To find: the height of rock when x=1 seconds, x=1.1 seconds, x=1.2 seconds, x=1.3 seconds.
a)
Expert Solution
Answer to Problem 95AYU
The height of rock when x=1 seconds, x=1.1 seconds, x=1.2 seconds, x=1.3 seconds are 15.1 meters, 14.01 meters, 12.944 meters, and 11.719 meters respectively.
Explanation of Solution
Given information:
Rock falls from a height of 20 meter on Earth.
The height H meter after x seconds is approximated by
H(x)=20−4.9x2
Calculation:
Consider the given function.
H(x)=20−4.9x2
For x=1 seconds the height can be calculated as shown:
H(x)=20−4.9x2H(1)=20−4.9(1)2=20−4.9=15.1meters
For x=1.1 seconds the height can be calculated as shown:
H(x)=20−4.9x2H(1.1)=20−4.9(1.1)2=14.01meters
For x=1.2 seconds the height can be calculated as shown:
H(x)=20−4.9x2H(1.2)=20−4.9(1.2)2=12.944meters
For x=1.3 seconds the height can be calculated as shown:
H(x)=20−4.9x2H(1.3)=20−4.9(1.3)2=11.719meters
b)
To determine
To find: the time when height of rock is H=15meters , H=10meters , and H=5meters .
b)
Expert Solution
Answer to Problem 95AYU
The time when height of rock is H=15meters , H=10meters , and H=5meters are 1.01 seconds, 1.43 seconds, and 1.75 seconds respectively.
Explanation of Solution
Given information:
Rock falls from a height of 20 meter on Earth.
The height H meter after x seconds is approximated by
H(x)=20−4.9x2
Calculation:
Consider the given function.
H(x)=20−4.9x2
For H=15 metersthe time can be calculated as shown:
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