Chapter 23, Problem 23.14P

(a)

Interpretation Introduction

Interpretation:

The distribution coefficient $\left(\text{D}\right)$ for extraction of $\text{0}\text{.1}\text{µm}{\text{Cu}}^{\text{2+}}$ into ${\text{CCl}}_{\text{4}}$ has to be calculated.

Concept introduction:

Distribution of metal-chelate complex:

Distribution of metal-chelate complex between phases is given by

$\begin{array}{l}\text{D}\approx \frac{{\text{K}}_{\text{M}}{\text{βK}}_{\text{a}}^{\text{n}}}{{\text{K}}_{\text{L}}^{\text{n}}}\frac{{\left[\text{HL}\right]}_{\text{org}}^{\text{n}}}{{\left[{\text{H}}^{\text{+}}\right]}_{\text{aq}}^{\text{n}}}\\ \text{where,}\\ \text{D}\text{-}\text{distribution}\text{coefficient}\\ {\text{K}}_{\text{M}}\text{-}\text{partition}\text{coefficient}\text{for}\text{metal}\\ {\text{K}}_{\text{L}}\text{-}\text{partition}\text{coefficient}\text{for}\text{ligand}\\ \text{β}\text{-}\text{formation}\text{constant}\\ {\text{K}}_{\text{a}}\text{-}\text{acid}\text{dissociation}\text{constant}\end{array}$

(b)

Interpretation Introduction

Interpretation:

The remaining fraction of ${\text{Cu}}^{\text{2+}}$ in the aqueous phase has to be calculated.