In Exercises 23–26, use the fact that the following two matrices are inverses of each other to solve the system of linear equations. [ 9 0 2 0 − 20 − 9 − 5 5 4 0 1 0 − 4 − 2 − 1 1 ] and [ 1 0 − 2 0 0 1 0 − 5 − 4 0 9 0 0 2 1 − 9 ] { x − 2 z = − 1 y − 5 w = 0 − 4 x + 9 z = 0 2 y + z − 9 w = 1
In Exercises 23–26, use the fact that the following two matrices are inverses of each other to solve the system of linear equations. [ 9 0 2 0 − 20 − 9 − 5 5 4 0 1 0 − 4 − 2 − 1 1 ] and [ 1 0 − 2 0 0 1 0 − 5 − 4 0 9 0 0 2 1 − 9 ] { x − 2 z = − 1 y − 5 w = 0 − 4 x + 9 z = 0 2 y + z − 9 w = 1
Solution Summary: The author calculates the solution to the system of linear equations with the use of x=-9,y=25,z=-4,w=5
In Exercises 19–20, solve the matrix equation for X.
1
-1
1
-1
5
7
8.
19. 2
3
0| X =
4
-3
1
1
3
5
-7
2
1
-
Solve the matrix equation for X:
1 -1 2
0 1|
– 15 -3
|
8 -5 11
i
i
X =
2. Assume that all the operations are properly defined, solve the following equation for
the unknown matrix X:
((A+X)" – 1) = B
Use the result to evaluate X using the matrices A
and
6
-2
B =
Chapter 2 Solutions
Finite Mathematics & Its Applications (12th Edition)
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