Principles of Foundation Engineering, SI Edition
8th Edition
ISBN: 9781305446298
Author: Braja M. Das
Publisher: Cengage Learning US
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Chapter 2, Problem 2.23P
To determine
Calculate the major principal stress at failure.
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A clay specimen with drained shear strength parameters of c'=5 kPa and Φ=320 is consolidated under all around pressure of 140 kPa.The specimen was then loaded axially to failure under undrained condition and failed when the principal stress diffrences reached 60 kPa.Calculate the pore pressure(u) and the pore pressure coefficient D(=A*B=Δu/Δσv) of the clay.
A triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure were determined to be 6100 psf and 4600 psf, respectively.
a. Determine the angle of internal friction of the sand?
b. Determine the angle of the failure plane?
c. Determine the maximum principal stress?
Please answer this asap. For upvote. Thank you very much
A consolidated-drained triaxial test on a normally consolidated clay yielded a friction angle, Φ', of 28°. If the all-around confining pressure during the test was 140 kN/m2, what was the major principal stress at failure?
Chapter 2 Solutions
Principles of Foundation Engineering, SI Edition
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - For a normally consolidated soil, the following is...Ch. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27P
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- A consolidated undrained triaxial test was performed on a normally consolidated clay with a critical state friction angle of 230. After an initial isotropic consolidation at a cell pressure of 50 kPa, drainage was turned off, the cell pressure was increased to 85 kPa, and the sample was loaded to ultimate conditions. A pore pressure of 55 kPa was measured at ultimate state. What value of major principal total stress was measured at the ultimate state?arrow_forwardIn an Oedometer apparatus, a specimen of fully saturated clay has been consolidated under a vertical pressure of 50 kN/m2 and is presently at equilibrium. The effective stress and pore water pressure immediately on increasing the vertical stress to 150 kN/m2, respectively are...?arrow_forwardA consolidated-undrained test determines that the shear strength of a normally consolidated clay is given by τf = σ’tan 27o. The confining pressure is 150 kPa, and deviator stress at failure is 120 kPa.• Find the consolidated-undrained friction angle• Pore water pressure developed in the specimen at failureFinal answer should be in 3 decimal places.arrow_forward
- 5- The shear strength of a normally consolidated clay can be given by the equation tf o'tan 27°. Following are the results of a consolidated-undrained test on the clay. • Chamber-confining pressure = 3,130 lb/ft² Deviator stress at failure = 2,510 lb/ft² a) Determine the consolidated-undrained friction angle b) Pore-water pressure developed in the specimen at failurearrow_forward[Shear Strength,. speciments of a fully saturdated clay, the following results were obtained at failure. In a series of unconsolidated-undrained triaxial tests on Major Principal Stress Minor Principal Stress (kPa) 200 422 618 400 600 820 Calculate the following: a. Cohesion b. Angle of internal frictionarrow_forwardThe shear strength of a normally consolidated clay can be given by theequation (tau)f=(sigma prime)tan(21). The results of a consolidated-undrained test on theclay areChamber confining pressure 5 225 kN/m2Deviator stress at failure 5 112 kN/m2Determine:a. The consolidated-undrained (total stress) friction angleb. Pore water pressure developed in the specimen at failurearrow_forward
- In a triaxial test, a specimen of saturated [normally consolidated] clay was consolidated under a chamber confining pressure of 80 kPa. The axial stress on the specimen was then increased through the allowing the drainage from the specimen. The specimen fails when 120 kPa. The pore water pressure at the time was 50 kPa. What is the consolidated undrained friction angle [phi]?arrow_forwardA consolidated-undrained test on a normally consolidate clay yield the following results: Confining Pressure 167 KPa; Deviator Stress = 184 KPa; Pore Pressure = 74 KPa. Calculate the normal stress at the failure plane at drained condition in KPa.arrow_forwardA sample of normally consolidated clay was subjected to a consolidated undrained triaxial compression test that was carried out until the specimen failed at a deviator stress of 50 kN/m2. The pore water pressure at failure was recorded to be 20 kN/m2 and confining pressure of 50 kN/m2 was used in the test. Determine the consolidated undrained friction angle.arrow_forward
- • In consolidated-drained triaxial test on a normally consolidated clay, the specimen failed at a deviator stress of 124 KN/sq.m. If the effective stress friction angle is known to be 31°, what was the effective confining pressure at failure?arrow_forwardIn a consolidated drained triaxial test, a specimen of clay tails at a cell pressure of 100KN/m?. The effective shear strength parameters are c' = 20KN/m? and o' = 300 Determine the major principal stress?. kN/m?arrow_forwardProb.5. Samples of a dry sand are to be tested in triaxial and direct shear test. In the triaxial test the specimen fails when the major and minor principal stress are 960 kN/m² and 260 kN/m² respectively. What shear strength would be expected in direct shear test, when normal stress is 230 kN/m²?arrow_forward
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