Explanation Given Info: The value of resistor 1 ( R 1 ) is 3 Ω , the value of resistor 2 ( R 2 ) is 2 Ω , the value of resistor 3 ( R 3 ) is 7 Ω , the current through resistor R 3 ( I 3 ) is 1.8 A , and the emf of the battery ( V ) is 24 V . From figure 1, Apply Kirchhoff voltage rule to loop 1, V − I 3 R 3 − I 1 R 1 = 0 Substitute 3 Ω for R 1 , 7 Ω for R 3 , 1.8 A for I 3 , and 24 V for V to find I 1 , ( 24 V ) − ( 1.8 A ) ( 7 Ω ) − I 1 ( 3 Ω ) = 0 ( 24 V ) − ( 12.6 V ) − I 1 ( 3 Ω ) = 0 ( 11.4 V ) = I 1 ( 3 Ω ) I 1 = 3

Sears And Zemansky's University Physics With Modern Physics

13th Edition

ISBN: 9780321897961

Author: YOUNG, Hugh D./

Publisher: Pearson College Div

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Question

Chapter 26, Problem 64E

To determine

The emf of the battery.

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Chapter 26, Problem 63E

Chapter 26, Problem 65E

Chapter 26 Solutions

Sears And Zemansky's University Physics With Modern Physics

Ch. 26 - Prob. 1DQ Ch. 26 - Prob. 2DQ Ch. 26 - Prob. 3DQ Ch. 26 - Prob. 4DQ Ch. 26 - Prob. 5DQ Ch. 26 - Prob. 6DQ Ch. 26 - Prob. 7DQ Ch. 26 - Prob. 8DQ Ch. 26 - Prob. 9DQ Ch. 26 - Prob. 10DQ

Ch. 26 - Prob. 11DQ Ch. 26 - Prob. 12DQ Ch. 26 - Prob. 13DQ Ch. 26 - Prob. 14DQ Ch. 26 - Prob. 15DQ Ch. 26 - Prob. 16DQ Ch. 26 - Prob. 17DQ Ch. 26 - Prob. 18DQ Ch. 26 - Prob. 19DQ Ch. 26 - Prob. 20DQ Ch. 26 - Prob. 21DQ Ch. 26 - Prob. 1E Ch. 26 - Prob. 2E Ch. 26 - Prob. 3E Ch. 26 - Prob. 4E Ch. 26 - Prob. 5E Ch. 26 - Prob. 6E Ch. 26 - Prob. 7E Ch. 26 - Prob. 8E Ch. 26 - Prob. 9E Ch. 26 - Prob. 10E Ch. 26 - Prob. 11E Ch. 26 - Prob. 12E Ch. 26 - Prob. 13E Ch. 26 - Prob. 14E Ch. 26 - Prob. 15E Ch. 26 - Prob. 16E Ch. 26 - Prob. 17E Ch. 26 - Prob. 18E Ch. 26 - Prob. 19E Ch. 26 - Prob. 20E Ch. 26 - Prob. 21E Ch. 26 - Prob. 22E Ch. 26 - Prob. 23E Ch. 26 - Prob. 24E Ch. 26 - Prob. 25E Ch. 26 - Prob. 26E Ch. 26 - Prob. 27E Ch. 26 - Prob. 28E Ch. 26 - Prob. 29E Ch. 26 - Prob. 30E Ch. 26 - Prob. 31E Ch. 26 - Prob. 32E Ch. 26 - Prob. 33E Ch. 26 - Prob. 34E Ch. 26 - Prob. 35E Ch. 26 - Prob. 36E Ch. 26 - Prob. 37E Ch. 26 - Prob. 38E Ch. 26 - Prob. 39E Ch. 26 - Prob. 40E Ch. 26 - Prob. 41E Ch. 26 - Prob. 42E Ch. 26 - Prob. 43E Ch. 26 - Prob. 44E Ch. 26 - Prob. 45E Ch. 26 - Prob. 46E Ch. 26 - Prob. 47E Ch. 26 - Prob. 48E Ch. 26 - Prob. 49E Ch. 26 - Prob. 50E Ch. 26 - Prob. 51E Ch. 26 - Prob. 52E Ch. 26 - Prob. 53E Ch. 26 - Prob. 54E Ch. 26 - Prob. 55E Ch. 26 - Prob. 56E Ch. 26 - Prob. 57E Ch. 26 - Prob. 58E Ch. 26 - Prob. 59E Ch. 26 - Prob. 60E Ch. 26 - Prob. 61E Ch. 26 - Prob. 62E Ch. 26 - Prob. 63E Ch. 26 - Prob. 64E Ch. 26 - Prob. 65E Ch. 26 - Prob. 66E Ch. 26 - Prob. 67E Ch. 26 - Prob. 68E Ch. 26 - Prob. 69E Ch. 26 - Prob. 70E Ch. 26 - Prob. 71E Ch. 26 - Prob. 72E Ch. 26 - Prob. 73E Ch. 26 - Prob. 74E Ch. 26 - Prob. 75E Ch. 26 - Prob. 76E Ch. 26 - Prob. 77E Ch. 26 - Prob. 78E Ch. 26 - Prob. 79E Ch. 26 - Prob. 80E Ch. 26 - Prob. 81E Ch. 26 - Prob. 82E Ch. 26 - Prob. 83E Ch. 26 - Prob. 84E Ch. 26 - Prob. 85E Ch. 26 - Prob. 86E Ch. 26 - Prob. 87E Ch. 26 - Prob. 88E Ch. 26 - Prob. 89E Ch. 26 - Prob. 90E Ch. 26 - Prob. 91E Ch. 26 - Prob. 92E Ch. 26 - Prob. 93E

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