Digital Fundamentals (11th Edition)
11th Edition
ISBN: 9780132737968
Author: Thomas L. Floyd
Publisher: PEARSON
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Question
Chapter 2, Problem 53P
(a)
Program Plan Intro
To add the BCDnumbers
(b)
Program Plan Intro
To add the BCD numbers
(c)
Program Plan Intro
To add the BCD numbers
(d)
Program Plan Intro
To add the BCD numbers
(e)
Program Plan Intro
To add the BCD numbers
(f)
Program Plan Intro
To add the BCD numbers
(g)
Program Plan Intro
To add the BCD numbers
(h)
Program Plan Intro
To add the BCD numbers
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427 in BCD is converted to pure binary integer what is its binary value
(a) 010000100111
(b) 10000100111
(c) 110101011
(d) 111001000010
Add the following BCD numbers:(a) 0010 + 0001 (b) 0101 + 0011(c) 0111 + 0010 (d) 1000 + 0001(e) 00011000 + 00010001 (f) 01100100 + 00110011(g) 01000000 + 01000111 (h) 10000101 + 00010011
Convert the following binary numbers to octal:(a) 110101111 (b) 1001100010 (c) 10111111001
Chapter 2 Solutions
Digital Fundamentals (11th Edition)
Ch. 2.1 - Prob. 1CUCh. 2.1 - Prob. 2CUCh. 2.2 - Prob. 1CUCh. 2.2 - Prob. 2CUCh. 2.2 - Prob. 3CUCh. 2.3 - Prob. 1CUCh. 2.3 - Prob. 2CUCh. 2.4 - Prob. 1CUCh. 2.4 - Prob. 2CUCh. 2.4 - Prob. 3CU
Ch. 2.5 - Prob. 1CUCh. 2.5 - Prob. 2CUCh. 2.6 - Prob. 1CUCh. 2.6 - Prob. 2CUCh. 2.6 - Prob. 3CUCh. 2.6 - Prob. 4CUCh. 2.7 - Prob. 1CUCh. 2.7 - Prob. 2CUCh. 2.7 - Prob. 3CUCh. 2.7 - What is the sign of the product when two negative...Ch. 2.7 - Prob. 5CUCh. 2.7 - What is the sign of the quotient when a positive...Ch. 2.7 - Prob. 7CUCh. 2.8 - Prob. 1CUCh. 2.8 - Prob. 2CUCh. 2.8 - Prob. 3CUCh. 2.8 - Prob. 4CUCh. 2.8 - Prob. 5CUCh. 2.8 - Prob. 6CUCh. 2.9 - Prob. 1CUCh. 2.9 - Prob. 2CUCh. 2.9 - Prob. 3CUCh. 2.9 - Prob. 4CUCh. 2.10 - What is the binary weight of each 1 in the...Ch. 2.10 - Convert the following decimal numbers to BCD 6 15...Ch. 2.10 - Prob. 3CUCh. 2.10 - Prob. 4CUCh. 2.11 - Prob. 1CUCh. 2.11 - Prob. 2CUCh. 2.11 - Prob. 3CUCh. 2.12 - Prob. 1CUCh. 2.12 - Prob. 2CUCh. 2.12 - Prob. 3CUCh. 2.12 - Prob. 4CUCh. 2.12 - Prob. 5CUCh. 2 - The decimal number system is a weighted system...Ch. 2 - Prob. 2TFQCh. 2 - Prob. 3TFQCh. 2 - Prob. 4TFQCh. 2 - Prob. 5TFQCh. 2 - Prob. 6TFQCh. 2 - Prob. 7TFQCh. 2 - The hexadecimal number system has 16 characters,...Ch. 2 - BCD stands for binary coded decimalCh. 2 - Prob. 10TFQCh. 2 - Prob. 11TFQCh. 2 - Prob. 12TFQCh. 2 - Prob. 1STCh. 2 - Prob. 2STCh. 2 - Prob. 3STCh. 2 - The decimal number 17 is equal to the binary...Ch. 2 - The decimal number 175 is equal to the binary...Ch. 2 - Prob. 6STCh. 2 - Prob. 7STCh. 2 - Prob. 8STCh. 2 - Prob. 9STCh. 2 - Prob. 10STCh. 2 - Prob. 11STCh. 2 - Prob. 12STCh. 2 - Prob. 13STCh. 2 - Prob. 14STCh. 2 - Prob. 15STCh. 2 - Prob. 16STCh. 2 - Prob. 17STCh. 2 - Prob. 18STCh. 2 - Prob. 19STCh. 2 - Prob. 20STCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - How high can you count with four decimal digits?Ch. