Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)
4th Edition
ISBN: 9780133178579
Author: Ross L. Finney
Publisher: PEARSON
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Chapter 2.1, Problem 44E

(a)

To determine

To check: Whether the statement limx1+f(x)=1 is true or not.

(a)

Expert Solution
Check Mark

Answer to Problem 44E

Yes, the statement limx1+f(x)=1 is true.

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  1

As observed from the graph, the function y=f(x) approaches to 1 as x approaches to 1 from the right side. So,

  limx1+f(x)=1

Therefore, the statement limx1+f(x)=1 is true.

(b)

To determine

To check: Whether the statement limx2f(x) doesn’t exist is true or not.

(b)

Expert Solution
Check Mark

Answer to Problem 44E

The statement limx2f(x) does not exist is false.

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  2

As observed from the graph, the function y=f(x) approaches to 1 as x approaches to 2 from both the sides of x=2 .

  limx2f(x)=limx2+f(x)=1

So, the limit limx2f(x) exists.

Therefore, the statement limx2f(x) does not exist is false.

(c)

To determine

To check: Whether the statement limx2f(x)=2 is true or not.

(c)

Expert Solution
Check Mark

Answer to Problem 44E

The statement limx2f(x)=2 is false.

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  3

As calculated in part (b), the left hand limit and right hand limit is equal to 1 .

  limx2f(x)=limx2+f(x)=1

So, the value of limx2f(x) is not equal to 2 .

Therefore, the statement limx2f(x)=2 is false.

(d)

To determine

To check: Whether the statement limx1f(x)=2 is true or not.

(d)

Expert Solution
Check Mark

Answer to Problem 44E

Yes, the statement limx1f(x)=2 is true.

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  4

As observed from the graph, the function y=f(x) approaches to 2 as x approaches to 1 from the left side.

  limx1f(x)=2

Therefore, the statement limx1f(x)=2 is true.

(e)

To determine

To check: Whether the statement limx1+f(x)=1 is true or not.

(e)

Expert Solution
Check Mark

Answer to Problem 44E

Yes, the statement limx1+f(x)=1 is true.

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  5

As observed from the graph, the function y=f(x) has value equal to 1 for every value x in [1,2] . So,

  limx1+f(x)=1

Therefore, the statement limx1+f(x)=1 is true.

(f)

To determine

To check: Whether the statement limx1f(x) does not exist is true or not.

(f)

Expert Solution
Check Mark

Answer to Problem 44E

Yes, the statement limx1f(x) does not exist is true.

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  6

As calculated in part (d), the value limx1f(x) is equal to 2 .

As calculated in part (e), the value limx1+f(x) is equal to 1 .

Both the left hand and right hand limits are not equal at x=1 . So, the value limx1f(x) does not exist.

Therefore, the statement limx1f(x) does not exist is true.

(g)

To determine

To check: Whether the statement limx0+f(x)=limx0f(x) is true or not.

(g)

Expert Solution
Check Mark

Answer to Problem 44E

Yes, the statement limx0+f(x)=limx0f(x) is true.

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  7

As observed from the graph, the function y=f(x) approaches to 0 as x approaches to 0 from both the sides.

So, the value of both limx0f(x) and limx0+f(x) are equal to 0 .

Therefore, the statement limx0+f(x)=limx0f(x) is true.

(h)

To determine

To check: Whether the statement limxcf(x) exists at every c in (1,1) is true or not.

(h)

Expert Solution
Check Mark

Answer to Problem 44E

Yes, the statement limxcf(x) exists at every c in (1,1) .

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  8

As observed from the graph, the function y=f(x) is a continuous graph in the interval (1,1) .

So, the value limxcf(x) exists at every c in (1,1) .

Therefore, the statement limxcf(x) exists at every c in (1,1) is true.

(i)

To determine

To check: Whether the statement limxcf(x) exists at every c in (1,3) is true or not.

(i)

Expert Solution
Check Mark

Answer to Problem 44E

Yes, the statement limxcf(x) exists at every c in (1,3) is true.

Explanation of Solution

Given information:

The graph of the function is:

  Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy), Chapter 2.1, Problem 44E , additional homework tip  9

As observed from the graph, the function y=f(x) has the value 1 in the interval (1,3) .

So, the value limxcf(x) exists at every c in (1,3) .

Therefore, the statement limxcf(x) exists at every c in (1,3) is true.

