Concept explainers
The measurement which remain unchanged after the amplitude of two waves are doubled.
Answer to Problem 5TP
The intensity of dark fringe.remains unchanged. Option (b) is correct.
Explanation of Solution
Introduction:
The resultant amplitude of two waves with equal amplitude is given by
The relation between intensity and amplitude is given by
The difference in intensity of consecutive bright and dark fringes is given by
The double of amplitude is given by
The maximum amplitude of interference is calculated as follows:
The maximum intensity of interference is calculated as follows:
The minimum amplitude of interference is calculated as follows:
The minimum intensity of interference is calculated as follows:
The difference in intensity of consecutive bright and dark fringes is calculated as follows:
The double of amplitude is calculated as follows:
The maximum amplitude of interference having doubled amplitude waves is calculated as follows:
The maximum intensity of interference having doubled amplitude waves is calculated as follows:
The minimum amplitude of interference having doubled amplitude waves is calculated as follows:
The minimum intensity of interference having doubled amplitude waves is calculated as follows:
The difference in intensity of consecutive bright and dark fringes having doubled amplitude waves is calculated as follows:
Conclusion:
The intensity of dark fringe remains unchanged as
The intensity of bright fringe is changed to
The difference in intensitities of consecutive bright and dark fringes is changed to
The intensity of dark fringe remains unchanged. So one potion is correct Therefore option (d) is incorrect.
Want to see more full solutions like this?
Chapter 27 Solutions
COLLEGE PHYSICS
- A beam of monochromatic green light is diffracted by a slit of width 0.550 mm. The diffraction pattern forms on a wall 2.06 m beyond the slit. The distance between the positions of zero intensity on both sides of the central bright fringe is 4.10 mm. Calculate the wavelength of the light.arrow_forwardSuppose Youngs double-slit experiment is performed in air using red light and then the apparatus is immersed in water. What happens to the interference pattern on the screen? (a) It disappears. (b) The bright and dark fringes stay in the same locations, but the contrast is reduced. (c) The bright fringes are closer together. (d) The bright fringes are farther apart. (e) No change happens in the interference pattern.arrow_forwardA monochromatic beam of light of wavelength 500 nm illuminates a double slit having a slit separation of 2.00 105 m. What is the angle of the second-order bright fringe? (a) 0.050 0 rad (b) 0.025 0 rad (c) 0.100 rad (d) 0.250 rad (e) 0.010 0 radarrow_forward
- Consider a wave passing through a single slit. What happens to the width of the central maximum of its diffraction pattern as the slit is made half as wide? (a) It becomes one-fourth as wide. (b) It becomes one-half as wide. (c) Its width does not change. (d) It becomes twice as wide. (e) It becomes four times as wide.arrow_forwardAn effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.30 m apart are powered by a single-function generator producing sine waves at 1200-Hz frequency. A student walks along a line 12.5 m away and parallel to the line between the speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is (a) the wavelength of this sound and (b) the distance between the central maximum and the first maximum (loud) position along this line?arrow_forwardConsider the single-slit diffraction pattern for =600 nm, D=0.025 mm , and x=2.0 m. Find the intensity in terms of Io at =0.5 , 1.0°, 1.5°, 3.0°, and 10.0°.arrow_forward
- A spacer is cut from a playing card of thickness 2.90 104 m and used to separate one end of two rectangular, optically flat. 3.00-cm long glass plates with n = 1.55, as in Figure P24.24. Laser light at 594 nm shine straight down on the top plate. The plates have a length of 3.00 cm. (a) Count the number of phase reversals for the interfering waves. (b) Calculate the separation between dark interference Kinds observed on the lop plate.arrow_forwardUltraviolet light of wavelength 350 nm is incident on a diffraction grating with slit spacing d and forms an interference pattern on a screen a distance L away. The angular positions bright of the interference maxima are large. The locations of the bright fringes are marked on the screen. Now red light of wavelength 700 nm is used with a diffraction grating to form another diffraction pattern on the screen. Will the bright fringes of this pattern be located at the marks on the screen if (a) the screen is moved to a distance 2L from the grating, (b) the screen is moved to a distance L/2 from the grating, (c) the grating is replaced with one of slit spacing 2d, (d) the grating is replaced with one of slit spacing d/2, or (e) nothing is changed?arrow_forwardShow that the distribution of intensity in a double-slit pattern is given by Equation 36.9. Begin by assuming that the total magnitude of the electric field at point P on the screen in Figure 36.4 is the superposition of two waves, with electric field magnitudes E1=E0sintE2=E0sin(t+) The phase angle in in E2 is due to the extra path length traveled by the lower beam in Figure 36.4. Recall from Equation 33.27 that the intensity of light is proportional to the square of the amplitude of the electric field. In addition, the apparent intensity of the pattern is the time-averaged intensity of the electromagnetic wave. You will need to evaluate the integral of the square of the sine function over one period. Refer to Figure 32.5 for an easy way to perform this evaluation. You will also need the trigonometric identity sinA+sinB=2sin(A+B2)cos(AB2)arrow_forward
- A Fraunhofer diffraction pattern is produced on a screen located 1.00 m from a single slit. If a light source of wavelength 5.00 107 m is used and the distance from the center of the central bright fringe to the first dark fringe is 5.00 103 m, what is the slit width? (a) 0.010 0 mm (b) 0.100 mm (c) 0.200 mm (d) 1.00 mm (e) 0.005 00 mmarrow_forwardThe central bright fringe in a single-slit diffraction pattern has a width that equals the distance between the screen and the slit. Find the ratio A/W of the wavelength of the light to the width W of the slit. Number i Unitsarrow_forwardIn a Young's double-slit experiment, the seventh dark fringe is located 0.029 m to the side of the central bright fringe on a flat screen, which is 1.2 m away from the slits. The separation between the slits is 1.5 x 10-4 m. What is the wavelength of the light being used? Double slit 0 Number i Seventh dark fringe Central bright fringe Seventh dark fringe Screen Unitsarrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillUniversity Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax