EBK PHYSICS FOR SCIENTISTS & ENGINEERS
5th Edition
ISBN: 9780134296074
Author: GIANCOLI
Publisher: VST
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 26, Problem 73GP
The internal resistance of a 1.35-V mercury cell is 0.030 Ω, whereas that of a 1.5-V dry cell is 0.35 Ω. Explain why three mercury cells can more effectively power a 2.5-W hearing aid that requires 4.0 V than can three dry cells.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Chapter 26 Solutions
EBK PHYSICS FOR SCIENTISTS & ENGINEERS
Ch. 26 - Explain why birds can sit on power lines safely,...Ch. 26 - Discuss the advantages and disadvantages of...Ch. 26 - If all you have is a 120-V line, would it be...Ch. 26 - Two lightbulbs of resistance R1 and R2 (R2 R1)...Ch. 26 - Household outlets are often double outlets. Are...Ch. 26 - With two identical lightbulbs and two identical...Ch. 26 - If two identical resistors are connected in series...Ch. 26 - You have a single 60-W bulb on in your room. How...Ch. 26 - Compare and discuss the formulas for resistors and...Ch. 26 - When applying Kirchhoffs loop rule (such as in...
Ch. 26 - For what use are batteries connected in series?...Ch. 26 - Can the terminal voltage of a battery ever exceed...Ch. 26 - Explain in detail how you could measure the...Ch. 26 - In an RC circuit, current flows from the battery...Ch. 26 - Given the circuit shown in Fig. 2634, use the...Ch. 26 - What is the main difference between an analog...Ch. 26 - What would happen if you mistakenly used an...Ch. 26 - Explain why an ideal ammeter would have zero...Ch. 26 - A voltmeter connected across a resistor always...Ch. 26 - A small battery-operated flashlight requires a...Ch. 26 - (II) A 1.5-V dry cell can be tested by connecting...Ch. 26 - (I) Three 45- lightbulbs and three 65- lightbulbs...Ch. 26 - (III) Consider the network of resistors shown in...Ch. 26 - (III) You are designing a wire resistance heater...Ch. 26 - (III) Determine the time constant for charging the...Ch. 26 - Suppose that you wish to apply a 0.25-V potential...Ch. 26 - For the circuit shown in Fig. 2618a, show that the...Ch. 26 - A Wheatstone bridge is a type of bridge circuit...Ch. 26 - The internal resistance of a 1.35-V mercury cell...Ch. 26 - A solar cell, 3.0 cm square, has an output of 350...Ch. 26 - The current through the 20- resistor in Fig. 2669...
Additional Science Textbook Solutions
Find more solutions based on key concepts
If you replot Fig. 34.7 for a material with a different work function, (1) will the slope of the line change? (...
Essential University Physics: Volume 2 (3rd Edition)
The diagrams at right show two identical gliders that move to the right without friction. The hands exert ident...
Tutorials in Introductory Physics
The Sun’s position in the Milky Way is shown in the picture above. What is the approximate distance from the Su...
Lecture- Tutorials for Introductory Astronomy
Choose the best answer to each of the following. Explain your reasoning with one or more complete sentences.
As...
Life in the Universe (4th Edition)
Three identical books of length L are stacked over the edge of a table as shown in Fig. 12.29. The top book ove...
Essential University Physics: Volume 1 (3rd Edition)
Choose the best answer to each of the following. Explain your reasoning. The asteroid belt lies between the orb...
The Cosmic Perspective Fundamentals (2nd Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Explain why R=R0(1 + a?T) for the temperature variation of the resistance R of an object is not as accurate as P=P0(1 + a?T) which gives the temperature variation of resistivity P.arrow_forwardReview. When a straight wire is warmed, its resistance is given by R = R0,[1 + a(T T0)] according to Equation 27.20, where a is the temperature coefficient of resistivity. This expression needs to be modified if we include the change in dimensions of the wire due to thermal expansion. For a copper wire of radius 0.100 0 mm and length 2.000 m, find its resistance at 100.0C, including the effects of both thermal expansion and temperature variation of resistivity. Assume the coefficients are known to four significant figures.arrow_forwardA 12.0-V emf automobile battery has a terminal voltage of 16.0 V when being charged by a current of 10.0 A. (a) What is the battery’s internal resistance? (b) What power is dissipated inside the battery? (c) At what rate (in °C/min ) will its temperature increase if its mass is 20.0 kg and it has a specific heat of 0.300 kcal/kg • °C, assuming no heat escapes?arrow_forward
- Power P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?arrow_forwardIf the terminals of a battery with zero internal resistance are connected across two identical resistors in series, the total power delivered by the battery is 8.00 W. If the same battery is connected across the same resistors in parallel, what is the total power delivered by the battery? (a) 16.0 W (b) 32.0 W (c) 2.00 W (d) 4.00 W (e) none of those answersarrow_forwardThe power dissipated in a resistor is given by P = V2/R, which means power decreases if resistance increases. Yet this power is also given by P = I2R, which means power increases if resistance increases. Explain why there is no contradiction here.arrow_forward
- A child's electronic toy is supplied by three 1.58-V alkaline cells having internal resistances of 0.0200 inseries with a 1.53-V carbon-zinc dry cell having a 0.100- internal resistance. The load resistance is 10.0 . (a) Draw a circuit diagram of the toy and itsbatteries, (b) What current flows? (c) How much power is supplied to the load? (d) What is the internal resistance of the dry cell if it goes bad, resulting in only 0.500 W being supplied to the load?arrow_forwardLightbulb A is marked 25.0 W 120. V, and lightbulb B is marked 100. W 120. V. These labels mean that each lightbulb has its respective power delivered to it when it is connected to a constant 120.-V source. (a) Find the resistance of each lightbulb. (b) During what time interval does 1.00 C pass into lightbulb A? (c) Is this charge different upon its exit versus its entry into the lightbulb? Explain. (d) In what time interval does 1.00 J pass into lightbulb A? (e) By what mechanisms does this energy enter and exit the lightbulb? Explain. (f) Find the cost of running lightbulb A continuously for 30.0 days, assuming the electric company sells its product at 0.110 per kWh.arrow_forwardWhen a straight wire is heated, its resistance changes according to the equation R = R0 [1 + (T T0)] (Eq. 17.7), where is the temperature coefficient of resistivity. (a) Show that a more precise result, which includes the length and area of a wire change when it is heated, is R=R0[1+(TT0)][1+(TT0)][1+2(TT0)] where is the coefficient of linear expansion. (See Topic 10.) (b) Compare the two results for a 2.00-m-long copper wire of radius 0.100 mm, starting at 20.0C and heated to 100.0C.arrow_forward
- Power P0 = I0 V0 is delivered to a resistor of resistance R0. If the resistance is doubled (Rnew = 2R0) while the voltage is adjusted such that the current is constant, what are the ratios (a) Pnew/P0 and (b) Vnew/V0? If, instead, the resistance is held constant while Pnew = 2P0, what are the ratios (c) Vnew/V0, and (d) Inew/I0?arrow_forwardWhen resistors with different resistances are connected in parallel, which of the following must be the same for each resistor? Choose all correct answers, (a) potential difference (b) current (c) power delivered (d) charge entering each resistor in a given time interval (e) none of those answersarrow_forwardWhen a straight wire is heated, its resistance changes according to the equation R = R0 [1 + (T T0)] (Eq. 17.7), where is the temperature coefficient of resistivity. (a) Show that a more precise result, which includes the length and area of a wire change when it is heated, is R=R0[1+(TT0)][1+(TT0)][1+2(TT0)] where is the coefficient of linear expansion. (See Topic 10.) (b) Compare the two results for a 2.00-m-long copper wire of radius 0.100 mm, starting at 20.0C and heated to 100.0C.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
How To Solve Any Resistors In Series and Parallel Combination Circuit Problems in Physics; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=eFlJy0cPbsY;License: Standard YouTube License, CC-BY