The magnitude of the velocity of a projectile when it is at its maximum height above ground level is 10.0 m/s. (a) What is the magnitude of the velocity of the projectile 1.00 s before it achieves its maximum height? (b) What is the magnitude of the velocity of the projectile 1.00 s after it achieves its maximum height? If we take x = 0 and y = 0 to be at the point of maximum height and positive x to be in the direction of the velocity there, what are the (c) x coordinate and (d) y coordinate of the projectile 1.00 s before it reaches its maximum height and the (e) x coordinate and (f) y coordinate 1.0 s after it reaches its maximum height?

A juggler performs in a room whose ceiling is 4.62 m above the level of his hands. He throws a ball upward with an upward speed of v 0 so that it just reaches the ceiling. At the instant when the first ball is at ceiling, the juggler throws a second ball upward with 4 v 0 /3 velocity. At what distance above the juggler’s hand do they pass each other?

A rocket is launched from the origin with an acceleration of 20.0 m/s2 at an angle of 30.0 degrees above the horizontal. The launch acceleration lasts for 2.00 seconds at which time the fuel is exhausted. The rocket then falls with an acceleration of 9.80 m/s2downward. What is the maximum height attained?

A projectile is fired horizontally at V0 velocity from the top of an h-high cliff. Immediately after, it enters a fixed tube of length x. There is friction between the bullet and the tube, and the friction causes the bullet to slow down with constant ax acceleration. After the bullet leaves the tube, it fires a normal oblique shot towards the ground. Calculate the horizontal path of the bullet. (g = 9.8 m / s) V0=6.5 m/s ax=-3.5m/s^2 x=5.5m h=16m

A cannon ball is fired with an initial speed of 123 m/s at angle of 60 degrees from the horizontal. Express the initial velocity as a linear combination of its unit vector components. Vo = ( m/s) i + ( m/s) At the maximum height, the speed of the cannon ball is v = m/s and the magnitude of its acceleration is a = m/s?. The time needed to reach maximum height is t = S. The maximum height reached by the cannon ball is H = m.

A Chinook (King) salmon (Genus Oncorynchus) can jump out of water with a speed of 5.55 m/s. If the salmon is in a stream with water speed equal to 1.65 m/s, how high in the air can the fish jump if it leaves the water traveling vertically upwards relative to the Earth?

A high jumper leaves the ground with an initial velocity of 11.1 m/s rightward at an angle of 17°. What is the high jumper's initial horizontal velocity, in m/s? Answer: m/s

A projectile is fired horizontally at V0 velocity from the top of an h-high cliff. Immediately after, it enters a fixed tube of length x. There is friction between the bullet and the tube, and the friction causes the bullet to slow down with constant ax acceleration. After the bullet leaves the tube, it fires a normal oblique shot towards the ground. Calculate the horizontal path of the bullet. (g = 9.8 m / s)

A horizontal projectile is shot with an initial velocity of 13.9 m/s from a height of 8 m above the ground. Neglecting air-resistance, what is the direction of the final velocity (in degrees)? Hint: angle measured from the horizontal (x-axis), positive for counterclockwise & negative for clockwise.