The peak magnitude of electric field.
Answer to Problem 3P
The answer is 5.25 N/C
Explanation of Solution
Given info:
Magnetic field, B=17.5 nT=17.5 ×10−9 T
Factor, c=3×108 m/s
Formula used:
In anelectromagneticwave,
E=cB
Where,
B is magnetic field
E magnitude of electric field
c is a factor
Calculation:
In an electromagnetic wave, magnitude of electric field is always c times that of mangnetic field.
Substitute given and known values in formula, E=cB
E=(3×108 m/s)(17.5×10−9 T)=5.25 N/C
Conclusion: The peak magnitude is 5.25 N/C .
Chapter 22 Solutions
Physics: Principles with Applications
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