(a). Answer The total revenue = x ⋅ 3 − x 40 2 . Explanation Given: Number of people = 60 . p = 3 − x 40 2 . Concept Used: The total revenue per trip received by the bus company r ( x ) = x ⋅ p . Calculation: The formula for total revenue is: r ( x ) = x ⋅ p = x ⋅ 3 − x 40 2 Conclusion: The total revenue = x ⋅ 3 − x 40 2 b. To determine To calculate: The number of people per trip that will make the marginal zero. Answer The number of people per trip that will make the marginal zero = 40 . Explanation Given: Number of people = 60 p = 3 − x 40 2 . Concept Used: The total revenue per trip received by the bus company r ( x ) = x ⋅ p . Calculation: Find the value of x such that, d d t r ( x ) = 0 . d d t r t = 0 d d t 3 − x 40 2 = 0 3 − x 40 2 − 2 x 40 3 − x 40 = 0 3 − x 40 3 − x 40 − 2 x 40 = 0 3 − x 40 3 − 3 x 40 = 0 3 − x 40 = 0 or 3 − 3 x 40 = 0 x = 40 or x = 120 x = 120 is not possible as the bus can take only 60 people. Therefore, the number of people per trip that will make the marginal zero = 40 Also, the corresponding fare will be: p = 3 − 40 40 2 = 3 − 1 2 = 4 Conclusion:

Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020

6th Edition

ISBN: 9781418300203

Author: Prentice Hall

Publisher: Prentice Hall

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Question

Chapter 2, Problem 74RE

(a).

To determine

To find: The formula for the total revenue per trip received by the bus company.

(a).

Expert Solution

Answer to Problem 74RE

The total revenue =x⋅3−x402 .

Explanation of Solution

Given:

Number of people =60 .

p=3−x402 .

Concept Used:

The total revenue per trip received by the bus company r(x)=x⋅p .

Calculation:

The formula for total revenue is:

r(x)=x⋅p=x⋅3−x402

Conclusion:

The total revenue =x⋅3−x402

To determine

To calculate: The number of people per trip that will make the marginal zero.

Expert Solution

Answer to Problem 74RE

The number of people per trip that will make the marginal zero =40 .

Explanation of Solution

Given:

Number of people =60

p=3−x402 .

Concept Used:

The total revenue per trip received by the bus company r(x)=x⋅p .

Calculation:

Find the value of x such that, ddtr(x)=0 .

ddtrt=0ddt3−x402=03−x402−2x403−x40=03−x403−x40−2x40=03−x403−3x40=03−x40=0 or 3−3x40=0x=40 or x=120

x=120 is not possible as the bus can take only 60 people.

Therefore, the number of people per trip that will make the marginal zero =40

Also, the corresponding fare will be:

p=3−40402=3−12=4

Conclusion:

Chapter 2, Problem 73RE

Chapter 2, Problem 75RE

Chapter 2 Solutions

Ch. 2.1 - Prob. 1QR Ch. 2.1 - Prob. 2QR Ch. 2.1 - Prob. 3QR Ch. 2.1 - Prob. 4QR Ch. 2.1 - Prob. 5QR Ch. 2.1 - Prob. 6QR Ch. 2.1 - Prob. 7QR Ch. 2.1 - Prob. 8QR Ch. 2.1 - Prob. 9QR Ch. 2.1 - Prob. 10QR

