ELEM PRINC CHEM (LL) W/EBOOK
ELEM PRINC CHEM (LL) W/EBOOK
4th Edition
ISBN: 9781119846772
Author: FELDER
Publisher: WILEY
Question
Book Icon
Chapter 2, Problem 2.1P
Interpretation Introduction

(a)

Interpretation:

: To convert 2 wk to microseconds.

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol. d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In two weeks there are 1.2×1012μs.

Explanation of Solution

In one week there are seven days and in one day there are twenty-four hours. In one hour there are sixty minutes and in one minute there are sixty seconds. In one second there are 106 microseconds.

Convert week to microseconds as follows:

2wk=(2wk)(7d1wk)(24h1d)(60min1h)(60s1min)(106μs1s)=1.2×1012μs.

Interpretation Introduction

(b)

Interpretation:

To convert 38.1 ft/s to kilometers/h.

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In 38.1 fts there are 41.8 kmh.

Explanation of Solution

In one day there are twenty-four hours and in one hour there are sixty minutes.

In one pound there are 0.453593 kg and in one feet there are 0.3048 m. Convert meter per day into kilogram to feet per minute into pound as follows:

554m4daykg=(554m4daykg)(1day24 h)(1h60min)(0.453593kg1lbm)(1ft4(0.3048 m)4)=20.2ft4minlbm.

Interpretation Introduction

(c)

Interpretation:

To convert 554 m4/(day.kg) to ft4/(min.lbm ).

Concept introduction:

The international system of unit (SI units):

Day is represented by the symbol d
Week is represented by the symbol wk
Hour is represented by the symbol h
Minutes is represented by the symbol min
Seconds is represented by the symbol s
Microsecond is represented by the symbol µs
Meter is represented by the symbol m
Feet is represented by the symbol ft
Kilometer is represented by the symbol km
Kilogram is represented by the symbol kg
Pound is represented by the symbol lb

Expert Solution
Check Mark

Answer to Problem 2.1P

In 554m4daykg there are 20.2ft4minlbm.

Explanation of Solution

In one day there are twenty-four hours and in one hour there are sixty minutes.

In one pound there are 0.453593 kg and in one feet there are 0.3048 m. Convert meter per day into kilogram to feet per minute into pound as follows:

554m4daykg=(554m4daykg)(1day24 h)(1h60min)(0.453593kg1lbm)(1ft4(0.3048m)4)=20.2ft4minlbm.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
01:49
Knowledge Booster
Background pattern image
Recommended textbooks for you
Text book image
Introduction to Chemical Engineering Thermodynami...
Chemical Engineering
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:McGraw-Hill Education
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemical Engineering
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Text book image
Elements of Chemical Reaction Engineering (5th Ed...
Chemical Engineering
ISBN:9780133887518
Author:H. Scott Fogler
Publisher:Prentice Hall
Text book image
Process Dynamics and Control, 4e
Chemical Engineering
ISBN:9781119285915
Author:Seborg
Publisher:WILEY
Text book image
Industrial Plastics: Theory and Applications
Chemical Engineering
ISBN:9781285061238
Author:Lokensgard, Erik
Publisher:Delmar Cengage Learning
Text book image
Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:9780072848236
Author:Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:McGraw-Hill Companies, The