Chapter 27, Problem 63A

To determine

To Find: Maximum kinetic energy of photoelectrons ejected from metal.

Answer to Problem 63A

  $6.08\times {10}^{-19}\text{J}$

Explanation of Solution

Given data:

Stopping potential $V_o=3.8\text{V}$

Formula used:

Maximum kinetic energy and stopping potential are related as follows:

  $K.E_{\max }=e{V}_o$

Here, e is the charge on an electron.

Calculation:

Substitute the values and solve:

  $\begin{array}{c}K.E_{\max }=e{V}_o\\ =1.6\times {10}^{-19}\times 3.8\\ =6.08\times {10}^{-19}\text{J}\end{array}$

Conclusion:

Thus, the maximum kinetic energy of the photoelectrons is $6.08\times {10}^{-19}\text{J}$ .