Tutorials in Introductory Physics
1st Edition
ISBN: 9780130970695
Author: Peter S. Shaffer, Lillian C. McDermott
Publisher: Addison Wesley
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Textbook Question
Chapter 24.5, Problem 1aTH
Suppose that the bulb is placed as shown. Using all three principal rays, draw an accurate ray diagram to determine the location of the image. Label the image location.
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Construct ray diagram and show where the image of the object given below are located. Draw in the complete image and describe its characteristics (real or virtual, enlarged or diminished, inverted or upright).
Draw a ray diagram for each of the following, and then draw the image formed. Please add complete details and labels. Include size of image, location, orientation, and type of image.
Describe the difference between a real image and a virtual image?
Can your eyes tell the difference?
How can you tell the difference on a ray diagram?
How could you tell the difference between a virtual image and a real image experimentally?
Chapter 24 Solutions
Tutorials in Introductory Physics
Ch. 24.1 - On the diagram, sketch what you would see on the...Ch. 24.1 - The small bulb is replaced by three longfilament...Ch. 24.1 - The three longfilament bulbs are replaced by a...Ch. 24.1 - Predict the size and shape of the shadow that will...Ch. 24.1 - Is it possible to place the bulb in another...Ch. 24.1 - Prob. 2cTHCh. 24.1 - Prob. 2dTHCh. 24.1 - Prob. 3aTHCh. 24.1 - A student is looking at the building shown at...Ch. 24.1 - Prob. 4aTH
Ch. 24.1 - Suppose that this student were walking through the...Ch. 24.2 - The top view diagrams at right were drawn by a...Ch. 24.2 - Draw a ray diagram to determine the location of...Ch. 24.2 - Describe how you could use a ray diagram to...Ch. 24.2 - A pencil is placed in front of a plane mirror as...Ch. 24.2 - Prob. 3bTHCh. 24.3 - Prob. 1aTHCh. 24.3 - A pin is placed in front of a semicylindrical...Ch. 24.3 - Prob. 1cTHCh. 24.3 - Prob. 2aTHCh. 24.3 - A very small, very bright bulb is placed for from...Ch. 24.4 - The following are top view diagrams of solid...Ch. 24.4 - The following are top view diagrams of solid...Ch. 24.4 - The following are top view diagrams of solid...Ch. 24.4 - The following are top view diagrams of solid...Ch. 24.4 - Prob. 2THCh. 24.4 - Prob. 3aTHCh. 24.4 - Prob. 3bTHCh. 24.4 - Is the image(s) of the nail real or virtual?...Ch. 24.5 - Suppose that the bulb is placed as shown. Using...Ch. 24.5 - Prob. 1bTHCh. 24.5 - Prob. 1cTHCh. 24.5 - Prob. 1dTHCh. 24.5 - Prob. 2aTHCh. 24.5 - Treat the image produced by lens 1 as an object...Ch. 24.5 - Repeat parts a andb for the case in which lens 2...Ch. 24.6 - Reproduced below is a side view diagram of the...Ch. 24.6 - In section III of the tutorial Magnification, you...Ch. 24.6 - Two thin convex lenses and an object are arranged...Ch. 24.6 - Prob. 3bTHCh. 24.6 - Two thin convex lenses and an object are arranged...Ch. 24.6 - Prob. 3dTHCh. 24.6 - Two thin convex lenses and an object are arranged...
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- Using a ruler or any straight edge and a scale of your choice and applying the steps in ray diagramming, complete the ray diagramming for Cases 2 to 5 in order to prove the correctness of the image characteristics of the objects in the specified positions as indicated in Table 1.arrow_forwardHi! This is about Ray Diagram. Got confused on answering this one, your help guys would be appreciated. Thank you so much! Instructions: For each case below draw a ray diagram. Draw the image as an arrow and give a description of the image.arrow_forwardConstruct ray diagrams to show where the images of the following objects are located. Dray in the complete image and describe its characteristics (real or virtual, enlarged or reduced in size, inverted or upright). (NOTE: review the ray diagrams for all possible objects locations for each device.)arrow_forward
- The Block shown is 40cm thick. (d) The block is shown below. A 25° line is displayed by a diagonal dashed line. The incident light is directed at the block along the 25° line. The light enters the front surface and exits the second side back into air some time later. i. Print or redraw the diagram below, sketch the light path as the ray enters and passes through to the air on the backside of the block. Please use a ruler or make relatively straight lines. ii. When the light exits the block back into the air, will the ray travel parallel to the 25° line or at an angle to it? Determine the angle between the exiting ray and the 25° line or the distance between the two lines if they are parallel. iii.arrow_forwardPlease refer to part (c) of Figure 1 included with this question. Here, the triangle is isosceles, and alpha (the angle at the top of the triangular prism) is 36.9 degrees. What is theta (the angle below the horizontal that the ray makes emerging from the prism on the right)? A. 7.5 degrees B. 9.4 degrees C. 2.8 degrees D. 13.2 degreesarrow_forwardThe diagram at the right shows a ray of light traveling through air towards a thin layer of linseed oil (n = 1.50) resting on top of water (n=1.33). The light ray approaches the linseed oil at an angle of incidence of 48.2°.a. Determine the angle of refraction at the air-linseed oil boundary.b. Determine the angle of refraction at the linseed oil-water boundary.arrow_forward
- Radius of curvature of a converging lens is 80 cm. If an object of height 10 cm is placed at a distance of 20 cm from lens on the principal axis, find : a. image distance b. image height c. Draw ray diagramarrow_forwardSolve with illustration. Locate the image by tracing it through ray diagramming and answer three questions for the possible positions: a. Is the image erect or inverted b. Is the image real or virtual? c. Is it enlarged, diminished, or the same size?arrow_forwardFigure 1 shows a curved surface separating a material with index of refraction n1 from a material with index n2. The surface forms an image I and object O? The center of curvature is point c For the ray that passes through the surface along a radial line, its angles of incidence and refraction are both zero, so its direction does not change at the surface. For the ray AB the direction changes according to Snell's law. Question Show that for small angle θ1 and θ2, the Snell's law can be written as n1 tan θ1 = n2 tan θ2arrow_forward
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