(a)
Interpretation:
Methyl cation would be attracted to the given ions or molecule and type of the intermolecular force involved in the attraction is to be determined.
Concept introduction:
Oppositely charged ions are attracted to each other due to strong intermolecular attractions. Ionic compounds are composed of oppositely charged particles held by the electrostatic force of attraction or ion-ion attractions. Ion-ion interactions are the strongest intermolecular interactions because ions have very high concentrations of position and negative charge. Covalent compounds containing an electronegative atom having lone pair of electrons can attract cations.

Answer to Problem 2.43P
Water will be attracted to methyl cation (CH3+).
Explanation of Solution
The methyl cation is CH3+. It is a positively charged ion and thus, it can be attracted to the negatively charged ion or the molecule having an atom with a lone pair of electrons. Water is a polar molecule. There are two lone pairs of electrons on the oxygen atom in water. Thus, water is attracted to CH3+. The dipole-dipole intermolecular forces are involved in the attraction.
Polar molecules are attracted to cation and anion due to electrostatic attraction between them.
(b)
Interpretation:
Methyl cation would be attracted to the given ions or molecules and the type of the intermolecular force involved in the attraction is to be determined.
Concept introduction:
Oppositely charged ions are attracted to each other due to strong intermolecular attractions. Ionic compounds are composed of oppositely charged particles held by the electrostatic force of attraction or ion-ion attractions. Ion-ion interactions are the strongest intermolecular interactions because ions have very high concentrations of position and negative charge. Covalent compounds containing an electronegative atom having lone pair of electrons can attract cations.

Answer to Problem 2.43P
Sodium ion (Na+) will not be attracted to methyl cation.
Explanation of Solution
The methyl cation is CH3+. It is a positively charged ion and thus, it can be attracted to the negatively charged ion or the molecule having an atom with a lone pair of electrons.
Na+ is the cation and this will not be attracted to methyl cation since the charges of both the ions are equal. Thus, Na+ will not be attracted to CH3+.
Cation must have the anion to form a polar covalent bond.
(c)
Interpretation:
Methyl cation would be attracted to the given ions or molecule and type of the intermolecular force involved in the attraction is to be determined.
Concept introduction:
Oppositely charged ions are attracted to each other due to strong intermolecular attractions. Ionic compounds are composed of oppositely charged particles held by the electrostatic force of attraction or ion-ion attractions. Ion-ion interactions are the strongest intermolecular interactions because ions have very high concentrations of position and negative charge. Covalent compounds containing an electronegative atom having lone pair of electrons can attract cations.

Answer to Problem 2.43P
Chlorine ion (Cl−) will be attracted to methyl cation CH3+.
Explanation of Solution
The methyl cation undergoes attractions with negatively charged ions with polar compounds. Cl− is an anion and they attracted to methyl cation CH3+. The ion-dipole intermolecular forces are involved in the attraction.
In polar molecules, cations and anions are attracted to each other due to electrostatic attraction between them.
(d)
Interpretation:
Methyl cation would be attracted to the given ions or molecule and type of the intermolecular force involved in the attraction is to be determined.
Concept introduction:
Oppositely charged ions are attracted to each other due to strong intermolecular attractions. Ionic compounds are composed of oppositely charged particles held by the electrostatic force of attraction or ion-ion attractions. Ion-ion interactions are the strongest intermolecular interactions because ions have very high concentrations of position and negative charge. Covalent compounds containing an electronegative atom having lone pair of electrons can attract cations.

Answer to Problem 2.43P
Fluorine ion (F-) will be attracted to methyl cation CH3+.
Explanation of Solution
The methyl cation is CH3+. It is a positively charged ion and thus, it can be attracted to the negatively charged ion or the molecule having an atom with a lone pair of electrons. Fluoride ion, F-, is a negatively charged ion. Negatively charged ions are attracted strongly to positively charged ions through ion-ion attractions. Thus, F- will be attracted to CH3+ cation.
In polar molecules, cations and anions are attracted to each other due to electrostatic attraction between them.
(e)
Interpretation:
Methyl cations would be attracted to the given ions or molecule and type of the intermolecular force involved in the attraction is to be determined.
Concept introduction:
Oppositely charged ions are attracted to each other due to strong intermolecular attractions. Ionic compounds are composed of oppositely charged particles held by the electrostatic force of attraction or ion-ion attractions. Ion-ion interactions are the strongest intermolecular interactions because ions have very high concentrations of position and negative charge. Covalent compounds containing an electronegative atom having lone pair of electrons can attract cations.

