Bundle: Chemistry: An Atoms First Approach, Loose-leaf Version, 2nd + OWLv2 with Student Solutions Manual, 4 terms (24 months) Printed Access Card
Bundle: Chemistry: An Atoms First Approach, Loose-leaf Version, 2nd + OWLv2 with Student Solutions Manual, 4 terms (24 months) Printed Access Card
2nd Edition
ISBN: 9781337086431
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Cengage Learning
Question
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Chapter 21, Problem 154CP

(a)

Interpretation Introduction

Interpretation: The two repeating units of ABS plastic assuming the three monomer units react in a 1:1:1 mole ratio and in the same order as the monomers are to be drawn. The percent by mass of acrylonitrile, butadiene and styrene in the polymer sample is to be calculated and the relative numbers of monomer units in the given sample of ABS plastic is to be determined.

Concept introduction: The polymers (repeating structural units) are derived from the simple and reactive molecules, called as monomers. ABS plastic is a terpolymer of styrene, acrylonitrile and polybutadiene.

To determine: The structure of two repeating units of ABS plastic assuming the three monomer units react in a 1:1:1 mole ratio and in the same order as the monomers.

(a)

Expert Solution
Check Mark

Answer to Problem 154CP

Answer

The two repeating units of ABS plastic are shown in Figure 1.

Explanation of Solution

Explanation

The structure of the polymer of ABS plastic is shown in figure 1.

The reaction of Abs polymer synthesis is,

Bundle: Chemistry: An Atoms First Approach, Loose-leaf Version, 2nd + OWLv2 with Student Solutions Manual, 4 terms (24 months) Printed Access Card, Chapter 21, Problem 154CP

Figure 1

ABS plastic is a terpolymer synthesized by polymerizing styrene, acrylonitrile and polybutadiene. The chemical formula of ABS polymer is (C8H8.C4H6.C3H3N)n whose structure of two repeating units of monomers is shown in Figure 1

(b)

Interpretation Introduction

Interpretation: The two repeating units of ABS plastic assuming the three monomer units react in a 1:1:1 mole ratio and in the same order as the monomers are to be drawn. The percent by mass of acrylonitrile, butadiene and styrene in the polymer sample is to be calculated and the relative numbers of monomer units in the given sample of ABS plastic is to be determined.

Concept introduction: The polymers (repeating structural units) are derived from the simple and reactive molecules, called as monomers. ABS plastic is a terpolymer of styrene, acrylonitrile and polybutadiene.

To determine: The percent by mass of acrylonitrile, butadiene and styrene in the polymer sample.

(b)

Expert Solution
Check Mark

Answer to Problem 154CP

Answer

The mass percent of acrylonitrile is 16.90%_ .

The mass percent of butadiene is 17.22%_ .

The mass percent of styrene is 33.18%_ .

Explanation of Solution

Explanation

The mass percent of the three given monomers is calculated below.

Given

The mass of bromine to react completely with ABS plastic is 0.605 g .

The mass of ABS plastic is 1.20 g .

The molar mass of bromine is 158g/mol .

The number of moles is calculated by the formula,

Numberofmoles=GivenmassMolarmass

Substitute the given value of the mass and molar mass of bromine in the above expression.

Numberofmolesofbromine=GivenmassMolarmass=0.605g158g/mol=0.003829mol

Hence, each molecule in this polymer contains 0.003829mol .

Therefore, 0.003829mol of bromine reacted with 0.003829mol of polymer.

The ABS plastic is constructed by equimolar ratio of the three molecules. Hence, each molecule is 0.003829mol .

Therefore,

The mass of acrylonitrile, styrene and butadiene is calculated as,

The molar mass of acrylonitrile is 53 g/mol .

The molar mass of butadiene is 54 g/mol .

The molar mass of styrene is 104 g/mol .

The mass of acrylonitrile, styrene and butadiene is calculated by using the formula,

Mass=Number of moles×Molar mass .

Substitute the given value of the number of moles and molar mass of in the above expression.

