EBK PRACTICE OF STATISTICS IN THE LIFE
EBK PRACTICE OF STATISTICS IN THE LIFE
4th Edition
ISBN: 9781319067496
Author: BALDI
Publisher: VST
Question
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Chapter 22, Problem 22.4AYK

(a)

To determine

To find:

Thepercent of aphids land upright dropping from 3cm,5cm,10cm,20cm of the given table.

(a)

Expert Solution
Check Mark

Answer to Problem 22.4AYK

  66.667%

Explanation of Solution

Given:

    Landing posture3cm5cm10cm20cm
    Upright 20232729
    No upright10731
    Sample size30303030

Concept used:

Formula

  p=xn

Significance level

  α=1confidenceα=10.95

Calculation:

Parameter p= sample proportion

The best point of estimate of p is sample proportion

Since the sample size are large.

The condition for the two samples z test are met.

The population distribution is normal.

Sample size n=30

For aphids land upright when dropping from 3cm

The percentage

  =noofaphidslanduprightn×100=2030×100=66.667%

For aphids land upright when dropping from 5cm

The percentage

  =noofaphidslanduprightn×100=2330×100=76.667%

For aphids land upright when dropping from 10cm

The percentage

  =noofaphidslanduprightn×100=2930×100=90%

For aphids land upright when dropping from 20cm

The percentage

  =noofaphidslanduprightn×100=2930×100=96.667%

(b)

To determine

To explain:

The 95% confident are not capture the respective population proportion of the given table.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given:

    Landing posture3cm5cm10cm20cm
    Upright 20232729
    No upright10731
    Sample size30303030

Concept used:

Formula

  p=xn

Significance level

  α=1confidenceα=10.95

Calculation:

Parameter p= sample proportion

The best point of estimate of p is sample proportion

Since the sample size are large.

The condition for the two samples z test are met.

The population distribution is normal.

Sample size n=30

For aphids land upright when dropping from 3cm

The percentage

  =noofaphidslanduprightn×100=2030×100=66.667%

For aphids land upright when dropping from 5cm

The percentage

  =noofaphidslanduprightn×100=2330×100=76.667%

For aphids land upright when dropping from 10cm

The percentage

  =noofaphidslanduprightn×100=2930×100=90%

For aphids land upright when dropping from 20cm

The percentage

  =noofaphidslanduprightn×100=2930×100=96.667%

For aphids land upright dropping from 20cm is the percent of 96.667% .

This percent is large of the 95% confident.

So,the 95% confident are not capture the respective population proportion of all four intervals.

(c)

To determine

To explain:

The 95% confident are not capture the respective population proportion of the given table.

(c)

Expert Solution
Check Mark

Explanation of Solution

Given:

    Landing posture3cm5cm10cm20cm
    Upright 20232729
    No upright10731
    Sample size30303030

Concept used:

Formula

  p=xn

Significance level

  α=1confidenceα=10.95

Calculation:

Parameter p= sample proportion

The best point of estimate of p is sample proportion

Since the sample size are large.

The condition for the two samples z test are met.

The population distribution is normal.

Sample size n=30

For aphids land upright when dropping from 3cm

The percentage

  =noofaphidslanduprightn×100=2030×100=66.667%

For aphids land upright when dropping from 5cm

The percentage

  =noofaphidslanduprightn×100=2330×100=76.667%

For aphids land upright when dropping from 10cm

The percentage

  =noofaphidslanduprightn×100=2930×100=90%

For aphids land upright when dropping from 20cm

The percentage

  =noofaphidslanduprightn×100=2930×100=96.667%

Null hypothesis H0 :-No relationship between aphids land upright and landing posture.

Alternative hypothesis H1 :-A significant relationship between aphids land upright and landing posture.

Significance level

  α=1confidenceα=10.95α=0.05

Since p Value is greater than 0.05 significance level.

So the hypothesis is fail to reject null hypothesis H0

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