Chapter 20, Problem 14PP

Program Plan Intro

To open zip file and print the first “10” lines of files in it

Program plan:

• Import necessary packages.
• Create a class “ZipFileViewer”,
  • Define the “main()” method.
    • Create a “Scanner” object.
    • Prompt the user to enter the directory path.
    • Get the directory path from the user.
    • Call the method “deepZipView()”.
  • Define the method “deepZipView ()”,
    • Initialize the variable.
    • Execute “try” statement,
      • Create a list.
      • Create a loop,
        • Get the file.
        • If the file is a directory,
        • • Display the path of the directory.
        • Otherwise, if the path end with “.zip”,
        • • Copy the nested zip file to a temporary file.
          • Initialize the string variable for file name and extension.
          • Get the temporary file path and directory path.
          • Get the file name into temporary file name.
          • Get the path into the temporary path.
          • Call the method “copy()”.
          • Call the method “deepZipView()”.
        • Otherwise,
        • • Print the first “10” lines of the regular file.
          • Get the lines of files.
          • Create a list.
          • Create a loop,
            • Print the line of file.
              • Catch if exception occurs,
                • Print an exception.