Introduction to General, Organic and Biochemistry
11th Edition
ISBN: 9781285869759
Author: Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher: Cengage Learning
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Chapter 20, Problem 20.81P
Interpretation Introduction
Interpretation:
The transformation for the
Concept Introduction:
A monosaccharide in which
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Students have asked these similar questions
One pathway for the metabolism of D-glucose 6-phosphate is its enzyme-catalyzed
conversion to D-fructose 6-phosphate. Show that this transformation can be accom-
plished as two enzyme-catalyzed keto-enol tautomerisms.
СНО
CH,OH
C=0
enzyme
catalysis
Но
Но
H
OH
H
H.
O-
H-
-HO-
ČH,OPO,
ČH,OPO,
D-Glucose 6-phosphate
D-Fructose 6-phosphate
One step in the gluconeogenesis pathway for the biosynthesis of glucose is the partial reduction of 3-phosphoglycerate to give glyceraldehyde 3-phosphate. The process occurs by phosphorylation with ATP to give 1,3-bisphosphoglycerate,
reaction with a thiol group on the enzyme to give an enzyme-bound thioester, and reduction with NADH.
-OPO3²- Enz-SH
H-C-OH
ATP
CH₂OPO3²-
3-phosphoglycerate
O
0-0--0
O
ADP
CH₂CH3
substitute for
1,3-bisphosphoglycerate
C
H-C-OH
CH₂OPO3²-
1,3-bisphosphoglycerate
O=C
CH3-SH
substitute for
Enz-SH
H
H-C-OH
|
CH₂OPO3²-
PO4³-
O.
S-Enz
H-C-OH
glyceraldehyde 3-phosphate
Propose a structure for the first intermediates in the reaction of 1,3-bisphosphoglycerate with a thiol group on the enzyme to form an enzyme-bound thioester. Assume a basic group on the enzyme catalyzes the formation of this
intermediate.
To simplify the drawing process, substitute the structures below for the 1,3-bisphosphoglycerate and Enz-SH.
CH₂OPO3²-
(Enzyme-bound
thioester)
NADH/H*
NAD*,…
Isoerythrogenic acid, C18H26O2, is a acetylic fatty acid that turns vivid vle on exposure to UV light. On Catalytic hydrogenation over a palladium catalyst, five molar equivalents of hydrogen are absorbed, and stearic acid
Chapter 20 Solutions
Introduction to General, Organic and Biochemistry
Ch. 20.1 - Prob. 20.1PCh. 20.2 - Prob. 20.2PCh. 20.2 - Prob. 20.3PCh. 20.3 - Prob. 20.4PCh. 20.4 - Prob. 20.5PCh. 20 - Prob. 20.6PCh. 20 - Prob. 20.7PCh. 20 - Prob. 20.8PCh. 20 - Prob. 20.9PCh. 20 - Prob. 20.10P
Ch. 20 - Prob. 20.11PCh. 20 - Prob. 20.12PCh. 20 - Prob. 20.13PCh. 20 - Prob. 20.14PCh. 20 - Prob. 20.15PCh. 20 - Prob. 20.16PCh. 20 - Prob. 20.17PCh. 20 - Prob. 20.18PCh. 20 - .19 What is an amino sugar? Name the three amino...Ch. 20 - Prob. 20.20PCh. 20 - Prob. 20.21PCh. 20 - Prob. 20.22PCh. 20 - Prob. 20.23PCh. 20 - Prob. 20.24PCh. 20 - Prob. 20.25PCh. 20 - Prob. 20.26PCh. 20 - Prob. 20.27PCh. 20 - Prob. 20.28PCh. 20 - Prob. 20.29PCh. 20 - Prob. 20.30PCh. 20 - Prob. 20.31PCh. 20 - Prob. 20.32PCh. 20 - Prob. 20.33PCh. 20 - Prob. 20.34PCh. 20 - Prob. 20.35PCh. 20 - Prob. 20.36PCh. 20 - Prob. 20.37PCh. 20 - Prob. 20.38PCh. 20 - Prob. 20.39PCh. 20 - Prob. 20.40PCh. 20 - Prob. 20.41PCh. 20 - Prob. 20.42PCh. 20 - Prob. 20.43PCh. 20 - Prob. 20.44PCh. 20 - Prob. 20.45PCh. 20 - 6 Where is glycogen stored in the human body?Ch. 20 - Prob. 20.47PCh. 20 - 8 How is it possible that cows can digest grass...Ch. 20 - Prob. 20.49PCh. 20 - Prob. 20.50PCh. 20 - 1 Hyaluronic acid acts as a lubricant in the...Ch. 20 - 2 The anticlotting property of heparin is partly...Ch. 20 - Prob. 20.53PCh. 20 - Prob. 20.54PCh. 20 - Prob. 20.55PCh. 20 - Prob. 20.56PCh. 20 - Prob. 20.57PCh. 20 - Prob. 20.58PCh. 20 - Prob. 20.59PCh. 20 - Prob. 20.60PCh. 20 - Prob. 20.61PCh. 20 - 2 In making candy or sugar syrups, sucrose is...Ch. 20 - Prob. 