Tutorials in Introductory Physics
1st Edition
ISBN: 9780130970695
Author: Peter S. Shaffer, Lillian C. McDermott
Publisher: Addison Wesley
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Textbook Question
Chapter 25.7, Problem 1aTH
Identical beams of light are incident on three different pairs of (ideal) polarizers. The double arrow drawn on each polarizer represents its direction of polarization.
- Suppose that the incident light in each case were unpolarized.
Rank the three cases (A−C) according to the intensity of the light transmitted past the second polarizer, from largest to smallest. If for any case no light is transmitted past the second polarizer, state that explicitly. Explain your reasoning.
Expert Solution & Answer
To determine
The ranking of intensity of light after passing through the second polarizer in each case.
Answer to Problem 1aTH
B<A=C
Explanation of Solution
Introduction:
The intensity of light passing through a polarizer depends directly on square of cosine of the angle. Smaller the angle between the two polarizer, greater will be the intensity of light passing through the second polarizer.
The angle between the two polariser is smallest in case A. hence the intensity of light is greatest in case A.
For case A and case C, the value of square of cosine of the angle between two polariser is same. Hence the intensity of light is same in case A and case C.
The angle between the two polariser is greatest in case B. hence the intensity of light is smallest in case B.
Conclusion:
Hence the intensity of light after passing through second polarizer is same in case A and case C and is greater than the intensity of light in case B.
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Chapter 25 Solutions
Tutorials in Introductory Physics
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