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.2 - Prob. 1QR Ch. 2.2 - Prob. 2QR Ch. 2.2 - Prob. 3QR Ch. 2.2 - Prob. 4QR Ch. 2.2 - 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Prob. 46E Ch. 2.2 - Prob. 47E Ch. 2.2 - Prob. 48E Ch. 2.3 - Prob. 1QR Ch. 2.3 - Prob. 2QR Ch. 2.3 - Prob. 3QR Ch. 2.3 - Prob. 4QR Ch. 2.3 - Prob. 5QR Ch. 2.3 - Prob. 6QR Ch. 2.3 - Prob. 7QR Ch. 2.3 - Prob. 8QR Ch. 2.3 - Prob. 9QR Ch. 2.3 - Prob. 10QR Ch. 2.3 - Prob. 1E Ch. 2.3 - Prob. 2E Ch. 2.3 - Prob. 3E Ch. 2.3 - Prob. 4E Ch. 2.3 - Prob. 5E Ch. 2.3 - Prob. 6E Ch. 2.3 - Prob. 7E Ch. 2.3 - Prob. 8E Ch. 2.3 - Prob. 9E Ch. 2.3 - Prob. 10E Ch. 2.3 - Prob. 11E Ch. 2.3 - Prob. 12E Ch. 2.3 - Prob. 13E Ch. 2.3 - Prob. 14E Ch. 2.3 - Prob. 15E Ch. 2.3 - Prob. 16E Ch. 2.3 - Prob. 17E Ch. 2.3 - Prob. 18E Ch. 2.3 - Prob. 19E Ch. 2.3 - Prob. 20E Ch. 2.3 - Prob. 21E Ch. 2.3 - Prob. 22E Ch. 2.3 - Prob. 23E Ch. 2.3 - Prob. 24E Ch. 2.3 - Prob. 25E Ch. 2.3 - Prob. 26E Ch. 2.3 - Prob. 27E Ch. 2.3 - Prob. 28E Ch. 2.3 - Prob. 29E Ch. 2.3 - Prob. 30E Ch. 2.3 - Prob. 31E Ch. 2.3 - Prob. 32E Ch. 2.3 - Prob. 33E Ch. 2.3 - Prob. 34E Ch. 2.3 - Prob. 35E Ch. 2.3 - Prob. 36E Ch. 2.3 - Prob. 37E Ch. 2.3 - Prob. 38E Ch. 2.3 - 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Prob. 3RWDT Ch. 2 - Prob. 4RWDT Ch. 2 - Prob. 5RWDT Ch. 2 - Prob. 6RWDT Ch. 2 - Prob. 7RWDT Ch. 2 - Prob. 8RWDT Ch. 2 - Prob. 9RWDT Ch. 2 - Prob. 10RWDT Ch. 2 - Prob. 1RE Ch. 2 - Prob. 2RE Ch. 2 - Prob. 3RE Ch. 2 - Prob. 4RE Ch. 2 - Prob. 5RE Ch. 2 - Prob. 6RE Ch. 2 - Prob. 7RE Ch. 2 - Prob. 8RE Ch. 2 - Prob. 9RE Ch. 2 - Prob. 10RE Ch. 2 - Prob. 11RE Ch. 2 - Prob. 12RE Ch. 2 - Prob. 13RE Ch. 2 - Prob. 14RE Ch. 2 - Prob. 15RE Ch. 2 - Prob. 16RE Ch. 2 - Prob. 17RE Ch. 2 - Prob. 18RE Ch. 2 - Prob. 19RE Ch. 2 - Prob. 20RE Ch. 2 - Prob. 21RE Ch. 2 - Prob. 22RE Ch. 2 - Prob. 23RE Ch. 2 - Prob. 24RE Ch. 2 - Prob. 25RE Ch. 2 - Prob. 26RE Ch. 2 - Prob. 27RE Ch. 2 - Prob. 28RE Ch. 2 - Prob. 29RE Ch. 2 - Prob. 30RE Ch. 2 - Prob. 31RE Ch. 2 - Prob. 32RE Ch. 2 - Prob. 33RE Ch. 2 - Prob. 34RE Ch. 2 - Prob. 35RE Ch. 2 - Prob. 36RE Ch. 2 - Prob. 37RE Ch. 2 - Prob. 38RE Ch. 2 - Prob. 39RE Ch. 2 - Prob. 40RE Ch. 2 - Prob. 41RE Ch. 2 - Prob. 42RE Ch. 2 - Prob. 43RE Ch. 2 - Prob. 44RE Ch. 2 - Prob. 45RE Ch. 2 - 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