Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 25, Problem 42QTP
To determine
Derive an equation for optimum cutting speed in face milling using insert cutter.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
In an orthogonal cutting operation an 8 mm deep groove is to be turned on a 50 mm diameter steel bar. Spindle speed is 300 rpm and a feed rate of 0.25 mm/rev is given to the tool. Produced chips have a width of 2 mm. Calculate the material removal rate at the beginning and at the end of the cut.
Can u help me please?
In turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and depth
of cut = 2.5 mm. The tool used in this cutting is cemented carbide tool where Taylor tool life parameters are n
= 0.24 and C = 450 (tool life (min) and cutting speed (m/min). Compute the cutting speed that will allow the
tool life to be 10% longer than the machining time for this part.
In orthogonal turning of a low carbon steel bar of diameter 150 mm with uncoated carbide tool. the cutting velocity is 90 m/min The feed is 0.24 mm/rev and the depth of cut is 2 mm. The chip thickness obtained is 0.48 mm If the orthogonal rake angle is zero and the principal cutting edge angle is 90°
Calculate the shear angle in degree.
Chapter 25 Solutions
Manufacturing Engineering & Technology
Ch. 25 - Describe the distinctive features of machining...Ch. 25 - Explain how the tooling system in a machining...Ch. 25 - Explain the trends in materials used for...Ch. 25 - Is there any difference between chatter and...Ch. 25 - What are the differences between forced and...Ch. 25 - Explain the importance of foundations in...Ch. 25 - Explain why automated pallet changers and...Ch. 25 - What types of materials are machine-tool bases...Ch. 25 - What is meant by the modular construction of...Ch. 25 - What is a hexapod? What are its advantages?
Ch. 25 - What factors contribute to costs in machining...Ch. 25 - List the reasons that temperature is important in...Ch. 25 - Explain the technical and economic factors that...Ch. 25 - Spindle speeds in machining centers vary over a...Ch. 25 - Explain the importance of stiffness and damping of...Ch. 25 - Are there machining operations described in...Ch. 25 - How important is the control of cutting-fluid...Ch. 25 - Review Fig. 25.10 on modular machining centers,...Ch. 25 - Prob. 19QLPCh. 25 - Describe the adverse effects of vibration and...Ch. 25 - Describe some specific situations in which thermal...Ch. 25 - Prob. 22QLPCh. 25 - Prob. 23QLPCh. 25 - Prob. 24QLPCh. 25 - List the parameters that influence the temperature...Ch. 25 - List and explain factors that contribute to poor...Ch. 25 - Prob. 27QLPCh. 25 - Prob. 28QLPCh. 25 - Describe types and sizes of workpieces that would...Ch. 25 - Prob. 30QLPCh. 25 - Explain the advantages and disadvantages of...Ch. 25 - What are the advantages and disadvantages of (a)...Ch. 25 - What would be the advantages and limitations of...Ch. 25 - Explain how you would go about reducing each of...Ch. 25 - Describe workpieces that would not be suitable for...Ch. 25 - Give examples of forced vibration or self-excited...Ch. 25 - A machining-center spindle and tool extend 10 in....Ch. 25 - Using the data given in the example, estimate the...Ch. 25 - A machining-center spindle and tool extend 12 in....Ch. 25 - In the production of a machined valve, the labor...Ch. 25 - Estimate the optimum cutting speed in Problem...Ch. 25 - Prob. 42QTPCh. 25 - If you were the chief engineer in charge of the...Ch. 25 - Prob. 45SDPCh. 25 - Make a list of components of machine tools that...Ch. 25 - The cost of machining and turning centers is...Ch. 25 - Prob. 49SDPCh. 25 - Describe your thoughts on whether or not it is...Ch. 25 - Prob. 51SDPCh. 