Explanation Given information: The limit lim x → − 2 ( 2 − | x | 2 + x ) Concept used: The limit lim x → a ( f ( x ) ) exists if lim x → a − ( f ( x ) ) = lim x → a + ( f ( x ) ) Calculation: Consider the limit lim x → − 2 − ( 2 − | x | 2 + x ) lim x → − 2 − ( 2 − | x | 2 + x ) = 2 − ( − x ) 2 + x lim x → − 2 − ( 2 − | x | 2 + x ) = 2 + x 2 + x lim x → − 2 − ( 2 − | x | 2 + x ) = 1 since | x | = − x if

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

1st Edition

ISBN: 9781305779037

Author: James Stewart, Troy Day

Publisher: Cengage Learning

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Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Chapter 2.4, Problem 36E

To determine

The limit if exists

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Chapter 2.4, Problem 35E

Chapter 2.4, Problem 37E

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Chapter 2 Solutions

Bundle: Biocalculus: Calculus, Probability, And Statistics For The Life Sciences + Webassign Printed Access Card For Stewart/day's Biocalculus: Calculus For Life Sciences, 1st Edition, Multi-term

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

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The limit if exists

Solution Summary: The author explains that the limit exists if undersetxto amathrmlim(f(x))=1.

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The limit if exists

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Chapter 2 Solutions