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - What is the highest decimal number that can be...Ch. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Convert each hexadecimal number to decimal: 2316...Ch. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Convert the following decimal numbers to BCD: 104...Ch. 2 - Prob. 50PCh. 2 - Convert each of the BCD numbers to decimal...Ch. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - In a certain application a 4-bit binary sequence...Ch. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69P
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- Convert each of the BCD numbers to decimal:(a) 10000000 (b) 001000110111(c) 001101000110 (d) 010000100001(e) 011101010100 (f) 100000000000(g) 100101111000 (h) 0001011010000011(i) 1001000000011000 (j) 0110011001100111arrow_forwardConvert each binary number to octal:(a) 100 (b) 110 (c) 1100(d) 1111 (e) 11001 (f) 11110(g) 110011 (h) 101010 (i) 10101111arrow_forward000I1001 (y) 53. Add the following BCD numbers: (a) 1000 + 0110 (b) 0111 + 0101 (c) 1001 + 1000 (e) 00100101 + 00100111 (g) 10011000 + 10010111 (d) 1001 + 0111 (f) 01010001 + 01011000 (h) 010101100001 + 011100001000 54. Convert cach pair of decimal numbers to BCD, and add as indicated: (a) 4 - 3 (b) 5 + 2 (d) 17 + 12 ie) 28 - 23 (f) 65 + 58 (g) 113 + 101 (h) 295 – 157arrow_forward
- The BCD number for decimal 473 is(a) 111011010 (b) 110001110011 (c) 010001110011 (d) 010011110011arrow_forwardObtain the 1’s and 2’s complements of the following binary numbers: (a) 00010000 (d) 10101010 (b) 00000000 (e) 10000101 (c) 11011010 (f) 11111111 Represent the unsigned decimal numbers 791 and 658 in BCD, and then show the steps necessary to form their sum. Express the following numbers in decimal: (a) (10110.0101) 2 (b) (16.5) 16 (c) (26.24) 8 (d) (DADA.B) 16 (e) (1010.1101) 2 Add and multiply the following numbers without converting them to decimal. (a)Binary numbers 1011 and 101. (b)Hexadecimal numbers 2E and 34.arrow_forwardConvert the BCD NUMBER 0010 0000 0010 0110.0101 0110 0010 0101 to BINARY number showing the stepsarrow_forward
- Convert the following Hexa value (ABC)16 to Binary a. 101010111101 b. 101010111110 c. 101010111111 d. 101010111100arrow_forwardConvert the following binary numbers into decimal:(a) 100001 (b) 100111 (c) 101010 (d) 111001(e) 1100000 (f) 11111101 (g) 11110010 (h) 11111111arrow_forwardConvert 00110011 to decimal (step by step)arrow_forward
- When 725010 is converted to floating point notation, the biased exponent is O A. 1000 11002 O B. 0000 10112 O C. 1000 10112 D. 0000 11002arrow_forwardConvert the following IEEE floating-point number to base 10. Show your work. 0 0111 1101 011 0000 0000 0000 0000 0000arrow_forward8- Convert to octal and then to decimal: (a) (10111011.1): (b) (1101101.011):arrow_forward
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