Give the formula and the number of each ion that makes up each of the following compounds: (a) K 2 S (b) CoSO 4 (c) KMnO 4 (d) (NH 4 ) 3 PO 4 (e) Ca(CIO) 2 (f)NaCH 3 CO 2

Question

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Answer 1

Textbook Question

Chapter 2, Problem 43PS

Give the formula and the number of each ion that makes up each of the following compounds:

(a) K₂S

(b) CoSO₄

(c) KMnO₄

(d) (NH₄)₃PO₄

(e) Ca(CIO)₂

(f)NaCH₃CO₂

(a)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$K2S$ is composed of one $K+$ ion and two $S2−$ ions.

Explanation of Solution

In the given ionic compound $K2S$ , there are $K$ ion and $S$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and thereby the charge of $S$ must be $2-$ to balance the $2+$ charge of two $K$ ions.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and two $S2−$ ions are present in $K2S$ compound.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$CoSO4$ is composed of one $Co2+$ ions and one $SO42−$ ion.

Explanation of Solution

In the given ionic compound $CoSO4$ , there are $Co$ ion and $SO4$ ion present. Since the charge of $SO4$ is $2-$ , then the charge of $Co$ must be $2+$ to balance the charge of the $SO4$ ions .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Co2+$ ion and one $SO42−$ ion are present in $CoSO4$ compound.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$KMnO4$ is composed of one $K+$ ion and one $MnO4−$ ion.

Explanation of Solution

In the given ionic compound $KMnO4$ , there are $K$ ion and $MnO4$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and also the charge of $MnO4$ is $1-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and one $MnO4−$ ion are present in $KMnO4$ compound.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$(NH4)3PO4$ is composed of three $NH4+$ ion and one $PO4$ ion.

Explanation of Solution

In the given ionic compound $(NH4)3PO4$ , there are $NH4$ ion and $PO4$ ion present. The charge of $NH4$ is $1+$ and also the charge of $PO4$ is $3-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $NH4+$ ion and one $PO43−$ ion are present in $(NH4)3PO4$ compound.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$Ca(ClO)2$ is composed of one $Ca2+$ ion and two $ClO−$ ions.

Explanation of Solution

In the given ionic compound $Ca(ClO)2$ , there are $Ca$ ion and $ClO$ ion present. Since the $Ca$ is group $IIA$ element, then the charge will be $2+$ and the charge of $ClO$ is $1-$ . So there will be two $ClO−$ ions for each of the $Ca2+$ ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Ca2+$ ion and one $ClO−$ ion are present in $Ca(ClO)2$ compound.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$NaCH3CO2$ is composed of one $Na+$ ion and one $CH3CO2−$ ion .

Explanation of Solution

In the given ionic compound $NaCH3CO2$ , there are $Na$ ion and $CH3CO2$ ion present. Since the Na is group $IA$ element, then the charge will be $1+$ and thereby the charge $CH3CO2$ must be $1-$ to balance the two $1+$ charge of sodium ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Na+$ ion and one $CH3CO2−$ ion are present in $NaCH3CO2$ compound.

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Answer 2

Textbook Question

Chapter 2, Problem 43PS

Give the formula and the number of each ion that makes up each of the following compounds:

(a) K₂S

(b) CoSO₄

(c) KMnO₄

(d) (NH₄)₃PO₄

(e) Ca(CIO)₂

(f)NaCH₃CO₂

(a)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$K2S$ is composed of one $K+$ ion and two $S2−$ ions.

Explanation of Solution

In the given ionic compound $K2S$ , there are $K$ ion and $S$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and thereby the charge of $S$ must be $2-$ to balance the $2+$ charge of two $K$ ions.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and two $S2−$ ions are present in $K2S$ compound.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$CoSO4$ is composed of one $Co2+$ ions and one $SO42−$ ion.

Explanation of Solution

In the given ionic compound $CoSO4$ , there are $Co$ ion and $SO4$ ion present. Since the charge of $SO4$ is $2-$ , then the charge of $Co$ must be $2+$ to balance the charge of the $SO4$ ions .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Co2+$ ion and one $SO42−$ ion are present in $CoSO4$ compound.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$KMnO4$ is composed of one $K+$ ion and one $MnO4−$ ion.