25 - Prob. 53SDP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Determine the total machining time for a workpiece 30mm in diameter and the required length is 145 mm. Other data: Material: 38mm dia. X 149 mm Depth of cut (turning): 4mm Depth of cut (facing): 2mm Feed : 0.05 mm/rev : 35 SMPM Cutting speedarrow_forwardIn face milling, assume that the Diameter of the cutter is 200 mm, the width of the block is 60 mm, and the length of the block is 344 mm, if the depth of cut is 3 mm, = 0.6 mm/min, and N = 100 rpm. The cutter has 12 inserts, and the workpiece material is bronze. Calculate the estimated power required, the cutting force, and the torque.arrow_forwardAn external turning operation is performed on a hollow workpiece of 200 mm external diameter and 100 mm inner diameter, at 40 m/min cutting speed, 2 mm depth of cut and 0.20 mm/rev feed. Calculate: The rotational speed for this workpiece. The machining time needed for a length of 250 mm. The material removal rate used. The parting-off time needed if the cross feed is 0.1 mm/rev. The expected tool life if the constants in Taylor Formula are n=0.23 and C= 240. The maximum number of work pieces that could be produced under the given cutting conditions, before the tool needs re-sharpening.arrow_forward
- The end of a large tubular workpart is to be faced on a NC vertical boring mill. The part has an outside diameter of 38.0 in and an inside diameter of 24.0 in. If the facing operation is performed at a rotational speed of 40.0 rev/min, feed of 0.015 in/rev, and depth of cut of 0.180 in, determine (a) the cutting time to complete the facing operation and the cutting speeds and metal removal rates at the beginning and end of the cut.arrow_forwardConsider a profile milling operation, where the initial (stock) geometry has (X,Y,Z) dimensions of 100 mm x 75 mm x 50 mm. The target part has dimensions of 95 mm x 70 mm x 50 mm. The target part is located in the centre of the stock part, i.e. the stock to be removed from all sides is equal. The operation has a cutting time of 1 minute. The tool axis is along the Z direction and the tool diameter is 12 mm having 6 cutting edges. The takes place at 54m/min feed rate of 0.2 mm/rev/tooth. Calculate the axial depth of cut ? process at aarrow_forwardIn 3-axis milling, the table feedrate is 703.00 mm/min. Using a 10mm endmill to cut the material with a radial depth of 4.60 mm and axial depth of 4.20 mm, what is the material removal rate (Cm³ /min) in this operation? Your Answer: Answerarrow_forward
- 3. A slot of 20 mm width is to be produced using horizontal milling machine. The ks 5,000 N/mm?, cutting speed is 50 m/min, feed rate is 200 mm/min, depth of cut is 4 mm, cutter diameter is 140 mm, and the number of teeth is 12. Calculate the machining power.arrow_forwardAssume that, in orthogonal cutting, the rake angle is 20 and the friction angle is 35 at thechip-tool interface. Determine the percentage change in chip thickness when the frictionangle is 50. Note that Merchant’s equation is more preferable.arrow_forwardFeed rate in slab milling operation is equal to (a) rotation per minute (rpm) (b) product of rpm and number of teeth in the cutter (c) product of rpm, feed per tooth and number of teeth in the cutter (d) product of rpm, feed per tooth and number of teeth in contactarrow_forward
- 1. In a production turning operation, the cylindrical workpiece is 425 mm long and 190 mm in diameter, Feed 0.30 mm/rev. What cutting speed must be used to achieve a machining time of 7.0 min?arrow_forwardA surface of 43 mm x 246 mm will be machined by using a shaper and 7 mm deep stock will be removed from the surface. The shaper is operating at 24 strokes/minute and feed is 0.7 mm/stroke. If the maximum stroke length is 827 mm and allowable depth of cut is 0.4 mm for both of rough and finish cuts, what is the total machining time, in minutes ?arrow_forwardQ3). A block of 190mm length and 100mm width is to be machined in shaping process. The permissible cutting speed is 30m/min. maximum quick return ratio is 3:2 at the design value of stroke of 400mm. Calculate the time of machining of the block, assuming total depth of cut to be 8mm, L=1₂+1+1, 40+190+20=250mm, B=ba+b+bo=10+100+10=120mm?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Types of Manufacturing Process | Manufacturing Processes; Author: Magic Marks;https://www.youtube.com/watch?v=koULXptaBTs;License: Standard Youtube License