For acrylonitrile,

Mass of acrylonitrile=Number of moles×Molar mass=0.003829 mol×53 g/mol=0.2029 g

For butadiene,

Mass of butadiene=Number of moles×Molar mass=0.003829 mol×54 g/mol=0.2067 g

For styrene

Mass of styrene=Number of moles×Molar mass=0.003829 mol×104 g/mol=0.3982 g

Therefore,

Mass percent of acrylonitrile, styrene and butadiene is calculated as,

For acrylonitrile,

Mass percent of acrylonitrile = 0.20291.20×10016.90%_

For butadiene,

Mass percent of butadiene = 0.20671.20×10017.22%_

For styrene

Mass percent of styrene = 0.39821.20×10033.18%_

(c)

Interpretation Introduction

Interpretation: The two repeating units of ABS plastic assuming the three monomer units react in a 1:1:1 mole ratio and in the same order as the monomers are to be drawn. The percent by mass of acrylonitrile, butadiene and styrene in the polymer sample is to be calculated and the relative numbers of monomer units in the given sample of ABS plastic is to be determined.

Concept introduction: The polymers (repeating structural units) are derived from the simple and reactive molecules, called as monomers. ABS plastic is a terpolymer of styrene, acrylonitrile and polybutadiene.

To determine: The relative numbers of monomer units in the given sample of ABS plastic.

(c)

Expert Solution
Check Mark

Answer to Problem 154CP

Answer

The three monomer units are in 1:1:2 molar ratios respectively.

Explanation of Solution

Explanation

The relative numbers of the monomer unit in ABS sample is explained below.

On the basis of the above results it is considered that the three monomer unit’s; acrylonitrile, butadiene and styrene are present in 1:1:2 molar ratios respectively.

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Chapter 21 Solutions

Bundle: Chemistry: An Atoms First Approach, Loose-leaf Version, 2nd + OWLv2 with Student Solutions Manual, 4 terms (24 months) Printed Access Card

