Chapter 2, Problem 2.1P

To determine

To find:

The output of the following sequence of statements and expressions, and verify them.

pvec = 3:2:10

pvec(2) = 15

pvec(7) = 33

pvec([2:4 7])

linspace(5, 11, 3)

logspace(2, 4, 3)

Answer to Problem 2.1P

Solution:

The output of the following sequence of statements and expressions:

“pvec = 3:2:10”, “pvec(2) = 15” “pvec(7) = 33”, “pvec([2:4 7])”, “linspace(5, 11, 3)”, and “logspace(2, 4, 3)” are “pvec = 3 5 7 9”, “pvec = 3 15 7 9 0 0 33”, “ans = 15 7 9 33”, “ans = 5 8 11”, and “ans = 100 1000 10000” respectively.

Explanation of Solution

Consider the following statement,

pvec = 3:2:10

The statement will generate the sequence of number from 3 to 10 in increment of 2.

So, the output is “pvec = 3 5 7 9”.

Consider the following statement,

pvec(2) = 15

The expression replaces the second term of the sequence of “pvec” with “15” and then displays sequence.

So, the output is “pvec = 3 15 7 9”.

Consider the following statement,

pvec(7) = 33

The expression replaces the seventh term of the sequence of “pvec” with “33” and then displays sequence. Since, the values of the 5^th and the 6^th terms are not allotted, so these terms are allotted with zero.

So, the output is “pvec = 3 15 7 9 0 0 33”.

Consider the following statement,

pvec([2:4 7])

The expression displays the values placed 2^nd to 4^th and then 7^th from the sequence.

So, the output is “ans = 15 7 9 33”.

Consider the following statement,

linspace(5, 11, 3)

The expression generates three values that are equally spaced from 5 to 11.

So, the output is “ans = 5 8 11”.

And, consider the following statement,

logspace(2, 4, 3)

The expression generates three values that are equal to ${10}^n$, here $n=2,3,4$.

So, the output is “ans = 100 1000 10000”.

The

MATLAB Code:

clc

clear all

close all

pvec = 3:2:10

% Define the instruction to generate the sequence of number from 3 to 10 in increment of 2.

pvec(2) = 15

% Define the instruction in which the expression replaces the second term of the sequence of “pvec” with “15” and then displays sequence.

pvec(7) = 33

% Define the instruction in which the expression replaces the seventh term of the sequence of “pvec” with “33” and then displays sequence. Since, the values of the 5^th and the 6^th terms are not allotted, so these terms are allotted with zero.

pvec([2:4 7])

% Define the instruction in which the expression displays the values placed 2^nd to 4^th and then 7^th from the sequence.

linspace(5, 11, 3)

% Define the instruction in which the expression generates three values that are equally spaced from 5 to 11.

logspace(2, 4, 3)

% Define the instruction in which the expression generates three values that are equal to 10^n, here n = 2, 3, 4.

Save the MATLAB script with name, chapter2_54793_2_1P.m in the current folder. Execute the script by typing the script name at the command window to find the answer of the given following sequence of statements and expressions.

Result:

Therefore, the output of the following sequence of statements and expressions:

“pvec = 3:2:10”, “pvec(2) = 15” “pvec(7) = 33”, “pvec([2:4 7])”, “linspace(5, 11, 3)”, and “logspace(2, 4, 3)” are “pvec = 3 5 7 9”, “pvec = 3 15 7 9 0 0 33”, “ans = 15 7 9 33”, “ans = 5 8 11”, and “ans = 100 1000 10000” respectively.