Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN: 9781305079243
Author: Steven S. Zumdahl, Susan A. Zumdahl
Publisher: Cengage Learning
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Chapter 20, Problem 26E
Interpretation Introduction

Interpretation: The electron configuration of metal ion in each given complex compound is to be stated.

Concept introduction: Valence electrons are filled in four principal orbitals according to the energy levels. The four orbitals are s,p,d and f .

The metals from group 3-12 are known as first row transition metals. The general form of valence electron configuration of these metals is,

[Nobelgas]nfxndynsz

The distribution of electrons among different orbitals is given by electron configuration. When an element loses an electron, a positive charge is accumulated on it, whereas when an element gains an electron, negative charge is accumulated on it.

Expert Solution & Answer
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Answer to Problem 26E

Answer

  1. (a) The electron configuration of metal ion Fe2+ in (NH4)2[Fe(H2O)2Cl4] is [Ar]3d6 .
  2. (b) The electron configuration of metal ion Co2+ in [Co(NH3)2(NH2CH2CH2NH2)]I2 is [Ar]3d7 .
  3. (c) The electron configuration of metal ion Ta5+ in Na2[TaF7] is [Xe]4f14 .
  4. (d) The electron configuration of metal ion Pt2+ in [Pt(NH3)2I2][PtI4] is [Xe]4f145d8 . The electron configuration of metal ion Pt4+ in [Pt(NH3)2I2][PtI4] is [Xe]4f145d6 .

Explanation of Solution

EXPLANATION

(a)

To write: The electron configuration of metal ion in (NH4)2[Fe(H2O)2Cl4] .

The metals from group 3-12 are known as first row transition metals. The general form of valence electron configuration of these metals is,

[Nobelgas]nfxndynsz

Where,

  • n is the shell of principal orbital.
  • x is the number of electrons in f orbital.
  • y is the number of electrons in d orbital.
  • z is the number of electrons in s orbital.

In the complex compound (NH4)2[Fe(H2O)2Cl4] , the metal ion is Fe2+ .

Iron is a group 8 element. The atomic number of iron (Fe) is 26 and its electronic configuration is,

[Ar]3d64s2

It loses two electrons to acquire two positive charges and becomes Fe2+ . The electronic configuration of Fe2+ is,

Fe2+=Fe2e

Substitute the electron configuration of Fe in the above equation.

Fe2+=Fe2e=[Ar]3d64s22e=[Ar]3d6

(b)

To write: The electron configuration of metal ion in [Co(NH3)2(NH2CH2CH2NH2)]I2 .

In the complex compound [Ag(NH3)2]Cl , metal ion is Co2+ .

Cobalt is a group 9 element. The atomic number of cobalt (Co) is 27 and its electronic configuration is,

[Ar]3d74s2

It loses two electrons to acquire two positive charges and becomes Co2+ . The electronic configuration of Co2+ is,

Co2+=Co2e

Substitute the electron configuration of Co in the above equation.

Co2+=Co2e=[Ar]3d74s22e=[Ar]3d7

 (c)

To write: The electron configuration of metal ion in Na2[TaF7] .

In the complex compound Na2[TaF7] , metal ion is Ta5+ .

Tantalum is a group 5 element. The atomic number of tantalum (Ta) is 73 and its electronic configuration is,

[Xe]4f145d36s2

It loses five electrons to acquire five positive charges and becomes Ta5+ . The electronic configuration of Ta5+ is,

Ta5+=Ta5e

Substitute the electron configuration of Ta in the above equation.

Ta5+=Ta5e=[Xe]4f142e=[Xe]4f14

(d)

To write: The electron configuration of metal ion in [Pt(NH3)2I2][PtI4] .

In the complex compound [Pt(NH3)2I2][PtI4] , metal ion is Pt2+ and Pt4+ .

Platinum is a group 10 element. The atomic number of platinum (Pt) is 78 and its electronic configuration is,

[Xe]4f145d96s1

It loses two electrons to acquire two positive charges and becomes Pt2+ . The electronic configuration of Pt2+ is,

Pt2+=Pt2e

Substitute the electron configuration of Pt in the above equation.

Pt2+=Pt2e=[Xe]4f145d96s12e=[Xe]4f145d8

Platinum loses four electrons to acquire four positive charges and becomes Pt4+ . The electronic configuration of Pt4+ is,

Pt4+=Pt4e

Substitute the electron configuration of Pt in the above equation.

