Concept explainers
(a)
To find: The first runner’s fastest and slowest times.
(a)
Answer to Problem 43PPS
The first runner’s fastest time is
Explanation of Solution
Given information:
The given time is
Calculation:
Calculate the time.
Let, the time for the first runner to run the race be
Thus the equation is
Hence, the required equation to find the fastest and slowest times of a runner is
Case
Case
Therefore, the first runner’s fastest time is
(b)
To find: The second runner’s fastest and slowest times.
(b)
Answer to Problem 43PPS
The second runner’s fastest time is
Explanation of Solution
Given information:
The given time is
Calculation:
Calculate the time.
Let, the time for the first runner to run the race be
Thus the equation is
Hence, the required equation to find the fastest and slowest times of a runner is
Case
Case
Therefore, the second runner’s fastest time is
(c)
To find: The team’s fastest and slowest times.
(c)
Answer to Problem 43PPS
The team’s fastest time is
Explanation of Solution
Given information:
The given runner of the fourth legs time is average of
Calculation:
Calculate the time.
Let, the time for the forth runner to run the race be
Thus the equation is
Hence, the required equation to find the fastest and slowest times of a runner is
Case
Case
Thus, the forth runner’s fastest time is
The fastest time for the team is
The slowest time for the team is
Therefore, the team’s fastest time is
Chapter 2 Solutions
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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