Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 25, Problem 101P
To determine
Proof of equation 25-40
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Don't use chat gpt It Chatgpt means downvote
need help solving for C
A constant electric field accelerates a proton from rest through a distance of 1.55 m to a speed of 1.97 ✕ 105 m/s. (The mass and charge of a proton are
mp = 1.67 ✕ 10−27 kg
and
qp = e = 1.60 ✕ 10−19 C.)
HINT
(a)
Find the change in the proton's kinetic energy (in J).
3.24E-17 J
(b)
Find the change in the system's electric potential energy (in J).
The work done by the electric force and the change in electric potential energy are related by
WFe = −ΔPE.
This relationship holds for any conservative force: the work done by any conservative force equals the negative of the change in the associated potential energy. -3.24E-17J
(c)
Calculate the magnitude of the electric field (in N/C).
N/C
The inhomogeneous Maxwell equations are given as follows:
18
c² Ət
V.E=
(b)
P
Eo
VxB
-
Use inhomogeneous Maxwell equations to derive the two equations of motion for the
potentials
(a)
-0$
10
-DA+VV.A+ Φ = HoJ,
c² Ət
Ε= μου.
P
- (v. A+ 100) - ².
ә
Ət
=
t
Hint: Vx (V xA) = V(VA) - V²A and =V²-
-
Chapter 25 Solutions
Physics for Scientists and Engineers
Ch. 25 - Prob. 1PCh. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - Prob. 4PCh. 25 - Prob. 5PCh. 25 - Prob. 6PCh. 25 - Prob. 7PCh. 25 - Prob. 8PCh. 25 - Prob. 9PCh. 25 - Prob. 10P
Ch. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Prob. 16PCh. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Prob. 19PCh. 25 - Prob. 20PCh. 25 - Prob. 21PCh. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Prob. 24PCh. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - Prob. 33PCh. 25 - Prob. 34PCh. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - Prob. 48PCh. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53PCh. 25 - Prob. 54PCh. 25 - Prob. 55PCh. 25 - Prob. 56PCh. 25 - Prob. 57PCh. 25 - Prob. 58PCh. 25 - Prob. 59PCh. 25 - Prob. 60PCh. 25 - Prob. 61PCh. 25 - Prob. 62PCh. 25 - Prob. 63PCh. 25 - Prob. 64PCh. 25 - Prob. 65PCh. 25 - Prob. 66PCh. 25 - Prob. 67PCh. 25 - Prob. 68PCh. 25 - Prob. 69PCh. 25 - Prob. 70PCh. 25 - Prob. 71PCh. 25 - Prob. 72PCh. 25 - Prob. 73PCh. 25 - Prob. 74PCh. 25 - Prob. 75PCh. 25 - Prob. 76PCh. 25 - Prob. 77PCh. 25 - Prob. 78PCh. 25 - Prob. 79PCh. 25 - Prob. 80PCh. 25 - Prob. 81PCh. 25 - Prob. 82PCh. 25 - Prob. 83PCh. 25 - Prob. 84PCh. 25 - Prob. 85PCh. 25 - Prob. 86PCh. 25 - Prob. 87PCh. 25 - Prob. 88PCh. 25 - Prob. 89PCh. 25 - Prob. 90PCh. 25 - Prob. 91PCh. 25 - Prob. 92PCh. 25 - Prob. 93PCh. 25 - Prob. 94PCh. 25 - Prob. 95PCh. 25 - Prob. 96PCh. 25 - Prob. 97PCh. 25 - Prob. 98PCh. 25 - Prob. 99PCh. 25 - Prob. 100PCh. 25 - Prob. 101PCh. 25 - Prob. 102PCh. 25 - Prob. 103PCh. 25 - Prob. 104PCh. 25 - Prob. 105PCh. 25 - Prob. 106PCh. 25 - Prob. 107PCh. 25 - Prob. 108PCh. 25 - Prob. 109PCh. 25 - Prob. 110PCh. 25 - Prob. 111PCh. 25 - Prob. 112PCh. 25 - Prob. 113PCh. 25 - Prob. 114PCh. 25 - Prob. 115PCh. 25 - Prob. 116PCh. 25 - Prob. 117PCh. 25 - Prob. 118PCh. 25 - Prob. 119PCh. 25 - Prob. 120P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The cntial सन्ये the Sufunaf ow to Kis cartat at raclvus R is knowh Spherica! shll VCR,O)= Kcos (20) be What is पञ्जको the potential nsid Sphe- k and outs de of thearrow_forwardAnswers: a) 3.3 C c/m² 6. Two electrons are fixed 2.00 cm apart. Another electron is shot from infinity and comes to rest midway between the two. What was its initial speed? Answer: 318 m/sarrow_forwardThis is a closed path why will SÈ•¿2 always egual Zero, regardless of the path's shape and whee on the path chages lie? 1.arrow_forward
- In nuclear fission, a nucleus splits roughly in half. A. What is the potential 4.00 x 10-14 m from a fragment that has 50 protons in it? (p=+1.602x10-19 C) →Why 1.8 MV is the answer for this problem?arrow_forward20 sin 0 If V : - V in free space, find: (a) py at P(r = 2,0 = 30°, Ø = 0);arrow_forward(8%) Problem 1: A particle moves from point A to point B. Let L be the straight-line distance between A and B, let R be the magnitude of the particle's displacement, and let S be the distance the particle traveled. A 33% Part (a) Which is always true? ▷ A 33% Part (b) Which is only sometimes true? oo L = R O R=S R>S Grade S Deductic Potentialarrow_forward
- Consider that a particular physical phenomenon can be modeled, in steric coordinates, by the scalar potential 0, q1 = r, q2 = 0, 93=0, find V, r(r, 0, 0) = r cos tan 0. If ê₁ = f, ê₂ = 4, 3 = knowing that, in generalized coordinates, V4(91, 92, 93) = 3 i=1 1 მს hi dqiarrow_forwardTwo electrons are 1 meter apart from each other. A third electron comes from infinity with an initial velocity Vo approaching the two electrons and it turns out that it passes a point which is 40 cm from one of the electrons and 60 cm from the other electron at half the speed of the original. Determine the initial velocity Voarrow_forwardIf a proton and electron are released when they are 2.0 m apart, find the initial acceleration of electron (in m/s2) The answer (in fundamental SI unit) isarrow_forward
- Consider a circular region of radius R = 6.00 cm in which there is an electric flux directed out of the page. (Outside of this region there is no flux.) The flux in this region varies with both time and location. Specifically, for rsR, the flux encircled by a concentric circle of radius r is given by PE enc = (0.600 V m/s)(r/R)t, where t is the time in seconds. a) Find the magnitude of the induced magnetic field at a radial distance of r = 2.00 cm from the center of the region. B(r = 2.00 cm) = T Help Enter b) Find the magnitude of the induced magnetic field at a radial distance of r = 10.00 cm from the center of the region. B(r = 10.00 cm) - T Help Enterarrow_forwardIn C how does 1/C = 1/4 + 1/8 turn into 1/C = 3/8?arrow_forwardSuppose an electron (q = -e = -1.6 x 10¬9 C,m=9.1 x 10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for %3D the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U = 0 K = -U 1 Since K mv and using the formula for potential energy above, we arrive at an equation for speed: 2 v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage LearningUniversity Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
- University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax