Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
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Chapter 21, Problem 4CQ
To determine
The evidence that supports the theory that eukaryotic cells developed after the formation of the symbiotic relationship between primitive prokaryotic cells.
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Chapter 21 Solutions
Integrated Science
Ch. 21.1 - Prob. 1SCCh. 21.3 - Prob. 2SCCh. 21.3 - Prob. 3SCCh. 21.3 - Prob. 4SCCh. 21.3 - Prob. 5SCCh. 21.8 - Prob. 6SCCh. 21.8 - Prob. 7SCCh. 21.9 - Prob. 8SCCh. 21.9 - Prob. 9SCCh. 21.10 - Prob. 10SC
Ch. 21.11 - Prob. 11SCCh. 21.11 - Prob. 12SCCh. 21.12 - Prob. 13SCCh. 21.12 - Prob. 14SCCh. 21.12 - Prob. 15SCCh. 21 - Prob. 1CQCh. 21 - Prob. 2CQCh. 21 - Prob. 3CQCh. 21 - Prob. 4CQCh. 21 - Prob. 5CQCh. 21 - Prob. 6CQCh. 21 - Prob. 7CQCh. 21 - Prob. 8CQCh. 21 - Prob. 9CQCh. 21 - Why has Lamarcks theory been rejected?Ch. 21 - Prob. 11CQCh. 21 - Prob. 12CQCh. 21 - Prob. 13CQCh. 21 - Prob. 14CQCh. 21 - Prob. 15CQCh. 21 - Prob. 16CQCh. 21 - Prob. 17CQCh. 21 - Evolution is a fact. Evolution is a theory....Ch. 21 - Prob. 19CQCh. 21 - Prob. 20CQCh. 21 - Prob. 21CQCh. 21 - Prob. 22CQCh. 21 - Prob. 23CQCh. 21 - Prob. 1PEACh. 21 - Prob. 2PEACh. 21 - Prob. 3PEACh. 21 - Prob. 4PEACh. 21 - Prob. 1PEBCh. 21 - Prob. 2PEBCh. 21 - Prob. 3PEBCh. 21 - Prob. 4PEB
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- Describe an example of natural selection acting on new DNA patterns to select the most advantageous characteristics.arrow_forward/tqżytbrxg Darwin's Bark Spider Claims Question: Why do traits for silk flexibility vary within this family of Darwin's bark spiders? Remember these are claims about why the trait for silk flexibility varies within the spider family. Claim 1: The offspring have mutations that affect their traits. Do we have enough evidence to support or eliminate any of the claims? WHY OR WHY Claim 2: The offspring's traits depend on which parent the offspring received more traits from. Claim 3: The offspring received different combinations of traits from their parents. NOT? Students, write your response! Pear Deck Interactarrow_forwardSmall birds like that in (Figure 1) can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. Fat is a good form of energy storage because it provides the most energy per unit mass: 1.00 grams of fat provides about 9.40 (food) Calories, compared to 4.20 (food) Calories per 1.00 grams of carbohydrate. Remember that Calories associated with food, which are always capitalized, are not exactly the same as calories used in physics or chemistry, even though they have the same name. More specifically, one food Calorie is equal to 1000 calories of mechanical work or 4184 joules. Therefore, in this problem use the conversion factor 1 Cal = 4184 J. Figure 1 of 1 Part A Consider a bird that flies at an average speed of 10.7 m/s and releases energy from its body fat reserves at an average rate of 3.70 W (this rate represents the power consumption of the bird). Assume that the bird consumes 4.00 g of fat to fly over a distance do without stopping for…arrow_forward
- Small birds like that in (Figure 1) can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. Fat is a good form of energy storage because it provides the most energy per unit mass: 1.00 grams of fat provides about 9.40 (food) Calories, compared to 4.20 (food) Calories per 1.00 grams of carbohydrate. Remember that Calories associated with food, which are always capitalized, are not exactly the same as calories used in physics or chemistry, even though they have the same name. More specifically, one food Calorie is equal to 1000 calories of mechanical work or 4184 joules. Therefore, in this problem use the conversion factor 1 Cal = 4184 J. Figure 1 of 1 Part A Consider a bird that flies at an average speed of 10.7 m/s and releases energy from its body fat reserves at an average rate of 3.70 W (this rate represents the power consumption of the bird). Assume that the bird consumes 4.00 g of fat to fly over a distance do without stopping for…arrow_forwardSmall birds like that in (Figure 1) can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. Fat is a good form of energy storage because it provides the most energy per unit mass: 1.00 grams of fat provides about 9.40 (food) Calories, compared to 4.20 (food) Calories per 1.00 grams of carbohydrate. Remember that Calories associated with food, which are always capitalized, are not exactly the same as calories used in physics or chemistry, even though they have the same name. More specifically, one food Calorie is equal to 1000 calories of mechanical work or 4184 joules. Therefore, in this problem use the conversion factor 1 Cal 4184 J. Figure 1 of 1 ▸ View Available Hint(s) db = 455 km Submit Previous Answers ▾ Part B ▶ How many grams of carbohydrate mcarbwould the bird have to consume to travel the same distance db? Express your answer in grams View Available Hint(s) Correct mcarb 8.95 g Submit Part C Previous Answers Correct This is more…arrow_forwardSmall birds like that in (Figure 1) can migrate over long distances without feeding, storing energy mostly as fat rather than carbohydrate. Fat is a good form of energy storage because it provides the most energy per unit mass: 1.00 grams of fat provides about 9.40 (food) Calories, compared to 4.20 (food) Calories per 1.00 grams of carbohydrate. Remember that Calories associated with food, which are always capitalized, are not exactly the same as calories used in physics or chemistry, even though they have the same name. More specifically, one food Calorie is equal to 1000 calories of mechanical work or 4184 joules. Therefore, in this problem use the conversion factor 1 Cal = 4184 J. Figure 1 of 1 > Review | Constants Consider a bird that flies at an average speed of 10.7 m/s and releases energy from its body fat reserves at an average rate of 3.70 W (this rate represents the power consumption of the bird). Assume that the bird consumes 4.00 g of fat to fly over a distance do without…arrow_forward
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