General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 2, Problem 2.14QP
Interpretation Introduction

Interpretation:

The number of protons, neutrons and electrons in given species has to be identified.

Concept Introduction:

Mass number(A): Mass number of an element is sum of protons and neutrons of the atom.

A= Number of protons(P) + Number of neutrons(n)

Consider an element X with atomic number and mass number,

ZAX

Where,

A is mass number and Z is atomic number ( number of proton or electron)

Expert Solution & Answer
Check Mark

Answer to Problem 2.14QP

Number of proton, neutron and electrons for given species are given as follows.

IsotopesN715S1633Cu2963Sr3884Ba56130W74186Hg80202
No. of Protons7162938567480
No. of Neutrons817344674112122
No. of Electrons7162938567480

Explanation of Solution

For N715, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  =N715Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 7A (mass number) = Number of protons (P) + Number of  neutrons (N)                      15 = 7 + n n=8

For S1633, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  =S1633Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 16A (mass number) = Number of protons (P) + Number of  neutrons (N)                      33 = 16 + n n=17

For Cu2963, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  = Cu2963Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 29A (mass number) = Number of protons (P) + Number of  neutrons (N)                      63 = 29 + n n=34

For Sr3884, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  = Sr3884Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 38A (mass number) = Number of protons (P) + Number of  neutrons (N)                      84 = 38 + n n= 46

For Ba56130, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  =Ba56130Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 56A (mass number) = Number of protons (P) + Number of  neutrons (N)                      130 = 56 + n n=74

For W74186, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  =W74186Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 74A (mass number) = Number of protons (P) + Number of  neutrons (N)                      186 = 74 + n n= 112

Thus, the number of neutrons, protons and electrons are found as 44,35 and 35 respectively.

For Hg80202, the number of protons, neutrons, and electrons is calculated as follows,

ZAX  = Hg80202Z (atomic number) = Number of protons (number of protons are equalent to number of electrons)= 80A (mass number) = Number of protons (P) + Number of  neutrons (N)                      202 = 80 + n n= 122

Thus, the number of neutrons, protons and electrons are found as 117,78 and 78 respectively.

Conclusion

The number of protons, neutrons and electrons in given species were identified.

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Chapter 2 Solutions

General Chemistry

Ch. 2.7 - Prob. 1PECh. 2.7 - Prob. 2PECh. 2.7 - Prob. 3PECh. 2.7 - Prob. 4PECh. 2.7 - Prob. 5PECh. 2.8 - Prob. 1RCCh. 2 - Prob. 2.1QPCh. 2 - Prob. 2.2QPCh. 2 - Prob. 2.3QPCh. 2 - 2.4 Describe the contributions of these scientists...Ch. 2 - 2.5 A sample of a radioactive element is found to...Ch. 2 - 2.6 Describe the experimental basis for believing...Ch. 2 - Prob. 2.7QPCh. 2 - 2.8 Roughly speaking, the radius of an atom is...Ch. 2 - Prob. 2.9QPCh. 2 - Prob. 2.10QPCh. 2 - 2.11 What is the mass number of an iron atom that...Ch. 2 - Prob. 2.12QPCh. 2 - Prob. 2.13QPCh. 2 - Prob. 2.14QPCh. 2 - Prob. 2.15QPCh. 2 - Prob. 2.16QPCh. 2 - Prob. 2.17QPCh. 2 - Prob. 2.18QPCh. 2 - Prob. 2.19QPCh. 2 - Prob. 2.20QPCh. 2 - Prob. 2.21QPCh. 2 - Prob. 2.22QPCh. 2 - Prob. 2.23QPCh. 2 - Prob. 2.24QPCh. 2 - Prob. 2.25QPCh. 2 - Prob. 2.26QPCh. 2 - Prob. 2.27QPCh. 2 - Prob. 2.28QPCh. 2 - Prob. 2.29QPCh. 2 - Prob. 2.30QPCh. 2 - 2.31 Identify the following as elements or...Ch. 2 - Prob. 2.32QPCh. 2 - Prob. 2.33QPCh. 2 - Prob. 2.34QPCh. 2 - Prob. 2.35QPCh. 2 - Prob. 2.36QPCh. 2 - Prob. 2.37QPCh. 2 - Prob. 2.38QPCh. 2 - Prob. 2.39QPCh. 2 - Prob. 2.40QPCh. 2 - Prob. 2.41QPCh. 2 - Prob. 2.42QPCh. 2 - Prob. 2.43QPCh. 2 - Prob. 2.44QPCh. 2 - Prob. 2.45QPCh. 2 - Prob. 2.46QPCh. 2 - Prob. 2.47QPCh. 2 - Prob. 2.48QPCh. 2 - Prob. 2.49QPCh. 2 - Prob. 2.50QPCh. 2 - Prob. 2.51QPCh. 2 - Prob. 2.52QPCh. 2 - Prob. 2.53QPCh. 2 - Prob. 2.54QPCh. 2 - Prob. 2.55QPCh. 2 - Prob. 2.56QPCh. 2 - Prob. 2.57QPCh. 2 - Prob. 2.58QPCh. 2 - Prob. 2.59QPCh. 2 - Prob. 2.60QPCh. 2 - Prob. 2.62QPCh. 2 - Prob. 2.63QPCh. 2 - Prob. 2.64QPCh. 2 - Prob. 2.65QPCh. 2 - Prob. 2.66QPCh. 2 - Prob. 2.67QPCh. 2 - Prob. 2.68QPCh. 2 - Prob. 2.69QPCh. 2 - Prob. 2.70QPCh. 2 - Prob. 2.71QPCh. 2 - Prob. 2.72QPCh. 2 - Prob. 2.73QPCh. 2 - Prob. 2.74QPCh. 2 - Prob. 2.75QPCh. 2 - Prob. 2.76SPCh. 2 - Prob. 2.77SPCh. 2 - Prob. 2.78SPCh. 2 - Prob. 2.79SPCh. 2 - Prob. 2.80SPCh. 2 - Prob. 2.81SPCh. 2 - Prob. 2.82SP
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