Traffic and Highway Engineering
5th Edition
ISBN: 9781305156241
Author: Garber, Nicholas J.
Publisher: Cengage Learning
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Chapter 21, Problem 12P
To determine
The current PCR for the pavement section and the new IRI that will trigger the rehabilitation.
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An agency uses the following formula to determine pavement condition rating,
PCR = 99.3 − 5.51 (5.0-ROUGH) − 1.59 LNALL − 0.221 AVGOUT − 0.0306 LONG − 0.531 TRAN,
where we have the following.
ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5 LNALL = natural logarithm of alligator cracking, ft per mile AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch LONG = longitudinal cracking, ft per mile TRAN = transverse cracking, number of cracks per mile
And, present serviceability rating is determined as the following.
PSR = 5e−0.0051118 · IRI − 0.0016027
A pavement section has the following distress data.
IRI = 108 in./mi Alligator cracking = 110 ft/mi Average rutting = 0.20 in. Longitudinal cracks = 130 ft/mi Transverse cracks = 12/mi
Determine the current PCR for this section.
PCR =
Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI…
An agency uses the following formula to determine pavement condition rating,
PCR = 99.3 5.51 (5.0-ROUGH) 1.59 LNALL 0.221 AVGOUT 0.0306 LONG
where we have the following.
ROUGH = roughness measured by present serviceability rating (PSR), scale of 0 to 5
LNALL = natural logarithm of alligator cracking, ft per mile
AVGOUT = outer wheel path rutting (all locations averaged), 0.01 inch
LONG = longitudinal cracking, ft per mile
TRAN = transverse cracking, number of cracks per mile
And, present serviceability rating is determined as the following.
PSR = 5e-0.0051118 IRI-0.0016027
A pavement section has the following distress data.
IRI = 106 in./mi
Alligator cracking
110 ft/mi
Average rutting =
0.20 in.
Longitudinal cracks = 130 ft/mi
Transverse cracks = 12/mi
Determine the current PCR for this section.
PCR =
0.531 TRAN,
Now, assume a new roughness measurement is expected soon. When PCR falls below 60, the section will be scheduled for rehabilitation. Determine the new IRI value (in in./mi)…
Chapter 21 Solutions
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