Explanation of Solution

In the given ionic compound $KMnO4$ , there are $K$ ion and $MnO4$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and also the charge of $MnO4$ is $1-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and one $MnO4−$ ion are present in $KMnO4$ compound.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$(NH4)3PO4$ is composed of three $NH4+$ ion and one $PO4$ ion.

Explanation of Solution

In the given ionic compound $(NH4)3PO4$ , there are $NH4$ ion and $PO4$ ion present. The charge of $NH4$ is $1+$ and also the charge of $PO4$ is $3-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $NH4+$ ion and one $PO43−$ ion are present in $(NH4)3PO4$ compound.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$Ca(ClO)2$ is composed of one $Ca2+$ ion and two $ClO−$ ions.

Explanation of Solution

In the given ionic compound $Ca(ClO)2$ , there are $Ca$ ion and $ClO$ ion present. Since the $Ca$ is group $IIA$ element, then the charge will be $2+$ and the charge of $ClO$ is $1-$ . So there will be two $ClO−$ ions for each of the $Ca2+$ ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Ca2+$ ion and one $ClO−$ ion are present in $Ca(ClO)2$ compound.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$NaCH3CO2$ is composed of one $Na+$ ion and one $CH3CO2−$ ion .

Explanation of Solution

In the given ionic compound $NaCH3CO2$ , there are $Na$ ion and $CH3CO2$ ion present. Since the Na is group $IA$ element, then the charge will be $1+$ and thereby the charge $CH3CO2$ must be $1-$ to balance the two $1+$ charge of sodium ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Na+$ ion and one $CH3CO2−$ ion are present in $NaCH3CO2$ compound.

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Answer 3

Textbook Question

Chapter 2, Problem 43PS

Give the formula and the number of each ion that makes up each of the following compounds:

(a) K₂S

(b) CoSO₄

(c) KMnO₄

(d) (NH₄)₃PO₄

(e) Ca(CIO)₂

(f)NaCH₃CO₂

(a)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$K2S$ is composed of one $K+$ ion and two $S2−$ ions.

Explanation of Solution

In the given ionic compound $K2S$ , there are $K$ ion and $S$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and thereby the charge of $S$ must be $2-$ to balance the $2+$ charge of two $K$ ions.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and two $S2−$ ions are present in $K2S$ compound.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$CoSO4$ is composed of one $Co2+$ ions and one $SO42−$ ion.

Explanation of Solution

In the given ionic compound $CoSO4$ , there are $Co$ ion and $SO4$ ion present. Since the charge of $SO4$ is $2-$ , then the charge of $Co$ must be $2+$ to balance the charge of the $SO4$ ions .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Co2+$ ion and one $SO42−$ ion are present in $CoSO4$ compound.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$KMnO4$ is composed of one $K+$ ion and one $MnO4−$ ion.

Explanation of Solution

In the given ionic compound $KMnO4$ , there are $K$ ion and $MnO4$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and also the charge of $MnO4$ is $1-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and one $MnO4−$ ion are present in $KMnO4$ compound.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$(NH4)3PO4$ is composed of three $NH4+$ ion and one $PO4$ ion.

Explanation of Solution

In the given ionic compound $(NH4)3PO4$ , there are $NH4$ ion and $PO4$ ion present. The charge of $NH4$ is $1+$ and also the charge of $PO4$ is $3-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $NH4+$ ion and one $PO43−$ ion are present in $(NH4)3PO4$ compound.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$Ca(ClO)2$ is composed of one $Ca2+$ ion and two $ClO−$ ions.

Explanation of Solution

In the given ionic compound $Ca(ClO)2$ , there are $Ca$ ion and $ClO$ ion present. Since the $Ca$ is group $IIA$ element, then the charge will be $2+$ and the charge of $ClO$ is $1-$ . So there will be two $ClO−$ ions for each of the $Ca2+$ ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Ca2+$ ion and one $ClO−$ ion are present in $Ca(ClO)2$ compound.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$NaCH3CO2$ is composed of one $Na+$ ion and one $CH3CO2−$ ion .

