For the system of capacitors shown in the figure at right, find a) the equivalent capacitance of the system, b) the potential across each capacitor, c) the charge on each capacitor, and d) the total energy stored by the group.

What total energy is stored in the capacitors in the figure below (C, = 0.343 µF, C, = 36.7 µF) if 1.80 x 104 J is stored in the 2.50 µF capacitor? (Enter your answer to at least three significant figures.) 1.861 What is the potential difference across the entire combination? What is the potential difference across the 2.50 uF capacitor compared to the potential difference across the combination? What is the potential difference across the series combination compared to the potential difference across the 2.50 µF capacitor? J 2.50 µF

A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that ℓ ≫ d. A parallel-plate capacitor is comprised of two square plates with sides of length ℓ and separation distance d. There are three dielectric materials in the space between the capacitor plates. A material with length ℓ⁄2, height d, and dielectric constant ?1 fills the left half of the space. A material with length ℓ⁄2, height d⁄2, and dielectric constant ?2 fills the top right quarter of the space. A material with length ℓ⁄2, height d⁄2, and dielectric constant ?3 fills the bottom right quarter of the space.   (a) Find an expression for the capacitance of the device in terms of the plate area A and d, ?1, ?2, and ?3. (Use the following as necessary: ?1, ?2, ?3, ?0, A and d.)C =        (b) Calculate the capacitance using the values A = 1.30 cm2, d = 2.00 mm, ?1 = 4.90, ?2 = 5.60, and ?3 = 2.50.

A 10 cm2 parallel plate capacitor has its plates separated by 5 x 10-4 m thick paper. Find the capacitance of the capacitor. (κpapel = 3,7)