20.63PCh. 20 - Prob. 20.64PCh. 20 - Prob. 20.65PCh. 20 - Prob. 20.66PCh. 20 - Prob. 20.67PCh. 20 - Prob. 20.68PCh. 20 - Prob. 20.69PCh. 20 - 0 What are the structural differences between...Ch. 20 - Prob. 20.71PCh. 20 - Prob. 20.72PCh. 20 - Prob. 20.73PCh. 20 - Prob. 20.74PCh. 20 - Prob. 20.75PCh. 20 - Prob. 20.76PCh. 20 - Prob. 20.77PCh. 20 - Prob. 20.78PCh. 20 - Prob. 20.79PCh. 20 - Prob. 20.80PCh. 20 - Prob. 20.81PCh. 20 - Prob. 20.82PCh. 20 - Prob. 20.83PCh. 20 - Prob. 20.84PCh. 20 - Prob. 20.85PCh. 20 - Prob. 20.86PCh. 20 - Prob. 20.87PCh. 20 - Prob. 20.88PCh. 20 - Prob. 20.89P
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- 4. Glycolysis is a metabolic pathway that converts glucose into pyruvate while synthesizing high-energy molecules. During one step of Glycolysis, glucose-6-phosphate (an aldose) is converted to fructose-6-phosphate (a ketose) via an ene-diol intermediate. OH OH O OP OH OH ОН ОН glucose-6-phosphate OH OH OH OP OH fructose-6-phosphate Draw arrow pushing mechanism to describe this isomerization. Use B: and HA as surrogates for basic/acidic amino acid residues.arrow_forwardrivatives: Nucleophilic Acyl Substitution Reactions - EOC O C-O [References] One step in the gluconeogenesis pathway for the biosynthesis of glucose is the partial reduction of 3-phosphoglycerate to give glyceraldehyde 3-phosphate. The process occurs by phosphorylation with ATP to give 1,3-bisphosphoglycerate, reaction with a thiol group on the enzyme to give an enzyme-bound thioester, and reduction with NADH. H-C-OH ATP ADP CH₂OPO32- 3-phosphoglycerate 0= OPO32- C H-C-OH CH₂OPO32 1,3-bisphosphoglycerate Enz-SH PO43- O= C S-Enz H-C-OH CH₂OPO3² (Enzyme-bound thioester) NADH/H+ O=C NAD*, Enz-SH H H-C-OH CH₂OPO3²- glyceraldehyde 3-phosphate Propose a structure for the first intermediate in the reaction of the enzyme-bound thioester with NADH to form glyceraldehyde 3-phosphate. To simplify the drawing process, substitute the structure below for the enzyme-bound thioester. S-CH3 substitute for the CH2CH3 enzyme-bound thioester You do not have to consider stereochemistry. • You do not have…arrow_forwardCholesterol-lowering drugs commonly target O HMG-COA synthase, the enzyme that catalyzes the synthesis of mevalonate O pyruvate decarboxylase complex, which catalyzes the synthesis of acetyl-CoA O mevalonate, an isoprene O HMG-COAreductase, the rate-limiting enzyme in cholesterol biosynthesis O HMG-CoA synthase, the enzyme that catalyzes the first step in cholesterol biosynthesisarrow_forward
- One of the steps in the pentose phosphate pathway for glucose catabolism is the reaction of sedoheptulose 7-phosphate with glyceraldehydes 3-phosphate in the presence of a transaldolase to yield erythrose 4-phosphate and fructose 6-phosphate. (a) The first part of the reaction is the formation of a protonated Schiff base of sedoheptulose 7-phosphate with a lysine residue in the enzyme followed by a retro-aldol cleavage to give an enamine plus erythrose 4-phosphate. Show the structure of the enamine and the mechanism by which it is formed. (b) The second part of the reaction is a nucleophilic addition of the enamine to glyceraldehyde 3-phosphate followed by hydrolysis of the Schiff base to give fructose 6-phosphate. Show the mechanism.arrow_forwardCarbonic anhydrase facilitates the dissolution of carbon dioxide gas into water by catalyzing its hydration. Is the catalyzed reaction efficient? By what criterion do you state that?arrow_forwardYou do not have to consider stereochemistry. You do not have to explicitly draw H atoms. Do not include lone pairs in your answer. Draw phosphate groups, when present, as in the question: in basic form and with a phosphorous oxygen double bond.arrow_forward
