(a)
The average power incident on the telescope due to a wave at normal incidence with intensity
(a)
Answer to Problem 37P
The average power incident on the telescope due to a wave at normal incidence with intensity
Explanation of Solution
Given that the diameter of the telescope is
Write the expression for the average power incident on a surface of area
Here,
Write the expression for the area of the circular surface.
Here,
Use equation (II) in equation (I),
Conclusion:
Substitute
Therefore, the average power incident on the telescope due to a wave at normal incidence with intensity
(b)
Average power incident on Earth’s surface.
(b)
Answer to Problem 37P
Average power incident on Earth’s surface is
Explanation of Solution
The diameter of the Earth is
The average power incident on the Earth’s surface can be found out by equation (III),
Conclusion:
Substitute
Therefore, the average power incident on Earth’s surface is
(c)
The rms electric and magnetic fields.
(c)
Answer to Problem 37P
The rms electric and magnetic fields are
Explanation of Solution
Write the expression for the energy density.
Here,
Write the expression for the energy density in terms of intensity.
Here,
Use equation (V) in equation (IV),and solve for
Write the relation connecting rms electric field and rms magnetic field.
Here,
Solve equation (VII) for
Conclusion:
Substitute
Substitute
Therefore, the rms electric and magnetic fields are
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