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Chapter 2, Problem 53P

(a)

To determine

The average velocity over the time interval t=0.0s to t=10.0s.

(a)

Expert Solution
Check Mark

Answer to Problem 53P

The average velocity over the time interval t=0.0s to t=10.0s, is 3.0m/s_.

Explanation of Solution

Write the expression for average velocity.

  vavg=ΔxΔt        (I)

Conclusion:

Substitute, 30m0m for Δx, and 10.0s0.0s for Δt in equation (I) to find the average velocity from t=0.0s to t=10.0s.

  vavg=30m0m10.0s0s=3.0m/s

Therefore, the average velocity over the time interval t=0.0s to t=10.0s, is 3.0m/s_.

(b)

To determine

The average velocity over the time interval t=0.0s to t=5.0s.

(b)

Expert Solution
Check Mark

Answer to Problem 53P

The average velocity over the time interval t=0.0s to t=5.0s is 4.5m/s_.

Explanation of Solution

Use equation (I) to find the answer.

Conclusion:

Substitute, 22.5m0m for Δx, and 5.0s0.0s for Δt in equation (I) to find the average velocity from t=0.0s to t=5.0s.

  vavg=22.5m0m5.0s0s=4.5m/s

Therefore, the average velocity over the time interval t=0.0s to t=5.0s is 4.5m/s_.

(c)

To determine

The average velocity between t=5.0s and t=10.0s.

(c)

Expert Solution
Check Mark

Answer to Problem 53P

The average velocity between t=5.0s and t=10.0s is 1.5m/s_.

Explanation of Solution

Use equation (I) to find the answer.

Conclusion:

Substitute, 30m22.5m for Δx, and 10.0s5.0s for Δt in equation (I) to find the average velocity from t=5.0s to t=10.0s.

  vavg=30m22.5m10.0s5.0s=1.5m/s

Therefore, the average velocity between t=5.0s and t=10.0s is 1.5m/s_.

(d)

To determine

The relation of answers in part (a), (b), and (c).

(d)

Expert Solution
Check Mark

Answer to Problem 53P

The relation is average of answers in part (b), and (c) is answer in part (a).

Explanation of Solution

The total average velocity over the time interval t=0.0s to t=10.0s must be equal to the average of the individual average velocities for the time intervals t=0.0s to t=5.0s and t=5.0s to t=10.0s.

Write the expression for the average velocity.

  vavg,a=vavg,b+vavg,c2        (II)

Conclusion:

Substitute, 4.5m/s for vavg,b, 1.5m/s for vavg,c in equation (II).

  vavg,a=4.5m/s+1.5m/s2=3.0m/s

Therefore, the relation is average of answers in part (b), and (c) is answer in part (a).

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Chapter 2 Solutions

Bundle: College Physics: Reasoning And Relationships, 2nd + Webassign Printed Access Card For Giordano's College Physics, Volume 1, 2nd Edition, Multi-term

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