COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 20, Problem 3QAP
To determine
Subsequent motion of the rod
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A conducting rod of mass m 40 g can freely slide down along the two vertical rail tracks as show below.
The tracks are parallel to each other, separated by the distance l = 60 cm, and connected with a resistance
R = 3.52 (the entire system form a circuit). Find the terminal velocity of the rode if the there is an
external uniform magnetic field B = 3.1 T perpendicular to the tracks. Take g = 9.81 m/s².
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The terminal velocity, v =
Find the speed of the rod (in m/s) as a function of time t (in s), assume that the rod starts to slide down
from rest, v(0) = 0. Do not submit the units. Hint: use analogy with RC circuits.
The speed, v(t) =
m/s.
Units m/s
With the exception of compasses, you seldom see or personally experience forces due to the Earth’s small magnetic field.To illustrate this, suppose that in a physics lab you rub a glass rod with silk, placing a 20-nC positive charge on it. Calculate the force on the rod due to the Earth’s magnetic field, if you throw it with a horizontal velocity of 10 m/s due west in a place where the Earth’s field is due north parallel to the ground. (The direction of the force is determined with right hand rule 1 as shown.)
An iron bolt of mass 58.5 g hangs from a string 37.5 cm long. The top end of the string is fixed. Without touching it, a magnet attracts the bolt so that it remains stationary, but is displaced horizontally 25.0 cm to the right from the previously vertical line of the string.
Draw a free-body diagram of the bolt.
Find the tension in the string. Find the magnetic force on the bolt.
magnitude
direction
Chapter 20 Solutions
COLLEGE PHYSICS
Ch. 20 - Prob. 1QAPCh. 20 - Prob. 2QAPCh. 20 - Prob. 3QAPCh. 20 - Prob. 4QAPCh. 20 - Prob. 5QAPCh. 20 - Prob. 6QAPCh. 20 - Prob. 7QAPCh. 20 - Prob. 8QAPCh. 20 - Prob. 9QAPCh. 20 - Prob. 10QAP
Ch. 20 - Prob. 11QAPCh. 20 - Prob. 12QAPCh. 20 - Prob. 13QAPCh. 20 - Prob. 14QAPCh. 20 - Prob. 15QAPCh. 20 - Prob. 16QAPCh. 20 - Prob. 17QAPCh. 20 - Prob. 18QAPCh. 20 - Prob. 19QAPCh. 20 - Prob. 20QAPCh. 20 - Prob. 21QAPCh. 20 - Prob. 22QAPCh. 20 - Prob. 23QAPCh. 20 - Prob. 24QAPCh. 20 - Prob. 25QAPCh. 20 - Prob. 26QAPCh. 20 - Prob. 27QAPCh. 20 - Prob. 28QAPCh. 20 - Prob. 29QAPCh. 20 - Prob. 30QAPCh. 20 - Prob. 31QAPCh. 20 - Prob. 32QAPCh. 20 - Prob. 33QAPCh. 20 - Prob. 34QAPCh. 20 - Prob. 35QAPCh. 20 - Prob. 36QAPCh. 20 - Prob. 37QAP
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- An ion with charge q but with unknown mass is accelerated through a potential difference V , and enters a magnetic field B. After following the semicircular path shown, it lands a distance x from where it entered the magnetic field. Find an expression for the mass of the ion.arrow_forwardThe magnetic force dFg on a infinitesimal segment of current I is dFs = I dEx B Where di is the displacement vector of the infinitesimal current segment. The total magnetic force on a finite current segment is F = 1J (dL x B) 1. If the magnetic field is uniform in space the magnetic force on current simplifies to FB = {(x5). What is vector in this expression? Choose one. is the length of the current segment is the vector from the point where the current enters the uniform field to the point where the current leaves the uniform field. a. What is the magnetic force on the portions of the wire to the left of the dashed line? • is the current. 2. The magnetic field is zero to the left of the dashed line. The magnetic field to the right of the dashed line is uniform outwards. A current carrying wire goes through the region as shown. b. What is the magnetic force on the bottom wire segment? Write answer in component vector form. c. What is the magnetic force on the slanted wire segment?…arrow_forwardThe velocity field in a potential flow is governed by the two kinematic equations grad*u=0 and grad×u=0. The same two equations, grad*B=0 and grad×B=0, govern the distribution of static magnetic fields, and indeed many of the potential flows discussed in mathematics texts were originally derived as magnetic field distributions by nineteenth-century physicists. Where does Newton's second law enter into such velocity distributions?arrow_forward
- USE GRESA THANK YOU An electron experiences a magnetic force of magnitude 4.6×1015N moving at an angle of 60° with respect to the magnetic field of magnitude 3.5×10−3T. Find the speed of the electron. Make a sketch of the problem showing the velocity, magnetic field, and force vectors.arrow_forwardJ 3 show that velocity and acceleration are contravariant vectors and that the gradient of a scalar field is a covariant vector.arrow_forwardcan you help me to solve this? and kindly put the answers as whole number or decimals and not the significant figures? Thank you!arrow_forward
- Near the surface of the earth, a magnet is made to levitate above another magnet, which is on a table, due only to magnetic force. The levitating magnet has a mass of 150 g with its north pole facing the magnet on the table and its south pole facing upwards. A stream of electrons is shot between the magnets, perpendicular to the field. Describe, in general, what will happen to the electrons, ignoring the effects of gravity on the electrons. Sketch the magnetic field between the two magnets.arrow_forwardWrite down an expression for the net force along the (tangentially to) arc of motion on a simple pendulum made of a metal rod of the length l and the mass m carrying the current I . The rod is suspended by the middle on a weightless wire of the length L in the magnetic field B and the gravitational field g perpendicular to the rod (see picture below).arrow_forwardAn experimental magnetically levitated train is supported by magnetic repulsion forces exerted in a direction normal to the tracks. Motion of the train transverse to the tracks is prevented by lateral supports. Suppose that the 25,000-kg train is traveling at 25 m/s on a circular segment of a track of radius R = 150 m, and the bank angle of the track is 40°, what force must the magnetic levitation system exert to support the train, and what total force is exerted by the lateral supports?arrow_forward
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