Introduction To Computing Systems
Introduction To Computing Systems
3rd Edition
ISBN: 9781260150537
Author: PATT, Yale N., Patel, Sanjay J.
Publisher: Mcgraw-hill,
Question
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Chapter 2, Problem 33E

a.

Program Plan Intro

OR operation:

  • OR function needs two inputs and produces one output.
  • It is also known as binary logical function.
  • If one of the inputs or both the inputs are “1”, then one-bit OR operation produces the output as “1”.
  • If both the inputs are “0”, then OR operation produces the output as “0”.
  • The following diagram depicts the one-bit OR operation,

Introduction To Computing Systems, Chapter 2, Problem 33E

b.

Explanation of Solution

101 OR 110:

The truth table for OR operation is as follows,

XYZ=X OR Y
000
011
101
111

Explanation:

  • In the above table, “X” and “Y” are the inputs, and “Z” is the output.
  • In the above table, when “X=0”, and “Y=0”, the output “Z” is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output “Z” is “1”, because one of the input “Y” contains the value “1”.
  • When “X=1”, and “Y=0”, the output “Z” is “1”, because one of the input “X” contains the value “1”...

c.

Explanation of Solution

11100000 OR 10110100:

The truth table for OR operation is as follows,

XYZ=X OR Y
000
011
101
111

Explanation:

  • In the above table, “X” and “Y” are the inputs, and “Z” is the output.
  • In the above table, when “X=0”, and “Y=0”, the output “Z” is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output “Z” is “1”, because one of the input “Y” contains the value “1”.
  • When “X=1”, and “Y=0”, the output “Z” is “1”, because one of the input “X” contains the value “1”...

d.

Explanation of Solution

00011111 OR 10110100:

The truth table for OR operation is as follows,

XYZ=X OR Y
000
011
101
111

Explanation:

  • In the above table, “X” and “Y” are the inputs, and “Z” is the output.
  • In the above table, when “X=0”, and “Y=0”, the output “Z” is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output “Z” is “1”, because one of the input “Y” contains the value “1”.
  • When “X=1”, and “Y=0”, the output “Z” is “1”, because one of the input “X” contains the value “1”...

e.

Explanation of Solution

(0101 OR 1100) OR 1101:

The truth table for OR operation is as follows,

XYZ=X OR Y
000
011
101
111

Explanation:

  • In the above table, “X” and “Y” are the inputs, and “Z” is the output.
  • In the above table, when “X=0”, and “Y=0”, the output “Z” is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output “Z” is “1”, because one of the input “Y” contains the value “1”.
  • When “X=1”, and “Y=0”, the output “Z” is “1”, because one of the input “X” contains the value “1”.
  • When “X=1”, and “Y=1”, the output “Z” is “1”, because both the inputs “X” and “Y” contains the value “1”...

f.

Explanation of Solution

0101 OR (1100 OR 1101):

The truth table for OR operation is as follows,

XYZ=X OR Y
000
011
101
111

Explanation:

  • In the above table, “X” and “Y” are the inputs, and “Z” is the output.
  • In the above table, when “X=0”, and “Y=0”, the output “Z” is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output “Z” is “1”, because one of the input “Y” contains the value “1”.
  • When “X=1”, and “Y=0”, the output “Z” is “1”, because one of the input “X” contains the value “1”.
  • When “X=1”, and “Y=1”, the output “Z” is “1”, because both the inputs “X” and “Y” contains the value “1”...

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