EBK CHEMISTRY: ATOMS FIRST
EBK CHEMISTRY: ATOMS FIRST
3rd Edition
ISBN: 8220103675505
Author: Burdge
Publisher: YUZU
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 2, Problem 2.22QP

The following radioactive isotopes are used in medicine for things such as imaging organs, studying blood circulation, and treating cancer. Give the number of neutrons present in each isotope: 198Au, 47Ca, 60Co, 18F, 125I, 131I, 42K, 43K, 24Na, 32P, 85Sr, 99Tc.

Expert Solution & Answer
Check Mark
Interpretation Introduction

Interpretation:

The total number of neutrons present in the given set of radioactive isotopes needs to be given.

Concept introduction:

The total number of protons in an atom is said to be its atomic number.  By using the total number of protons and neutrons all the atoms can be identified.  Atomic number is denoted by “Z”.  Atomic number is a characteristic of each and every atom in an element.

The total number of neutrons and protons of an atom is said to be its mass number.  By using the total number of protons and neutrons all the atoms can be identified.  Mass number is denoted by “A”.

Atomic number does not change for atoms present in an element while mass number can change due to difference in number of neutrons.  These are known as isotopes.

EBK CHEMISTRY: ATOMS FIRST, Chapter 2, Problem 2.22QP

Total number of neutrons present in an atom can be found out of finding the difference between mass number and atomic number.

mass number (A) = number of protons (Z) + number of neutrons

To Determine: The number of neutrons present in the given radioactive isotopes.

Answer to Problem 2.22QP

The number of neutrons in 198Au is 119

The number of neutrons in 47Ca is 27

The number of neutrons in 60Co is 33

The number of neutrons in 18F is 9

The number of neutrons in 125I is 72

The number of neutrons in 131I is 78

The number of neutrons in 42K is 23

The number of neutrons in 43K is 24

The number of neutrons in 24Na is 13

The number of neutrons in 32P is 17

The number of neutrons in 85Sr is 47

The number of neutrons in 99Tc is 56

Explanation of Solution

To determine the number of neutrons present in 198Au

Atom of the element given= gold

Mass number (A)= 198

Total number of protons (Z)=79

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =198 - 79 =119

Therefore, the mass number of 198Au is 119.

To determine the number of neutrons present in 47Ca

Atom of the element given= calcium

Mass number (A)= 47

Total number of protons (Z)=20

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =47 - 20 =27

Therefore, the mass number of 47Ca is 27.

To determine the number of neutrons present in 60Co

Atom of the element given= cobalt

Mass number (A)= 60

Total number of protons (Z)=27

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =60 - 27 =33

Therefore, the mass number of 60Co is 33.

To determine the number of neutrons present in 18F

Atom of the element given= fluorine

Mass number (A)= 18

Total number of protons (Z)=9

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =18 - 9 =9

Therefore, the mass number of 18F is 9.

To determine the number of neutrons present in 125I

Atom of the element given= iodine

Mass number (A)= 125

Total number of protons (Z)=53

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =125 - 53 =72

Therefore, the mass number of 125I is 72.

To determine the number of neutrons present in 131I

Atom of the element given= iodine

Mass number (A)= 131

Total number of protons (Z)=53

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =131 - 53 =78

Therefore, the mass number of 131I is 78.

To determine the number of neutrons present in 42K

Atom of the element given= potassium

Mass number (A)= 42

Total number of protons (Z)=19

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =42 - 19 =23

Therefore, the mass number of 42K is 23.

To determine the number of neutrons present in 43K

Atom of the element given= potassium

Mass number (A)= 43

Total number of protons (Z)=19

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =43 - 19 =24

Therefore, the mass number of 43K is 24.

To determine the number of neutrons present in 24Na

Atom of the element given= sodium

Mass number (A)= 24

Total number of protons (Z)=11

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =24 - 11 =13

Therefore, the mass number of 24Na is 13.

To determine the number of neutrons present in 32P

Atom of the element given= phosphorous

Mass number (A)= 32

Total number of protons (Z)=15

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =32 - 15 =17

Therefore, the mass number of 32P is 17.

To determine the number of neutrons present in 85Sr

Atom of the element given= strontium

Mass number (A)= 85

Total number of protons (Z)=38

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =85 - 38 =47

Therefore, the mass number of 85Sr is 47.

To determine the number of neutrons present in 99Tc

Atom of the element given= technitium

Mass number (A)= 99

Total number of protons (Z)=43

The number of neutrons in any atom can be got by finding the difference between mass number and total number of protons.

Mass number (A) = Total number of protons (Z) + Total number of neutronsTotal number of neutrons=  Mass number (A) - Total number of protons (Z) =99 - 43 =56

Therefore, the mass number of 99Tc is 56.

