Explanation Given information: x 0 = 0.4 , c = 3.5 Calculation: Given difference equation x t + 1 = c x t ( 1 − x t ) Where x 0 = 0.4 , c = 3.5 . Let us calculate some terms of the sequence. x 0 = 0.4 x 1 = ( 3.5 ) ⋅ x 0 ( 1 − x 0 ) = ( 3.5 ) ⋅ ( 0.4 ) ( 1 − 0.4 ) = 0.8400 x 2 = ( 3.5 ) ⋅ x 1 ( 1 − x 1 ) = ( 3.5 ) ⋅ ( 0.8400 ) ( 1 − 0.8400 ) = 0.4704 x 3 = ( 3.5 ) ⋅ x 2 ( 1 − x 2 ) = ( 3.5 ) ⋅ ( 0.4704 ) ( 1 − 0.4704 ) ≈ 0.8719 x 4 = ( 3.5 ) ⋅ x 3 ( 1 − x 3 ) ≈ ( 3.5 ) ⋅ ( 0.8719 ) ( 1 − 0.8719 ) ≈ 0.3908 x 5 = ( 3.5 ) ⋅ x 4 ( 1 − x 4 ) ≈ ( 3.5 ) ⋅ ( 0

15th Edition

ISBN: 9781133109631

Author: Stewart, JAMES, Day, Troy

Publisher: Cengage Learning,

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Chapter 2.1, Problem 50E

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Chapter 2.1, Problem 49E

Chapter 2.1, Problem 51E

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Chapter 2 Solutions

Biocalculus

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.1 - Prob. 53E Ch. 2.1 - Prob. 54E Ch. 2.1 - Prob. 55E Ch. 2.1 - Prob. 56E Ch. 2.1 - Prob. 57E Ch. 2.1 - Prob. 58E Ch. 2.1 - Prob. 59E Ch. 2.1 - Prob. 60E Ch. 2.1 - 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Prob. 9CS

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To plot: x t + 1 = c x t ( 1 − x t ) and calculate its exact value.

Solution Summary: The author explains that the sequence is oscillatory and does not appear to be convergent.

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To plot: xt+1=cxt(1−xt) and calculate its exact value.

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Chapter 2 Solutions