Explanation of Solution

In the given ionic compound $NaCH3CO2$ , there are $Na$ ion and $CH3CO2$ ion present. Since the Na is group $IA$ element, then the charge will be $1+$ and thereby the charge $CH3CO2$ must be $1-$ to balance the two $1+$ charge of sodium ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Na+$ ion and one $CH3CO2−$ ion are present in $NaCH3CO2$ compound.

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Answer 4

Textbook Question

Chapter 2, Problem 43PS

Give the formula and the number of each ion that makes up each of the following compounds:

(a) K₂S

(b) CoSO₄

(c) KMnO₄

(d) (NH₄)₃PO₄

(e) Ca(CIO)₂

(f)NaCH₃CO₂

(a)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$K2S$ is composed of one $K+$ ion and two $S2−$ ions.

Explanation of Solution

In the given ionic compound $K2S$ , there are $K$ ion and $S$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and thereby the charge of $S$ must be $2-$ to balance the $2+$ charge of two $K$ ions.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and two $S2−$ ions are present in $K2S$ compound.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$CoSO4$ is composed of one $Co2+$ ions and one $SO42−$ ion.

Explanation of Solution

In the given ionic compound $CoSO4$ , there are $Co$ ion and $SO4$ ion present. Since the charge of $SO4$ is $2-$ , then the charge of $Co$ must be $2+$ to balance the charge of the $SO4$ ions .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Co2+$ ion and one $SO42−$ ion are present in $CoSO4$ compound.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$KMnO4$ is composed of one $K+$ ion and one $MnO4−$ ion.

Explanation of Solution

In the given ionic compound $KMnO4$ , there are $K$ ion and $MnO4$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and also the charge of $MnO4$ is $1-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and one $MnO4−$ ion are present in $KMnO4$ compound.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$(NH4)3PO4$ is composed of three $NH4+$ ion and one $PO4$ ion.

Explanation of Solution

In the given ionic compound $(NH4)3PO4$ , there are $NH4$ ion and $PO4$ ion present. The charge of $NH4$ is $1+$ and also the charge of $PO4$ is $3-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $NH4+$ ion and one $PO43−$ ion are present in $(NH4)3PO4$ compound.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$Ca(ClO)2$ is composed of one $Ca2+$ ion and two $ClO−$ ions.

Explanation of Solution

In the given ionic compound $Ca(ClO)2$ , there are $Ca$ ion and $ClO$ ion present. Since the $Ca$ is group $IIA$ element, then the charge will be $2+$ and the charge of $ClO$ is $1-$ . So there will be two $ClO−$ ions for each of the $Ca2+$ ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Ca2+$ ion and one $ClO−$ ion are present in $Ca(ClO)2$ compound.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$NaCH3CO2$ is composed of one $Na+$ ion and one $CH3CO2−$ ion .

Explanation of Solution

In the given ionic compound $NaCH3CO2$ , there are $Na$ ion and $CH3CO2$ ion present. Since the Na is group $IA$ element, then the charge will be $1+$ and thereby the charge $CH3CO2$ must be $1-$ to balance the two $1+$ charge of sodium ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Na+$ ion and one $CH3CO2−$ ion are present in $NaCH3CO2$ compound.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(a)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$K2S$ is composed of one $K+$ ion and two $S2−$ ions.

Explanation of Solution

In the given ionic compound $K2S$ , there are $K$ ion and $S$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and thereby the charge of $S$ must be $2-$ to balance the $2+$ charge of two $K$ ions.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and two $S2−$ ions are present in $K2S$ compound.

(b)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$CoSO4$ is composed of one $Co2+$ ions and one $SO42−$ ion.

Explanation of Solution

In the given ionic compound $CoSO4$ , there are $Co$ ion and $SO4$ ion present. Since the charge of $SO4$ is $2-$ , then the charge of $Co$ must be $2+$ to balance the charge of the $SO4$ ions .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Co2+$ ion and one $SO42−$ ion are present in $CoSO4$ compound.

