College Physics: A Strategic Approach (4th Edition)
4th Edition
ISBN: 9780134609034
Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher: PEARSON
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Textbook Question
Chapter 27, Problem 72GP
What is the speed of an electron after being accelerated from rest through a 20 ×106 V potential difference?
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Chapter 27 Solutions
College Physics: A Strategic Approach (4th Edition)
Ch. 27 - Prob. 1CQCh. 27 - Frame S moves relative to frame S as shown in...Ch. 27 - a. Two balls move as shown in Figure Q27.3. What...Ch. 27 - A lighthouse beacon alerts ships to the danger of...Ch. 27 - As a racket passes the earth at 0.75c, it fires a...Ch. 27 - At the instant that a clock standing next to you...Ch. 27 - Prob. 8CQCh. 27 - Firecrackers 1 and 2 are 600 m apart. You are...Ch. 27 - Your clocks and calendars are synchronized with...Ch. 27 - Two trees are 600 m apart. You are standing...
Ch. 27 - Prob. 12CQCh. 27 - In Figure Q27.12, clocks C1 and C2, in frame S are...Ch. 27 - Prob. 14CQCh. 27 - Prob. 15CQCh. 27 - Prob. 16CQCh. 27 - Prob. 17CQCh. 27 - The rocket speeds shown in Figure Q27.18 are...Ch. 27 - Can a particle of mass m have total energy less...Ch. 27 - In your chemistry classes, you have probably...Ch. 27 - Lee and Leigh are twins. At their first birthday...Ch. 27 - A space cowboy wants to eject from his spacecraft...Ch. 27 - Prob. 23MCQCh. 27 - Prob. 24MCQCh. 27 - A particle moving at speed 0.40c has momentum p0....Ch. 27 - A particle moving at speed 0.40c has kinetic...Ch. 27 - A sprinter crosses the finish line of a race. The...Ch. 27 - A baseball pitcher can throw a ball with a speed...Ch. 27 - A boy on a skateboard coasts along at 5 m/s. He...Ch. 27 - A boat takes 3.0 hours to travel 30 km down a...Ch. 27 - When the moving sidewalk at the airport is broken,...Ch. 27 - Prob. 6PCh. 27 - An out-of-control alien spacecraft is diving into...Ch. 27 - Prob. 8PCh. 27 - A starship blasts past the earth at 2.0 103 m/s....Ch. 27 - You are flying at 0.99c with respect to Kara. At...Ch. 27 - Prob. 11PCh. 27 - Bianca is standing at x = 600 m. Firecracker 1, at...Ch. 27 - You are standing at x = 9.0 km Lightning bolt 1...Ch. 27 - A light flashes at position x = 0 m. One...Ch. 27 - Jose is baking to the east. Lightning bolt 1...Ch. 27 - Your 1000-m-long starship has warning lights at...Ch. 27 - There is a lightbulb exactly halfway between the...Ch. 27 - Prob. 18PCh. 27 - A cosmic ray travels 60 km through the earths...Ch. 27 - Prob. 20PCh. 27 - At what speed relative to a laboratory does a...Ch. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - An astronaut travels to a star system 4.5 ly away...Ch. 27 - A subatomic particle moves through the laboratory...Ch. 27 - At what speed as a fraction of c, will a moving...Ch. 27 - Jill claims that her new rocket is 100 m long. As...Ch. 27 - Prob. 28PCh. 27 - A muon travels 60 km through the atmosphere at a...Ch. 27 - Prob. 30PCh. 27 - The Stanford Linear Accelerator (SLAC) accelerates...Ch. 27 - Our Milky Way galaxy is 100,000 ly in diameter. A...Ch. 27 - The X-15 rocket-powered plane holds the record for...Ch. 27 - Youre standing on an asteroid when you see your...Ch. 27 - A rocket cruising past earth at 0.800c shoots a...Ch. 27 - Prob. 36PCh. 27 - A base on Planet X fires a missile toward an...Ch. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - Prob. 40PCh. 27 - Prob. 41PCh. 27 - Prob. 42PCh. 27 - What are the kinetic energy, the rest energy, and...Ch. 27 - Prob. 44PCh. 27 - A quarter-pound hamburger with all the fixings has...Ch. 27 - Prob. 46PCh. 27 - How fast much an electron move so that its total...Ch. 27 - Prob. 48PCh. 27 - At what speed is a particle's kinetic energy twice...Ch. 27 - Prob. 50PCh. 27 - Prob. 51PCh. 27 - Prob. 52PCh. 27 - The chemical energy of gasoline is 46 MJ/kg. If...Ch. 27 - A standard nuclear power plant generates 3.0 GW of...Ch. 27 - A firecracker explodes at x = 0 m, t = 0 s. A...Ch. 27 - Prob. 56GPCh. 27 - Prob. 57GPCh. 27 - A very fast-moving train car passes you, moving to...Ch. 27 - A spaceship heads directly toward an asteroid at a...Ch. 27 - Prob. 60GPCh. 27 - Prob. 61GPCh. 27 - Prob. 62GPCh. 27 - A spaceship flies past an experimenter who...Ch. 27 - Marissas spaceship approaches Josephs at a speed...Ch. 27 - At a speed of 0.90c, a spaceship travels to a star...Ch. 27 - Prob. 66GPCh. 27 - A rocket traveling at 0.500c sets out for the...Ch. 27 - A distant quasar is found to be moving away from...Ch. 27 - A space beacon on Planet Karma emits a pulse of...Ch. 27 - Two rockets, A and B, approach the earth from...Ch. 27 - Prob. 71GPCh. 27 - What is the speed of an electron after being...Ch. 27 - What is the speed of a proton after being...Ch. 27 - Prob. 74GPCh. 27 - What is the total energy, in MeV, of a. A proton...Ch. 27 - Prob. 76GPCh. 27 - The sun radiates energy at the rate 3.8 1026 W....Ch. 27 - The radioactive element radium (Ra) decays by a...Ch. 27 - Prob. 79GPCh. 27 - Prob. 80GPCh. 27 - MCAT-Style Passage Problems Pion Therapy Subatomic...Ch. 27 - MCAT-Style Passage Problems Pion Therapy Subatomic...Ch. 27 - MCAT-Style Passage Problems Pion Therapy Subatomic...Ch. 27 - MCAT-Style Passage Problems Pion Therapy Subatomic...
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- Unreasonable Results A proton has a mass of 1.671027 kg. A physicist measures the proton's total energy to be 50.0 MeV. (a) What is the proton's kinetic energy? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forwardProtons in an accelerator at the Fermi National Laboratory near Chicago are accelerated to a total energy that is 400 times their rest energy. (a) What is the speed of these protons in terms of c? (b) What is their kinetic energy in MeV?arrow_forwardA filament running along the x axis from the origin to x = 80.0 cm carries electric charge with uniform density. At the point P with coordinates (x = 80.0 cm, y = 80.0 cm), this filament creates electric potential 100 V. Now we add another filament along the y axis, running from the origin to y = 80.0 cm, carrying the same amount of charge with the same uniform density. At the same point P, is the electric potential created by the pair of filaments (a) greater than 200 V, (b) 200 V, (c) 100 V, (d) between 0 and 200 V, or (e) 0?arrow_forward
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- Initially at rest, an electron is accelerating toward a target that is 20,000V higher potential than where the electron started. What is the speed of the electron just as it reaches the target? Note that the charge of an electron is -1.6x10-19 C and its mass is 9.1x10-31 kg.arrow_forwardAn electron is accelerating under a potential difference of 105 volts. (m,=9,108x10 31) a) What is the kinetic energy of the electron?arrow_forwardCalculate the speed of an electron (in m/s) after it accelerates from rest through a potential difference of 140 V. 7.02e25 m/s The speed of the electron v can be found using the kinetic energy equation, K = 1/2(mv^2). The change in kinetic energy is equal to the work done on the electron, K = W = -U = -qV. Using those two equations, solve for the speed v in terms of the potential V and constants. Remember that the mass of an electron is 9.1e-31 kg and its charge is 1.6e-19 C. Submit Answer Incorrect. Tries 1/2 Previous Triesarrow_forward
- Suppose an electron (q= -e= -1.6x 10-19 C.m=9.1×10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 v. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U- Assuming all potential energy U is converted to kinetic energy K. K+U=0 K--U Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: x 10' m/sarrow_forwardSuppose an electron (q = - e= - 1.6 x 10-19 C.m = 9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U= 0 K= -U 1 Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=arrow_forwardSuppose an electron (q = - e = - 1.6 x 10¬19 C,m=9.1 × 10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K + U = 0 K = -U mv and using the formula for potential energy above, we arrive at an equation for speed: 2 Since K= v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=arrow_forward
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