Concept explainers
For Exercises
You estimate that a box can hold 1152 in
The box is actually 10.5 in. long, 10.5 in. wide, and 8 in. tall. What is the percent error in your estimation? Round to the nearest percent.
A.
B.
C.
D.
To find : the percent error in the estimation.
A. 23% B. 31% C. 42% D. 77%
Answer to Problem 5STP
B 31%
Explanation of Solution
Given information: It is estimated that a box can hold 1152in3. The box is actually 10.5 in. long, 10.5 in. wide and 8 in. tall.
Calculation:
The box is actually 10.5 in. long, 10.5 in. wide and 8 in. tall.
Therefore, actual volume of box is
Estimated volume of the box is 1152 in3.
Now, percentage error in estimation IS
Thus, percent error in estimation is 31%.
Chapter 2 Solutions
High School Math 2012 Common-core Algebra 1 Practice And Problem Solvingworkbook Grade 8/9
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