Concept explainers
The missing values in the table.
Answer to Problem 1PP
ET = 120 V | ER = 72 V | EL = 200 V | EC = 104 V |
IT = 2 A | IR = 2 A | IL = 2 A | IC = 2 A |
Z = 60 Ω | R = 36 Ω | XL = 100 Ω | XC = 52 Ω |
VA = 240 | P = 144 W | VARSL = 400 | VARSC = 208 |
PF = 60 % | ∠θ = 53.13 ° | L = 0.2652 H | C = 51.01µF |
Explanation of Solution
Given data :
The value of the inductor is given by,
The value of the capacitor is given by,
The impedance of the series RLC circuit is calculated as,
The total current flowing through series RLC circuit will be,
Since the circuit is series R-L-C,
The total voltage drop across the resistor,
The total voltage drop across the inductor,
The total voltage drop across the capacitor,
The apparent power VA is given as,
The true power P is given as,
The reactive power VARSL is calculated as,
The reactive power VARSC is calculated as,
Power factor (PF) is calculated as,
Power factor angle θ will be,
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Chapter 24 Solutions
Delmar's Standard Textbook of Electricity (MindTap Course List)
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