- The hydrolysis of pyrophosphate to orthophosphate drives biosynthetic reactions such as DNA synthesis. In Escherichia coli, a pyrophosphatase catalyzes this hydrolytic reaction. The pyrophosphatase has a mass of 120 kDa and consists of six identical subunits. A unit of activity for this enzyme, U, is the amount of enzyme that hydrolyzes 10 umol of pyrophosphate in 15 minutes. The purified enzyme has a Vnax of 2800 U per milligram of enzyme. When (S] >> KM, how many micromoles of substrate can 1 mg of enzyme hydrolyze per second? Vnax = umol -s. mg- If cach enzyme subunit has one active site, how many micromoles of active sites, or (E]r, are there in 1 mg of enzyme? (Er = umol - mg-arrow_forwardThis is a thermodynamically unfavorable process, with ΔG°' = +13.7 kJ/mol. In a liver cell at 37°C the concentrations of both phosphate and glucose are normally maintained at about 6.2 mM each, while the glucose-6-phosphate is around 2.1 mM . Calcaulate the Gibb's Free Energy (ΔG) of this reaction occuring in the liverarrow_forwardA chemist synthesized compound X as a racemic mixture. When the ketone group in X was enzymatically reduced to the corresponding alcohol, a 100% yield was obtained of the product shown below. Choose the statement that best describes this result. ОН enzyme C;H1 `OCH,CH; pH 4.0 C3H1 `OCH,CH3 ОН ÕH X (racemic) (100% yield) One enantiomer of compound X reacts quickly with the enzyme. The other enantiomer of compound X is unreactive, but rapidly equilibrates with the reactive enantiomer under the reaction conditions. Since compound X was racemic, it makes sense that only a single product was obtained. O The product is a meso compound, so either enantiomer of compound X gives the same product. One enantiomer of compound X reacts quickly with the enzyme, while the other enantiomer of compound X remains unchanged.arrow_forward
- a) The D-aldopentose A, C5H1005, reacts with HNO3 to yield an optically active aldaric acid B. Kiliani-Fischer chain extension of A produces a pair of D-aldohexoses C and D. C is converted by HNO3 to an optically active aldaric acid, but D is converted by HNO3 to an optically inactive aldaric acid. Write acyclic Fischer projections for A, B, C, D. b) Disaccharide E is a reducing sugar. It is hydrolyzed by an α-glycosidase enzyme, which means it contains an α- glycoside link. Treatment of E with Ag2O and excess Mel gives an octamethyl derivative F. Hydrolysis of F in dilute aqueous acid gives the pair of molecules shown below. Write the structures of E and F. (If the stereochemistry at a particular carbon is not determined by the above data, indicate this with a wavy line as shown below.) HO OMe OMe MeO MeO MOH OMe mOH OMe OMearrow_forwarda) The D-aldopentose A, C5H1005, reacts with HNO3 to yield an optically active aldaric acid B. Kiliani-Fischer chain extension of A produces a pair of D-aldohexoses C and D. C is converted by HNO3 to an optically active aldaric acid, but D is converted by HNO3 to an optically inactive aldaric acid. Write acyclic Fischer projections for A, B, C, D.arrow_forwardQ2 CH,OH CH,OPO,2- H H OH H OH 0-PO,2- но но OH H. OH OH Glucose-1-phosphate Glucose-6-phosphate Calculate the standard free-energy change (AG°) fo the reaction catalyzed by the enzyme phosphoglucomutase. When at standard temperature (25 °C) and pressure, the equilibrium of each molecule is 1 mM glucose 1-phosphate and 19 mM glucose 6-phosphate. HINT: at 25 °C, RT = 2.479 kJ/molarrow_forward
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