Chapter 2, Problem 2.89FU

(a)

Interpretation Introduction

Interpretation: An equality and two conversion factors for Person G’s serum iron level should be written.

Concept Introduction: In humans, the normal range for serum iron is 80 to 160 mcg/dL.The low value of iron from this standard value indicates the deficiency of iron that is cause of anaemia.

Answer to Problem 2.89FU

Equality must be: 42 mcg of iron = 1 dL of blood

Conversion factors are:

  $\frac{\text{42 mcg iron}}{\text{1 dL blood}}\text{= }\frac{\text{1 dL blood}}{\text{42 mcg iron}}$

Explanation of Solution

During the doctor visit of Person G; he complained about feeling tired. The blood test showed the level of iron indicates 42 mcg/dL that is low compare to permissible value of iron blood. It indicates the iron deficiency in Person G that may cause anaemia.

Thus, the equality must be: 42 mcg of iron = 1 dL of blood

An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

So, the conversion factors are:

  $\frac{\text{42 mcg iron}}{\text{1 dL blood}}\text{= }\frac{\text{1 dL blood}}{\text{42 mcg iron}}$

(b)

Interpretation Introduction

Interpretation: The micrograms of iron present in the 8.0 mL of sample of Person G’s blood should be calculated.

Concept Introduction:An arithmetical multiplier which is used for converting a quantity expressed in one unit into another equivalent set of units is said to be conversion factor.

Answer to Problem 2.89FU

3.4 mcg

Explanation of Solution

Given Information:

42 mcg of iron = 1 dL of blood

Calculation:

  $\begin{array}{l}\frac{\text{42 mcg iron}}{\text{1 dL blood}}\text{x }\frac{\text{1 dL blood}}{\text{0}\text{.1 L of blood }}\text{x}\frac{\text{1 Lblood}}{\text{1000 mL blood}}{\text{= 42 x 10}}^{\text{-2}}\text{ mcg / mL}\\ \\ \frac{{\text{42 x 10}}^{\text{-2}}\text{ mcg}}{\text{1 mL}}\text{ x }\frac{\text{8 mL}}{\text{1mL}}\text{ = 3}\text{.4 mcg}\end{array}$

Thus, the iron level in Person G’s blood was found 42 mcg/dL hence in 8 mL; it will be 3.4 mcg.