Pt4+=Pt4e=[Xe]4f145d96s14e=[Xe]4f145d6

Conclusion

Conclusion

The electron configuration is the representation of distribution of electrons among different orbitals.

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Chapter 20 Solutions

Chemistry: An Atoms First Approach

Ch. 20 - Prob. 1ALQCh. 20 - Prob. 2ALQCh. 20 - Prob. 3ALQCh. 20 - Prob. 4ALQCh. 20 - Prob. 5QCh. 20 - Four different octahedral chromium coordination...Ch. 20 - Prob. 7QCh. 20 - Prob. 8QCh. 20 - Prob. 9QCh. 20 - Prob. 10QCh. 20 - Prob. 11QCh. 20 - Prob. 12QCh. 20 - Prob. 13QCh. 20 - Prob. 14QCh. 20 - Prob. 15QCh. 20 - Prob. 16QCh. 20 - Prob. 17QCh. 20 - Prob. 18QCh. 20 - Prob. 19QCh. 20 - Prob. 20QCh. 20 - Prob. 21ECh. 20 - Prob. 22ECh. 20 - Prob. 23ECh. 20 - Prob. 24ECh. 20 - Prob. 25ECh. 20 - Prob. 26ECh. 20 - Prob. 27ECh. 20 - Prob. 28ECh. 20 - Prob. 29ECh. 20 - Prob. 30ECh. 20 - Prob. 31ECh. 20 - A coordination compound of cobalt(III) contains...Ch. 20 - Prob. 33ECh. 20 - Prob. 34ECh. 20 - Prob. 35ECh. 20 - Prob. 36ECh. 20 - Prob. 37ECh. 20 - Give formulas for the following complex ions. a....Ch. 20 - Prob. 39ECh. 20 - Prob. 40ECh. 20 - Prob. 41ECh. 20 - Amino acids can act as ligands toward transition...Ch. 20 - Prob. 43ECh. 20 - Prob. 44ECh. 20 - Prob. 45ECh. 20 - Prob. 46ECh. 20 - Prob. 47ECh. 20 - Prob. 48ECh. 20 - Prob. 49ECh. 20 - Prob. 50ECh. 20 - Prob. 51ECh. 20 - Prob. 52ECh. 20 - The CrF64 ion is known to have four unpaired...Ch. 20 - Prob. 54ECh. 20 - Prob. 55ECh. 20 - The complex ion Fe(CN)63 is paramagnetic with one...Ch. 20 - Prob. 57ECh. 20 - Prob. 58ECh. 20 - Prob. 59ECh. 20 - Prob. 60ECh. 20 - The wavelength of absorbed electromagnetic...Ch. 20 - The complex ion NiCL42 has two unpaired electrons,...Ch. 20 - How many unpaired electrons are present in the...Ch. 20 - Prob. 64ECh. 20 - Prob. 65ECh. 20 - Prob. 66ECh. 20 - Prob. 67ECh. 20 - Prob. 68ECh. 20 - Silver is sometimes found in nature as large...Ch. 20 - Prob. 70ECh. 20 - Prob. 71AECh. 20 - The compound cisplatin, Pt(NH3)2Cl2, has been...Ch. 20 - Prob. 73AECh. 20 - Prob. 74AECh. 20 - Prob. 75AECh. 20 - Prob. 76AECh. 20 - Prob. 77AECh. 20 - Name the following coordination compounds. a....Ch. 20 - Prob. 79AECh. 20 - Prob. 80AECh. 20 - Carbon monoxide is toxic because it binds more...Ch. 20 - For the process Co(NH3)5Cl2++ClCO(NH3)4Cl2++NH3...Ch. 20 - Prob. 83CWPCh. 20 - Which of the following molecules exhibit(s)...Ch. 20 - Prob. 85CWPCh. 20 - Prob. 86CWPCh. 20 - Prob. 87CWPCh. 20 - Which of the following statement(s) is( are) true?...Ch. 20 - Prob. 89CPCh. 20 - Consider the pseudo-octahedral complex ion of...Ch. 20 - Prob. 91CPCh. 20 - Prob. 92CPCh. 20 - Prob. 93CPCh. 20 - Prob. 94CPCh. 20 - Prob. 95CPCh. 20 - Prob. 96CPCh. 20 - Prob. 97CPCh. 20 - Prob. 98IPCh. 20 - Prob. 99IPCh. 20 - Prob. 100IPCh. 20 - Prob. 101MP
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