m/ m 3 Assume that the dislocation density did not change in the 1% strain of thisspecimen, the Burger's vector (b) is a 2 [1 1 1] the slip plane is (110). the shear stress isapplied to the (110) plane, and the lattice parameter of the BCC iron is 0.286 nm. Calculate the magnitude of the Burger's vector for these dislocations in iron. Calculate the average distance moved by the mobile dislocations as a result of the 1% shear strain.arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
Materials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning
Materials Science And Engineering Properties
Civil Engineering
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Cengage Learning