Physics Laboratory Experiments
8th Edition
ISBN: 9781285738567
Author: Jerry D. Wilson, Cecilia A. Hernández-Hall
Publisher: Cengage Learning
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Textbook Question
Chapter 25, Problem 4ASA
Are the α of a metal conductor and the β of a thermistor the same? Explain.
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A close analogy exists between the flow of energy by heat because of a temperature difference (see Section 20.7) and the
flow of electric charge because of a potential difference. In a metal, energy dQ and electrical charge dq are both
transported by free electrons. Consequently, a good electrical conductor is usually a good thermal conductor as well.
Consider a thin conducting slab of thickness dx, area A, and electrical conductivity o, with a potential difference dv
between opposite faces. (a) Show that the current I = dq/dt is given by the equation on the left:
Charge conduction Thermal conduction
dq
TA
dt
JdT|
kA
dt
dQ
| dx
|AP|
|dx
In the analogous thermal conduction equation on the right (Eq. 20.15), the rate dQ/dt of energy flow by heat (in Sl units of
joules per second) is due to a temperature gradient dT/dx in a material of thermal conductivity k. (b) State analogous rules
relating the direction of the electric current to the change in potential and relating the direction of…
A close analogy exists between the flow of energy by heat because
of a temperature difference (see Section 19.6) and the flow of
electric charge because of a potential difference. In a metal,
energy dQ and electrical charge dq are both transported by free
electrons. Consequently, a good electrical conductor is usually a
good thermal conductor as well. Consider a thin conducting slab
of thickness dx, area A, and electrical conductivity o, with a
potential difference dVbetween opposite faces. (a) Show that the
current I= dq| dt is given by the equation on the left:
Charge conduction Thermal conduction
da
= GA
dt
dQ
= kA
dx
dt
dx
In the analogous thermal conduction equation on the right (Eq.
19.17), the rate dQ/ dt of energy flow by heat (in SI units of joules
per second) is due to a temperature gradient dT/ dx in a material of
thermal conductivity k. (b) State analogous rules relating the
direction of the electric current to the change in potential and
relating the direction of energy…
In (Figure 1), let Cı = 2.90 µF, C2 = 5.40 F, and
Vab = +63.0 V.
Chapter 25 Solutions
Physics Laboratory Experiments
Ch. 25 - Prob. 1ASACh. 25 - Prob. 2ASACh. 25 - Distinguish between a positive and a negative...Ch. 25 - Are the of a metal conductor and the of a...Ch. 25 - What are the circuit conditions when a Wheatstone...Ch. 25 - Prob. 6ASACh. 25 - What is the value of for copper in terms of...Ch. 25 - Prob. 3QCh. 25 - Prob. 4QCh. 25 - Prob. 5Q
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