Physics
5th Edition
ISBN: 9781260486919
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 27, Problem 17CQ
To determine
The reason why every line in the absorption spectrum of hydrogen is present in the emission spectrum, but not every line in the emission spectrum is present in the absorption spectrum.
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Students have asked these similar questions
The wavelengths of the Lyman series for hydrogen are given by:
= RH(1-1), n = 2, 3, 4, ...
For the second of this series; calculate the energy (in eV).
Note: 1.60 x 10^-19 J = 1.0 eV
O 4.10 x 10^3 eV
2.12 x 10^3 eV
3²
O 1.21 x 10^3 eV
3.30 x 10^3 eV
The wavelengths of the Lyman series for hydrogen are given by = RH(1-2), = 2, 3, 4, ...
1/2
(a) Calculate the wavelengths of the first three lines in this series.
nm
nm
nm
(b) Identify the region of the electromagnetic spectrum in which these lines appear.
O ultraviolet region
O infrared region
O x-ray region
O visible light region
O gamma ray region
The wavelengths of the Lyman series for hydrogen are given by
1
λ
= RH
1 −
1
n2
,n = 2, 3, 4, . . .
(a) Calculate the wavelengths of the first three lines in this series.
nm
nm
nm
(b) Identify the region of the electromagnetic spectrum in which these lines appear.
infrared regionvisible light region x-ray regionultraviolet regiongamma ray region
Chapter 27 Solutions
Physics
Ch. 27.2 - Prob. 27.2CPCh. 27.3 - Prob. 27.1PPCh. 27.3 - Prob. 27.2PPCh. 27.3 - Prob. 27.3CPCh. 27.3 - Prob. 27.3PPCh. 27.4 - Prob. 27.4PPCh. 27.5 - Prob. 27.5CPCh. 27.5 - Prob. 27.5PPCh. 27.7 - Prob. 27.7CPCh. 27.7 - Prob. 27.6PP
Ch. 27.7 - Prob. 27.7PPCh. 27.7 - Prob. 27.8PPCh. 27.8 - Prob. 27.9PPCh. 27 - Prob. 1CQCh. 27 - Prob. 2CQCh. 27 - Prob. 3CQCh. 27 - Prob. 4CQCh. 27 - Prob. 5CQCh. 27 - Prob. 6CQCh. 27 - Prob. 7CQCh. 27 - Prob. 8CQCh. 27 - Prob. 9CQCh. 27 - Prob. 10CQCh. 27 - Prob. 11CQCh. 27 - Prob. 12CQCh. 27 - Prob. 13CQCh. 27 - Prob. 14CQCh. 27 - Prob. 15CQCh. 27 - Prob. 16CQCh. 27 - Prob. 17CQCh. 27 - Prob. 18CQCh. 27 - Prob. 19CQCh. 27 - Prob. 20CQCh. 27 - Prob. 21CQCh. 27 - Prob. 22CQCh. 27 - Prob. 23CQCh. 27 - Prob. 1MCQCh. 27 - Prob. 2MCQCh. 27 - Prob. 3MCQCh. 27 - Prob. 4MCQCh. 27 - Prob. 5MCQCh. 27 - Prob. 6MCQCh. 27 - Prob. 7MCQCh. 27 - Prob. 8MCQCh. 27 - Prob. 9MCQCh. 27 - Prob. 10MCQCh. 27 - Prob. 1PCh. 27 - Prob. 2PCh. 27 - Prob. 3PCh. 27 - Prob. 4PCh. 27 - Prob. 5PCh. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - Prob. 9PCh. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - Prob. 35PCh. 27 - Prob. 36PCh. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - Prob. 40PCh. 27 - Prob. 41PCh. 27 - Prob. 42PCh. 27 - Prob. 43PCh. 27 - Prob. 44PCh. 27 - Prob. 45PCh. 27 - Prob. 46PCh. 27 - Prob. 47PCh. 27 - Prob. 48PCh. 27 - Prob. 49PCh. 27 - Prob. 50PCh. 27 - Prob. 51PCh. 27 - Prob. 52PCh. 27 - Prob. 53PCh. 27 - Prob. 54PCh. 27 - Prob. 55PCh. 27 - Prob. 56PCh. 27 - Prob. 57PCh. 27 - Prob. 58PCh. 27 - Prob. 59PCh. 27 - Prob. 61PCh. 27 - Prob. 60PCh. 27 - Prob. 62PCh. 27 - Prob. 64PCh. 27 - Prob. 63PCh. 27 - Prob. 66PCh. 27 - Prob. 65PCh. 27 - Prob. 68PCh. 27 - Prob. 67PCh. 