Conclusion

The number of neutrons in the given set of radioisotopes was determined.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Chapter 2 Solutions

EBK CHEMISTRY: ATOMS FIRST

Ch. 2.5 - The average atomic mass of nitrogen is 14.0067....Ch. 2.5 - Prob. 2PPCCh. 2.5 - Boron has two naturally occurring isotopes, 10B...Ch. 2.5 - The two naturally occurring isotopes of antimony,...Ch. 2.6 - Prob. 2.6.1SRCh. 2.6 - Prob. 2.6.2SRCh. 2.7 - Calcium is the most abundant metal in the human...Ch. 2.7 - Prob. 3PPACh. 2.7 - Calculate (a) the number of atoms in 1.05 106...Ch. 2.7 - Prob. 3PPCCh. 2.7 - Prob. 2.4WECh. 2.7 - Prob. 4PPACh. 2.7 - Prob. 4PPBCh. 2.7 - Prob. 4PPCCh. 2.7 - Prob. 2.5WECh. 2.7 - Prob. 5PPACh. 2.7 - Prob. 5PPBCh. 2.7 - Prob. 5PPCCh. 2.7 - Prob. 2.7.1SRCh. 2.7 - Prob. 2.7.2SRCh. 2.7 - Prob. 2.7.3SRCh. 2 - Define the terms atom and element.Ch. 2 - Use a familiar macroscopic example as an analogy...Ch. 2 - Prob. 2.3QPCh. 2 - Prob. 2.4QPCh. 2 - Prob. 2.5QPCh. 2 - Prob. 2.6QPCh. 2 - Describe the experimental basis for believing that...Ch. 2 - Prob. 2.8QPCh. 2 - Prob. 2.9QPCh. 2 - Prob. 2.10QPCh. 2 - Prob. 2.11QPCh. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Prob. 2.18QPCh. 2 - Prob. 2.19QPCh. 2 - Determine the mass number of (a) a beryllium atom...Ch. 2 - Prob. 2.21QPCh. 2 - The following radioactive isotopes are used in...Ch. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - In each pair of isotopes shown, indicate which one...Ch. 2 - What is the mass (in amu) of a carbon-12 atom? Why...Ch. 2 - Prob. 2.32QPCh. 2 - What information would you need to calculate the...Ch. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QPCh. 2 - Prob. 2.37QPCh. 2 - The element rubidium has two naturally occurring...Ch. 2 - Prob. 2.39QPCh. 2 - Prob. 2.40QPCh. 2 - Prob. 2.41QPCh. 2 - Give two examples of each of the following: (a)...Ch. 2 - Prob. 2.43QPCh. 2 - Prob. 2.44QPCh. 2 - Describe the changes in properties (from metals to...Ch. 2 - Consult the WebElements Periodic Table of the...Ch. 2 - Group the following elements in pairs that you...Ch. 2 - Prob. 2.48QPCh. 2 - Prob. 2.49QPCh. 2 - Prob. 2.50QPCh. 2 - Prob. 2.51QPCh. 2 - Prob. 2.52QPCh. 2 - Prob. 2.53QPCh. 2 - Prob. 2.54QPCh. 2 - Prob. 2.55QPCh. 2 - Prob. 2.56QPCh. 2 - Prob. 2.57QPCh. 2 - Prob. 2.58QPCh. 2 - Prob. 2.59QPCh. 2 - Prob. 2.60QPCh. 2 - Prob. 2.61QPCh. 2 - Prob. 2.62QPCh. 2 - Prob. 2.63QPCh. 2 - Prob. 2.64QPCh. 2 - The element francium (Fr) was the last element of...Ch. 2 - Prob. 2.66QPCh. 2 - Prob. 2.67QPCh. 2 - Prob. 2.68QPCh. 2 - Prob. 2.69QPCh. 2 - Prob. 2.70QPCh. 2 - Discuss the significance of assigning an atomic...Ch. 2 - Prob. 2.72QPCh. 2 - Prob. 2.73QPCh. 2 - Prob. 2.74QPCh. 2 - Prob. 2.75QPCh. 2 - One atom of a particular element with only one...Ch. 2 - Identify each of the following elements: (a) a...Ch. 2 - Prob. 2.78QPCh. 2 - Prob. 2.79QPCh. 2 - Prob. 2.80QPCh. 2 - Prob. 2.81QPCh. 2 - Prob. 2.82QPCh. 2 - Prob. 2.83QPCh. 2 - Prob. 2.84QP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
World of Chemistry
Chemistry
ISBN:9780618562763
Author:Steven S. Zumdahl
Publisher:Houghton Mifflin College Div
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Introductory Chemistry For Today
Chemistry
ISBN:9781285644561
Author:Seager
Publisher:Cengage
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Text book image
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:9781559539418
Author:Angelica Stacy
Publisher:MAC HIGHER
Atomic Number, Atomic Mass, and the Atomic Structure | How to Pass ChemistryThe Nucleus: Crash Course Chemistry #1; Author: Crash Course;https://www.youtube.com/watch?v=FSyAehMdpyI;License: Standard YouTube License, CC-BY