Physics Laboratory Experiments
8th Edition
ISBN: 9781285738567
Author: Jerry D. Wilson, Cecilia A. Hernández-Hall
Publisher: Cengage Learning
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Textbook Question
Chapter 29, Problem 3Q
How could the value of an unknown capacitance be determined using the experimental procedures? Show explicitly by assuming a value for an experimentally determined time constant.
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The total capacitance of three capacitors connected in series is equal to 6.25 μF . Two of the three capacitors have the following capacitance values, 25 μF and 50 μF while the other one is to be determined. If the three capacitors are connected in parallel , calculate the total capacitance of the parallel combination. Express the answer in Farad (F) using scientific notation.
The total capacitance of three capacitors connected in series is equal to 6.25 µF. Two of the three capacitors have the following
capacitance values, 25 µF and 50 µF while the other one is to be determined. If the three capacitors are connected in parallel, calculate
the total capacitance of the parallel combination. Express the answer in microFarad.
O 85 µF
8.55 µF
O 58 µF
O 50 uF
Chapter 29 Solutions
Physics Laboratory Experiments
Ch. 29 - Prob. 1ASACh. 29 - How is the time base of the horizontal...Ch. 29 - What is the significance of the RC time constant...Ch. 29 - Explain how the time constant of an RC circuit is...Ch. 29 - Judging on the basis of your experimental results,...Ch. 29 - In the form V = Vo(1 et/, the = RC in the...Ch. 29 - How could the value of an unknown capacitance be...
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- When three identical capacitor are connected in series, their equivalent capacitance is 2 µF. Now they are connected in parallel across a source of e.m.f. 200 V. The total energy stored is.arrow_forwardFind the net capacitance for three capacitors connected in parallel, given their individual capacitances are 1.0 μF, 5.0 μF, and 8.0 μF.arrow_forwardFind the total capacitance for three capacitors connected in series, given their individual capacitances are 1.000, 5.000, and 8.000 μF .arrow_forward
- A capacitor is composed of 2 plates separated by a sheet of insulating material 2mm thick and of relative permittivity 3. The distance between the plates is increased to allow the insertion of a second sheet of 3mm thick and of relative permittivity &,. If the equivalent capacitance is one-half of the original capacitance, find the value of ɛ,.arrow_forwardFind the net capacitance (in µF) of the combination of series and parallel capacitors shown below.arrow_forwardA capacitor is composed of 2 plates separated by a sheet of insulating material 3mm thick and of relative permittivity 4. The distance between the plates is increased to allow the insertion of a second sheet of 5mm thick and of relative permittivity &,. If the equivalent capacitance is one third of the original capacitance, find the value of Er.arrow_forward
- What is the equivalent capacitance between points A and B of the following arrangementof capacitors? (Give your answer to the closest nF.)arrow_forwardCompute the equivalent capacitance of the network.arrow_forwardWhy does the labeled capacitance of the capicitor is the same with the computed actual capacitance? What makes them have the same value?arrow_forward
- A 20.0 mF capacitor is charged to a potential differenceof 800 V. The terminals of the charged capacitor are then connectedto those of an uncharged 10.0 mF capacitor. Compute the decrease in energy when the capacitors are connected.arrow_forwardA 30μμF capacitor is charged to 80 V and then connected across an initially uncharged capacitor of unknown capacitance C. If the final potential difference across the 30μμF capacitor is 10 V, determine C.arrow_forwardTwo capacitors, empty inside, and with a capacitance of 2μF, are arranged in parallel and connected to an emf of 9V, reaching electrostatic balance without disconnecting the emf, and a dielectric (k=2.5) is introduced that occupies the entire capacitor. . Determine, for the capacitor that was left empty, the change in electric charge (ΔQ), the stored energy, the magnitude of the electric field vector and the energy density. The distance of the plates is 2.5mm.arrow_forward
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