(c)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$KMnO4$ is composed of one $K+$ ion and one $MnO4−$ ion.

Explanation of Solution

In the given ionic compound $KMnO4$ , there are $K$ ion and $MnO4$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and also the charge of $MnO4$ is $1-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and one $MnO4−$ ion are present in $KMnO4$ compound.

(d)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$(NH4)3PO4$ is composed of three $NH4+$ ion and one $PO4$ ion.

Explanation of Solution

In the given ionic compound $(NH4)3PO4$ , there are $NH4$ ion and $PO4$ ion present. The charge of $NH4$ is $1+$ and also the charge of $PO4$ is $3-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $NH4+$ ion and one $PO43−$ ion are present in $(NH4)3PO4$ compound.

(e)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$Ca(ClO)2$ is composed of one $Ca2+$ ion and two $ClO−$ ions.

Explanation of Solution

In the given ionic compound $Ca(ClO)2$ , there are $Ca$ ion and $ClO$ ion present. Since the $Ca$ is group $IIA$ element, then the charge will be $2+$ and the charge of $ClO$ is $1-$ . So there will be two $ClO−$ ions for each of the $Ca2+$ ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Ca2+$ ion and one $ClO−$ ion are present in $Ca(ClO)2$ compound.

(f)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$NaCH3CO2$ is composed of one $Na+$ ion and one $CH3CO2−$ ion .

Explanation of Solution

In the given ionic compound $NaCH3CO2$ , there are $Na$ ion and $CH3CO2$ ion present. Since the Na is group $IA$ element, then the charge will be $1+$ and thereby the charge $CH3CO2$ must be $1-$ to balance the two $1+$ charge of sodium ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Na+$ ion and one $CH3CO2−$ ion are present in $NaCH3CO2$ compound.

Answer 8

(a)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$K2S$ is composed of one $K+$ ion and two $S2−$ ions.

Explanation of Solution

In the given ionic compound $K2S$ , there are $K$ ion and $S$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and thereby the charge of $S$ must be $2-$ to balance the $2+$ charge of two $K$ ions.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and two $S2−$ ions are present in $K2S$ compound.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer 13

Answer to Problem 43PS

$K2S$ is composed of one $K+$ ion and two $S2−$ ions.

Answer 14

Explanation of Solution

In the given ionic compound $K2S$ , there are $K$ ion and $S$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and thereby the charge of $S$ must be $2-$ to balance the $2+$ charge of two $K$ ions.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and two $S2−$ ions are present in $K2S$ compound.

Answer 15

(b)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$CoSO4$ is composed of one $Co2+$ ions and one $SO42−$ ion.

Explanation of Solution

In the given ionic compound $CoSO4$ , there are $Co$ ion and $SO4$ ion present. Since the charge of $SO4$ is $2-$ , then the charge of $Co$ must be $2+$ to balance the charge of the $SO4$ ions .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Co2+$ ion and one $SO42−$ ion are present in $CoSO4$ compound.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer 20

Answer to Problem 43PS

$CoSO4$ is composed of one $Co2+$ ions and one $SO42−$ ion.

Answer 21

Explanation of Solution

In the given ionic compound $CoSO4$ , there are $Co$ ion and $SO4$ ion present. Since the charge of $SO4$ is $2-$ , then the charge of $Co$ must be $2+$ to balance the charge of the $SO4$ ions .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Co2+$ ion and one $SO42−$ ion are present in $CoSO4$ compound.

Answer 22

(c)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$KMnO4$ is composed of one $K+$ ion and one $MnO4−$ ion.

Explanation of Solution

In the given ionic compound $KMnO4$ , there are $K$ ion and $MnO4$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and also the charge of $MnO4$ is $1-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and one $MnO4−$ ion are present in $KMnO4$ compound.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer 27

Answer to Problem 43PS

$KMnO4$ is composed of one $K+$ ion and one $MnO4−$ ion.