Answer to Problem 2.43P
Formaldehyde (H2C=O) will be attracted to methyl cation (CH3+).
Explanation of Solution
The methyl cation is CH3+. It is a positively charged ion and thus, it can be attracted to the negatively charged ion or the molecule having an atom with a lone pair of electrons.
The given molecule, formaldehyde, (H2C=O) is a polar molecule due to the presence of the oxygen and carbon polar bond (C=O) and this will be attracted to methyl cation (CH3+). The dipole-dipole intermolecular forces are involved in the attraction.
Polar molecules are attracted to cation and anion due to electrostatic attraction between them.
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Chapter 2 Solutions
ORGANIC CHEM PRINC & MECH (BUNDLE)
- The vapor pressure of dichloromethane at 20.0 °C is 58.0 kPa and its enthalpy of vaporization is 32.7 kJ/mol. Estimate the temperature at which its vapor pressure is 66.0 kPa.arrow_forwardDraw the structure of A, the minor E1 product of the reaction. Cl Skip Part Check F1 esc CH_CH OH, D 3 2 Click and drag to start drawing a structure. 80 R3 F4 F2 F3 @ 2 # $ 4 3 Q W 95 % KO 5 F6 A F7 × G ☐ Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ►II A A F8 F9 F10 FL 6 7 88 & * 8 9 LLI E R T Y U A S D lock LL F G H 0 P J K L Z X C V B N M 9 Harrow_forwardFrom the choices given, which two substances have the same crystal structure? (Select both) Group of answer choices ZnS (zincblende) Diamond TiO2 (rutile) ZnS (wurtzite)arrow_forward
- Potassium (K) blends with germanium (Ge) to form a Zintl phase with a chemical formula of K4Ge4. Which of the following elements would you expect potassium to blend with to form an alloy? Electronegativities: As (2.0), Cl (3.0), Ge (1.8), K (0.8), S (2.5), Ti (1.5) Group of answer choices Arsenic (As) Sulfur (S) Chlorine (Cl) Titanium (Ti)arrow_forwardConsider two elements, X and Z. Both have cubic-based unit cells with the same edge lengths. X has a bcc unit cell while Z has a fcc unit cell. Which of the following statements is TRUE? Group of answer choices Z has a larger density than X X has more particles in its unit cell than Z does X has a larger density than Z Z has a larger unit cell volume than Xarrow_forwardHow many particles does a face-centered cubic (fcc) unit cell contain? Group of answer choices 2 14 8 4arrow_forward
- V Highlight all of the carbon atoms that have at least one beta (B) hydrogen, using red for one ẞ hydrogen, blue for two ẞ hydrogens, and green for three ẞ hydrogens. If none of the carbon atoms have ẞ hydrogens, check the box underneath the molecule. ED X None of the carbon atoms have ẞ hydrogens. Explanation esc 2 Check * F1 F2 1 2 80 # 3 Q W tab A caps lock shift fn control F3 N S option O 694 $ F4 F5 F6 005 % E R D F LL 6 olo 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A DII F7 F8 87 & * 8 T Y U G H 4 F9 F10 ( 9 0 E F11 F12 உ J K L + || X C V B N M H H command option commandarrow_forwardConsider the reaction below and answer the following questions. Part 1 of 4 Br NaOCH2CH3 Identify the mechanisms involved. Check all that apply. SN 1 SN 2 E1 E2 None of the above Part 2 of 4 Skip Part Check esc F1 F2 lock 1 2 Q W A S #3 80 F3 F4 F5 F6 Save For © 2025 McGraw Hill LLC. All Rights Reserved. Terms ˇˇ % & 4 5 6 89 7 IK A 分 བ F7 F8 F9 F * E R T Y U 8 9 D F G H K V B N M 0 Oarrow_forwardWhat kind of holes are not generated when solid-state particles adopt a close packing pattern? Group of answer choices tetrahedral cubic octahedral None of the other choices are correctarrow_forward
- For the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. 田 Major Product: Check ☐ + I Na OH esc F1 F2 2 1 @ 2 Q W tab A caps lock S #3 80 F3 69 4 σ F4 % 95 S Click and drag to sta drawing a structure mm Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use GO DII F5 F6 F7 F8 F9 F10 6 CO 89 & 7 LU E R T Y U 8* 9 0 D F G H J K L Z X C V B N M 36arrow_forwardProblem 7 of 10 Draw the major product of this reaction. Ignore inorganic byproducts. S' S 1. BuLi 2. ethylene oxide (C2H4O) Select to Draw a Submitarrow_forwardFeedback (4/10) 30% Retry Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the reactant and missing intermediates involved in this reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Incorrect, 6 attempts remaining :0: Draw the Reactant H H3CO H- HIO: Ö-CH3 CH3OH2* protonation H. a H (+) H Ο CH3OH2 O: H3C protonation CH3OH deprotonation > CH3OH nucleophilic addition H. HO 0:0 Draw Intermediate a Xarrow_forward
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