27 - Prob. 70PCh. 27 - Prob. 69PCh. 27 - Prob. 72PCh. 27 - Prob. 71PCh. 27 - Prob. 74PCh. 27 - Prob. 73PCh. 27 - Prob. 75PCh. 27 - Prob. 76PCh. 27 - Prob. 77PCh. 27 - Prob. 78PCh. 27 - Prob. 79PCh. 27 - Prob. 80PCh. 27 - Prob. 82PCh. 27 - Prob. 81PCh. 27 - Prob. 84PCh. 27 - Prob. 83PCh. 27 - Prob. 86PCh. 27 - Prob. 85PCh. 27 - Prob. 88PCh. 27 - Prob. 87PCh. 27 - Prob. 89PCh. 27 - Prob. 90PCh. 27 - Prob. 91PCh. 27 - Prob. 92PCh. 27 - Prob. 93PCh. 27 - Prob. 94PCh. 27 - Prob. 95PCh. 27 - Prob. 96P
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- If an atom has an election in the n = 5 state with m = 3, what are the possible values of l?arrow_forwardThe radial probability density of a hydrogen wavefunction in the 1s state is given by P(r) = |4rr2 (R13 (r))²| and the radial wavefunction R1s (r) = a0 , where ao is 3/2 the Bohr radius. Using the standard integral x"e - ka dx n! calculate the standard deviation in the radial position from the nucleus for the 1s state in the Hydrogen atom. Give your answer in units of the Bohr radius ao.arrow_forwardThe light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying EH=−RH/n2EH=−RH/n2 where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state. Be careful about units. The Rydberg constant in eV is 13.605693009 eV That would be multiplied by the charge on the electron 1.602× 10-19 C to give 2.18× 10-18 J A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules. The following questions are intended to help you understand the connection between…arrow_forward
- The Lyman series comprises a set of spectral lines. All of these lines involve a hydrogen atom whose electron undergoes a change in energy level, either beginning at the n = 1 level (in the case of an absorption line) or ending there (an emission line). The inverse wavelengths for the Lyman series in hydrogen are given by 1 - where n = 2, 3, 4, ... and the Rydberg constant R, = 1.097 x 10' m-. (Round your answers to at least one decimal place. Enter your answers in nm.) %3D (a) Compute the wavelength for the first line in this series (the line corresponding to n = 2). nm (b) Compute the wavelength for the second line in this series (the line corresponding to n = 3). nm (c) Compute the wavelength for the third line in this series (the line corresponding to n = 4). nm (d) In which part of the electromagnetic spectrum do these three lines reside? O x-ray region O ultraviolet region O infrared region O gamma ray region O visible light regionarrow_forwardAn energy of about 21 eV is required to excite an electron in a helium atom from the 1s state to the 2s state. The same transition for the He+ ion requires approximately twice as much energy. Explain.arrow_forwardA photon is emitted during the transition from the n = 7 state to the n = 1 state in the hydrogen atom. Note: Rydberg constant: 2.18x10-18 J Can this photon eject an electron from cesium metal (work function of Cs is 3.42x10-19 J) and why? What would be the speed of that electron once is ejected (mass electron is 9.109x10-31 kg)?arrow_forward
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