Answer 28

Explanation of Solution

In the given ionic compound $KMnO4$ , there are $K$ ion and $MnO4$ ion present. Since the potassium is group $IA$ element, then the charge will be $1+$ and also the charge of $MnO4$ is $1-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $K+$ ion and one $MnO4−$ ion are present in $KMnO4$ compound.

Answer 29

(d)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$(NH4)3PO4$ is composed of three $NH4+$ ion and one $PO4$ ion.

Explanation of Solution

In the given ionic compound $(NH4)3PO4$ , there are $NH4$ ion and $PO4$ ion present. The charge of $NH4$ is $1+$ and also the charge of $PO4$ is $3-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $NH4+$ ion and one $PO43−$ ion are present in $(NH4)3PO4$ compound.

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer 34

Answer to Problem 43PS

$(NH4)3PO4$ is composed of three $NH4+$ ion and one $PO4$ ion.

Answer 35

Explanation of Solution

In the given ionic compound $(NH4)3PO4$ , there are $NH4$ ion and $PO4$ ion present. The charge of $NH4$ is $1+$ and also the charge of $PO4$ is $3-$ .

The relative number of each ion is indicated in suffix of each ion.

That is,

One $NH4+$ ion and one $PO43−$ ion are present in $(NH4)3PO4$ compound.

Answer 36

(e)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$Ca(ClO)2$ is composed of one $Ca2+$ ion and two $ClO−$ ions.

Explanation of Solution

In the given ionic compound $Ca(ClO)2$ , there are $Ca$ ion and $ClO$ ion present. Since the $Ca$ is group $IIA$ element, then the charge will be $2+$ and the charge of $ClO$ is $1-$ . So there will be two $ClO−$ ions for each of the $Ca2+$ ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Ca2+$ ion and one $ClO−$ ion are present in $Ca(ClO)2$ compound.

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer 41

Answer to Problem 43PS

$Ca(ClO)2$ is composed of one $Ca2+$ ion and two $ClO−$ ions.

Answer 42

Explanation of Solution

In the given ionic compound $Ca(ClO)2$ , there are $Ca$ ion and $ClO$ ion present. Since the $Ca$ is group $IIA$ element, then the charge will be $2+$ and the charge of $ClO$ is $1-$ . So there will be two $ClO−$ ions for each of the $Ca2+$ ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Ca2+$ ion and one $ClO−$ ion are present in $Ca(ClO)2$ compound.

Answer 43

(f)

Expert Solution

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer to Problem 43PS

$NaCH3CO2$ is composed of one $Na+$ ion and one $CH3CO2−$ ion .

Explanation of Solution

In the given ionic compound $NaCH3CO2$ , there are $Na$ ion and $CH3CO2$ ion present. Since the Na is group $IA$ element, then the charge will be $1+$ and thereby the charge $CH3CO2$ must be $1-$ to balance the two $1+$ charge of sodium ion.

The relative number of each ion is indicated in suffix of each ion.

That is,

One $Na+$ ion and one $CH3CO2−$ ion are present in $NaCH3CO2$ compound.

Answer 44

(f)

Expert Solution

Answer 45

(f)

Expert Solution

Answer 46

Expert Solution

Answer 47

Interpretation Introduction

Interpretation:

For the given ionic compounds, the number and formula of constituted ions present are needed to be determined.

Concept introduction:

Ionic compounds are formed by electrostatic attraction between ions such as monoatomic ions and polyatomic ions; in which positively charged ions is known as cations and negatively charged ions are known as anions.

The sum of charges of ions present in an ionic compound is equals to net charge of the compound.

Answer 48

Answer to Problem 43PS

$NaCH3CO2$ is composed of one $Na+$ ion and one $CH3CO2−$ ion .

Answer 49

Explanation of Solution

In the given ionic compound $NaCH3CO2$ , there are $Na$ ion and $CH3CO2$ ion present. Since the Na is group $IA$ element, then the charge will be $1+$ and thereby the charge $CH3CO2$ must be $1-$ to balance the two $1+$ charge of sodium ion.