Chapter 2, Problem 2.34P

Interpretation Introduction

(a)

Interpretation: The product of the reaction between ${\left({\text{CH}}_{\text{3}}{\text{CH}}_2\right)}_3\text{N:}$ (Lewis base) and given Lewis acid is to be drawn.

Concept introduction: A Lewis acid-base reaction takes place between an electron rich species and an electron deficient species. In such reactions, a Lewis base (electron rich species) donates electron pair to a Lewis acid (electron deficient species) and forms a new bond.

Interpretation Introduction

(b)

Interpretation: The product of reaction between ${\left({\text{CH}}_{\text{3}}{\text{CH}}_2\right)}_3\text{N:}$ (Lewis base) and given Lewis acid is to be drawn.

Concept introduction: A Lewis acid-base reaction takes place between an electron rich species and an electron deficient species. In such reactions, a Lewis base (electron rich species) donates electron pair to a Lewis acid (electron deficient species) and forms a new bond.

Interpretation Introduction

(c)

Interpretation: The product of the reaction between ${\left({\text{CH}}_{\text{3}}{\text{CH}}_2\right)}_3\text{N:}$ (Lewis base) and given Lewis acid is to be drawn.

Concept introduction: A Lewis acid-base reaction takes place between an electron rich species and an electron deficient species. In such reactions, a Lewis base (electron rich species) donates electron pair to a Lewis acid (electron deficient species) and forms a new bond.