Chapter 2 Solutions

Calculus 2012 Student Edition (by Finney/Demana/Waits/Kennedy)

Ch. 2.1 - Prob. 1ECh. 2.1 - Prob. 2ECh. 2.1 - Prob. 3ECh. 2.1 - Prob. 4ECh. 2.1 - Prob. 5ECh. 2.1 - Prob. 6ECh. 2.1 - Prob. 7ECh. 2.1 - Prob. 8ECh. 2.1 - Prob. 9ECh. 2.1 - Prob. 10ECh. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.1 - Prob. 41ECh. 2.1 - Prob. 42ECh. 2.1 - Prob. 43ECh. 2.1 - Prob. 44ECh. 2.1 - Prob. 45ECh. 2.1 - Prob. 46ECh. 2.1 - Prob. 47ECh. 2.1 - Prob. 48ECh. 2.1 - Prob. 49ECh. 2.1 - Prob. 50ECh. 2.1 - Prob. 51ECh. 2.1 - Prob. 52ECh. 2.1 - Prob. 53ECh. 2.1 - Prob. 54ECh. 2.1 - Prob. 55ECh. 2.1 - Prob. 56ECh. 2.1 - Prob. 57ECh. 2.1 - Prob. 58ECh. 2.1 - Prob. 59ECh. 2.1 - Prob. 60ECh. 2.1 - Prob. 61ECh. 2.1 - Prob. 62ECh. 2.1 - Prob. 63ECh. 2.1 - Prob. 64ECh. 2.1 - Prob. 65ECh. 2.1 - Prob. 66ECh. 2.1 - Prob. 67ECh. 2.1 - Prob. 68ECh. 2.1 - Prob. 69ECh. 2.1 - Prob. 70ECh. 2.1 - Prob. 71ECh. 2.1 - Prob. 72ECh. 2.1 - Prob. 73ECh. 2.1 - Prob. 74ECh. 2.1 - Prob. 75ECh. 2.1 - Prob. 76ECh. 2.1 - Prob. 77ECh. 2.1 - Prob. 78ECh. 2.1 - Prob. 79ECh. 2.1 - Prob. 80ECh. 2.2 - Prob. 1QRCh. 2.2 - Prob. 2QRCh. 2.2 - Prob. 3QRCh. 2.2 - Prob. 4QRCh. 2.2 - Prob. 5QRCh. 2.2 - Prob. 6QRCh. 2.2 - Prob. 7QRCh. 2.2 - Prob. 8QRCh. 2.2 - Prob. 9QRCh. 2.2 - Prob. 10QRCh. 2.2 - Prob. 1ECh. 2.2 - Prob. 2ECh. 2.2 - Prob. 3ECh. 2.2 - Prob. 4ECh. 2.2 - Prob. 5ECh. 2.2 - Prob. 6ECh. 2.2 - Prob. 7ECh. 2.2 - Prob. 8ECh. 2.2 - Prob. 9ECh. 2.2 - Prob. 10ECh. 2.2 - Prob. 11ECh. 2.2 - Prob. 12ECh. 2.2 - Prob. 13ECh. 2.2 - Prob. 14ECh. 2.2 - Prob. 15ECh. 2.2 - Prob. 16ECh. 2.2 - Prob. 17ECh. 2.2 - Prob. 18ECh. 2.2 - Prob. 19ECh. 2.2 - Prob. 20ECh. 2.2 - Prob. 21ECh. 2.2 - Prob. 22ECh. 2.2 - Prob. 23ECh. 2.2 - Prob. 24ECh. 2.2 - Prob. 25ECh. 2.2 - Prob. 26ECh. 2.2 - Prob. 27ECh. 2.2 - Prob. 28ECh. 2.2 - Prob. 29ECh. 2.2 - Prob. 30ECh. 2.2 - Prob. 31ECh. 2.2 - Prob. 32ECh. 2.2 - Prob. 33ECh. 2.2 - Prob. 34ECh. 2.2 - Prob. 35ECh. 2.2 - Prob. 36ECh. 2.2 - Prob. 37ECh. 2.2 - Prob. 38ECh. 2.2 - Prob. 39ECh. 2.2 - Prob. 40ECh. 2.2 - Prob. 41ECh. 2.2 - Prob. 42ECh. 2.2 - Prob. 43ECh. 2.2 - Prob. 44ECh. 2.2 - Prob. 45ECh. 2.2 - Prob. 46ECh. 2.2 - Prob. 47ECh. 2.2 - Prob. 48ECh. 2.2 - Prob. 49ECh. 2.2 - Prob. 50ECh. 2.2 - Prob. 51ECh. 2.2 - Prob. 52ECh. 2.2 - Prob. 53ECh. 2.2 - Prob. 54ECh. 2.2 - Prob. 55ECh. 2.2 - Prob. 56ECh. 2.2 - Prob. 57ECh. 2.2 - Prob. 58ECh. 2.2 - Prob. 59ECh. 2.2 - Prob. 60ECh. 2.2 - Prob. 61ECh. 2.2 - Prob. 62ECh. 2.2 - Prob. 63ECh. 2.2 - Prob. 64ECh. 2.2 - Prob. 65ECh. 2.2 - Prob. 66ECh. 2.2 - Prob. 67ECh. 2.2 - Prob. 68ECh. 2.2 - Prob. 69ECh. 2.2 - Prob. 70ECh. 2.2 - Prob. 71ECh. 2.2 - Prob. 1QQCh. 2.2 - Prob. 2QQCh. 2.2 - Prob. 3QQCh. 2.2 - Prob. 4QQCh. 2.3 - Prob. 1QRCh. 2.3 - Prob. 2QRCh. 2.3 - Prob. 3QRCh. 2.3 - Prob. 4QRCh. 2.3 - Prob. 5QRCh. 2.3 - Prob. 6QRCh. 2.3 - Prob. 7QRCh. 2.3 - Prob. 8QRCh. 2.3 - Prob. 9QRCh. 2.3 - Prob. 10QRCh. 2.3 - Prob. 1ECh. 2.3 - Prob. 2ECh. 2.3 - Prob. 3ECh. 2.3 - Prob. 4ECh. 2.3 - Prob. 5ECh. 2.3 - Prob. 6ECh. 2.3 - Prob. 7ECh. 2.3 - Prob. 8ECh. 2.3 - Prob. 9ECh. 2.3 - Prob. 10ECh. 2.3 - Prob. 11ECh. 2.3 - Prob. 12ECh. 2.3 - Prob. 13ECh. 2.3 - Prob. 14ECh. 2.3 - Prob. 15ECh. 2.3 - Prob. 16ECh. 2.3 - Prob. 17ECh. 2.3 - Prob. 18ECh. 2.3 - Prob. 19ECh. 2.3 - Prob. 20ECh. 2.3 - Prob. 21ECh. 2.3 - Prob. 22ECh. 2.3 - Prob. 23ECh. 2.3 - Prob. 24ECh. 2.3 - Prob. 25ECh. 2.3 - Prob. 26ECh. 2.3 - Prob. 27ECh. 2.3 - Prob. 28ECh. 2.3 - Prob. 29ECh. 2.3 - Prob. 30ECh. 2.3 - Prob. 31ECh. 2.3 - Prob. 32ECh. 2.3 - Prob. 33ECh. 2.3 - Prob. 34ECh. 2.3 - Prob. 35ECh. 2.3 - Prob. 36ECh. 2.3 - Prob. 37ECh. 2.3 - Prob. 38ECh. 2.3 - Prob. 39ECh. 2.3 - Prob. 40ECh. 2.3 - Prob. 41ECh. 2.3 - Prob. 42ECh. 2.3 - Prob. 43ECh. 2.3 - Prob. 44ECh. 2.3 - Prob. 45ECh. 2.3 - Prob. 46ECh. 2.3 - Prob. 47ECh. 2.3 - Prob. 48ECh. 2.3 - Prob. 49ECh. 2.3 - Prob. 50ECh. 2.3 - Prob. 51ECh. 2.3 - Prob. 52ECh. 2.3 - Prob. 53ECh. 2.3 - Prob. 54ECh. 2.3 - Prob. 55ECh. 2.3 - Prob. 56ECh. 2.3 - Prob. 57ECh. 2.3 - Prob. 58ECh. 2.3 - Prob. 59ECh. 2.3 - Prob. 60ECh. 2.3 - Prob. 61ECh. 2.3 - Prob. 62ECh. 2.3 - Prob. 63ECh. 2.3 - Prob. 64ECh. 2.4 - Prob. 1QRCh. 2.4 - Prob. 2QRCh. 2.4 - Prob. 3QRCh. 2.4 - Prob. 4QRCh. 2.4 - Prob. 5QRCh. 2.4 - Prob. 6QRCh. 2.4 - Prob. 7QRCh. 2.4 - Prob. 8QRCh. 2.4 - Prob. 9QRCh. 2.4 - Prob. 10QRCh. 2.4 - Prob. 1ECh. 2.4 - Prob. 2ECh. 2.4 - Prob. 3ECh. 2.4 - Prob. 4ECh. 2.4 - Prob. 5ECh. 2.4 - Prob. 6ECh. 2.4 - Prob. 7ECh. 2.4 - Prob. 8ECh. 2.4 - Prob. 9ECh. 2.4 - Prob. 10ECh. 2.4 - Prob. 11ECh. 2.4 - Prob. 12ECh. 2.4 - Prob. 13ECh. 2.4 - Prob. 14ECh. 2.4 - Prob. 15ECh. 2.4 - Prob. 16ECh. 2.4 - Prob. 17ECh. 2.4 - Prob. 18ECh. 2.4 - Prob. 19ECh. 2.4 - Prob. 20ECh. 2.4 - Prob. 21ECh. 2.4 - Prob. 22ECh. 2.4 - Prob. 23ECh. 2.4 - Prob. 24ECh. 2.4 - Prob. 25ECh. 2.4 - Prob. 26ECh. 2.4 - Prob. 27ECh. 2.4 - Prob. 28ECh. 2.4 - Prob. 29ECh. 2.4 - Prob. 30ECh. 2.4 - Prob. 31ECh. 2.4 - Prob. 32ECh. 2.4 - Prob. 33ECh. 2.4 - Prob. 34ECh. 2.4 - Prob. 35ECh. 2.4 - Prob. 36ECh. 2.4 - Prob. 37ECh. 2.4 - Prob. 38ECh. 2.4 - Prob. 39ECh. 2.4 - Prob. 40ECh. 2.4 - Prob. 41ECh. 2.4 - Prob. 42ECh. 2.4 - Prob. 43ECh. 2.4 - Prob. 44ECh. 2.4 - Prob. 45ECh. 2.4 - Prob. 46ECh. 2.4 - Prob. 47ECh. 2.4 - Prob. 48ECh. 2.4 - Prob. 49ECh. 2.4 - Prob. 50ECh. 2.4 - Prob. 51ECh. 2.4 - Prob. 52ECh. 2.4 - Prob. 53ECh. 2.4 - Prob. 54ECh. 2.4 - Prob. 55ECh. 2.4 - Prob. 1QQCh. 2.4 - Prob. 2QQCh. 2.4 - Prob. 3QQCh. 2.4 - Prob. 4QQCh. 2 - Prob. 1RECh. 2 - Prob. 2RECh. 2 - Prob. 3RECh. 2 - Prob. 4RECh. 2 - Prob. 5RECh. 2 - Prob. 6RECh. 2 - Prob. 7RECh. 2 - Prob. 8RECh. 2 - Prob. 9RECh. 2 - Prob. 10RECh. 2 - Prob. 11RECh. 2 - Prob. 12RECh. 2 - Prob. 13RECh. 2 - Prob. 14RECh. 2 - Prob. 15RECh. 2 - Prob. 16RECh. 2 - Prob. 17RECh. 2 - Prob. 18RECh. 2 - Prob. 19RECh. 2 - Prob. 20RECh. 2 - Prob. 21RECh. 2 - Prob. 22RECh. 2 - Prob. 23RECh. 2 - Prob. 24RECh. 2 - Prob. 25RECh. 2 - Prob. 26RECh. 2 - Prob. 27RECh. 2 - Prob. 28RECh. 2 - Prob. 29RECh. 2 - Prob. 30RECh. 2 - Prob. 31RECh. 2 - Prob. 32RECh. 2 - Prob. 33RECh. 2 - Prob. 34RECh. 2 - Prob. 35RECh. 2 - Prob. 36RECh. 2 - Prob. 37RECh. 2 - Prob. 38RECh. 2 - Prob. 39RECh. 2 - Prob. 40RECh. 2 - Prob. 41RECh. 2 - Prob. 42RECh. 2 - Prob. 43RECh. 2 - Prob. 44RECh. 2 - Prob. 45RECh. 2 - Prob. 46RECh. 2 - Prob. 47RECh. 2 - Prob. 48RECh. 2 - Prob. 49RECh. 2 - Prob. 50RECh. 2 - Prob. 51RECh. 2 - Prob. 52RECh. 2 - Prob. 53RECh. 2 - Prob. 54RECh. 2 - Prob. 55RE

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