Ch. 21 - Prob. 11RQCh. 21 - Prob. 12RQCh. 21 - Prob. 1QCh. 21 - Prob. 2QCh. 21 - What is wrong with the following names? Give the...Ch. 21 - Prob. 4QCh. 21 - Prob. 5QCh. 21 - Prob. 6QCh. 21 - Prob. 7QCh. 21 - Prob. 8QCh. 21 - Prob. 9QCh. 21 - Prob. 10QCh. 21 - Prob. 11QCh. 21 - Prob. 12QCh. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Draw all the structural isomers for C8H18 that...Ch. 21 - Draw all the structural isomers for C8H18 that...Ch. 21 - Prob. 17ECh. 21 - Prob. 18ECh. 21 - Draw the structural formula for each of the...Ch. 21 - Prob. 20ECh. 21 - Prob. 21ECh. 21 - Prob. 22ECh. 21 - Prob. 23ECh. 21 - Prob. 24ECh. 21 - Name each of the following alkenes. a. CH2 = CH ...Ch. 21 - Name each of the following alkenes or alkynes. a....Ch. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Name each of the following. a. b. CH3CH2CH2CCl3 c....Ch. 21 - Prob. 32ECh. 21 - There is only one compound that is named...Ch. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - Prob. 37ECh. 21 - Prob. 38ECh. 21 - Prob. 39ECh. 21 - Prob. 40ECh. 21 - Draw all structural and geometrical (cistrans)...Ch. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Prob. 44ECh. 21 - If one hydrogen in a hydrocarbon is replaced by a...Ch. 21 - There are three isomers of dichlorobenzene, one of...Ch. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - Prob. 49ECh. 21 - Minoxidil (C9H15N5O) is a compound produced by...Ch. 21 - Prob. 51ECh. 21 - Prob. 52ECh. 21 - Name all the alcohols that have the formula...Ch. 21 - Prob. 54ECh. 21 - Prob. 55ECh. 21 - Prob. 56ECh. 21 - Prob. 57ECh. 21 - Prob. 58ECh. 21 - Prob. 59ECh. 21 - Prob. 60ECh. 21 - Prob. 61ECh. 21 - Prob. 62ECh. 21 - Prob. 63ECh. 21 - Prob. 64ECh. 21 - Prob. 65ECh. 21 - Prob. 66ECh. 21 - Prob. 67ECh. 21 - Prob. 68ECh. 21 - Prob. 69ECh. 21 - Complete the following reactions. a. CH3CO2H +...Ch. 21 - Prob. 71ECh. 21 - Prob. 72ECh. 21 - Prob. 73ECh. 21 - Prob. 74ECh. 21 - Prob. 75ECh. 21 - The polyester formed from lactic acid, is used for...Ch. 21 - Prob. 77ECh. 21 - Prob. 78ECh. 21 - Prob. 79ECh. 21 - Prob. 80ECh. 21 - Prob. 81ECh. 21 - Prob. 82ECh. 21 - Prob. 83ECh. 21 - Prob. 84ECh. 21 - Prob. 85ECh. 21 - Prob. 86ECh. 21 - Prob. 87ECh. 21 - Prob. 88ECh. 21 - Prob. 89ECh. 21 - Prob. 90ECh. 21 - Prob. 91ECh. 21 - Prob. 92ECh. 21 - Prob. 93ECh. 21 - Prob. 94ECh. 21 - Prob. 95ECh. 21 - Prob. 96ECh. 21 - Prob. 97ECh. 21 - Prob. 98ECh. 21 - Prob. 99ECh. 21 - Prob. 100ECh. 21 - Prob. 101ECh. 21 - Prob. 102ECh. 21 - Prob. 103ECh. 21 - Prob. 104ECh. 21 - Prob. 105ECh. 21 - Prob. 106ECh. 21 - Which base will hydrogen-bond with uracil within...Ch. 21 - Prob. 108ECh. 21 - The base sequences in mRNA that code for certain...Ch. 21 - Prob. 110ECh. 21 - Prob. 111AECh. 21 - Prob. 112AECh. 21 - Prob. 113AECh. 21 - Prob. 114AECh. 21 - Prob. 115AECh. 21 - Prob. 116AECh. 21 - Prob. 117AECh. 21 - Prob. 118AECh. 21 - Prob. 119AECh. 21 - Prob. 120AECh. 21 - Prob. 121AECh. 21 - Prob. 122AECh. 21 - Prob. 123AECh. 21 - Prob. 124AECh. 21 - Prob. 125AECh. 21 - Prob. 126AECh. 21 - Prob. 127AECh. 21 - Prob. 128AECh. 21 - Prob. 129AECh. 21 - Prob. 130AECh. 21 - Prob. 131AECh. 21 - Prob. 132AECh. 21 - Prob. 133AECh. 21 - Prob. 134AECh. 21 - When heat is added to proteins, the hydrogen...Ch. 21 - Prob. 136AECh. 21 - Prob. 137CWPCh. 21 - Prob. 138CWPCh. 21 - Prob. 139CWPCh. 21 - Name each of the following alkenes and alkynes. a....Ch. 21 - a. Name each of the following alcohols. b. Name...Ch. 21 - Prob. 142CWPCh. 21 - Prob. 143CWPCh. 21 - Prob. 144CWPCh. 21 - Prob. 145CPCh. 21 - Prob. 146CPCh. 21 - Prob. 147CPCh. 21 - Prob. 148CPCh. 21 - Prob. 149CPCh. 21 - Prob. 150CPCh. 21 - Prob. 151CPCh. 21 - Prob. 152CPCh. 21 - Prob. 153CPCh. 21 - Prob. 154CPCh. 21 - Stretch a rubber band while holding it gently to...Ch. 21 - Alcohols are very useful starting materials for...Ch. 21 - Prob. 157CPCh. 21 - Prob. 158CPCh. 21 - Prob. 159IPCh. 21 - Prob. 160IPCh. 21 - Prob. 161MPCh. 21 - Prob. 162MP
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