Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 2, Problem 2.13P
To determine
Calculate the percentage of gravels, sands, and fines in the soils based on the Unified Soil Classification System.
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7. Following details regarding the particle size distribution and other index properties pertinent to the classification of soil. Choose three soils and classify
each soil according to USCS and AASHTO classification systems. When necessary, assume Cu = 4.48 and Cc = 1.22. Your solution may be presented in similar
form as what was included in your module 4.
Sieve Analysis (Percent Finer)
Soil No
Liquid Limit
Plastic Limit
No. 10
No. 40
No. 200
98
80
50
38
29
2
100
92
80
56
23
100
88
65
37
22
4
85
55
45
28
20
92
75
62
43
28
6
48
28
N.A.
NP
7
87
62
30
32
24
8
90
76
34
37
25
100
78
8
N.A.
NP
10
92
74
32
44
35
7. Following details regarding the particle size distribution and other index properties pertinent to the classification of soil. Choose three soils and classify
each soil according to USCS and AASHTO classification systems. When necessary, assume Cu = 4.48 and C = 1.22. Your solution may be presented in similar
form as what was included in your module 4.
Sieve Analysis (Percent Finer)
Soil No
Liquid Limit
Plastic Limit
No. 10
No. 40
No. 200
1
98
80
50
38
29
2
100
92
80
56
23
3
100
88
65
37
22
4
85
55
45
28
20
5
92
75
62
43
28
6
48
28
6
N.A.
NP
7
87
62
30
32
24
8
90
76
34
37
25
9
100
78
8
N.A.
NP
10
92
74
32
44
35
The sieve analysis data for a granular soil are given below. % passing or finer 19 mm sieve = 100%% passing or finer 4.75 mm (4 sieve) = 61%% passing or finer 0.075mm (200 sieve) = 16%
What are the percentages of gravels, sands and fines within this soil, based on the Unified Soil Classification System?
Chapter 2 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 2 - Prob. 2.1PCh. 2 - Following are the results of a sieve analysis: a....Ch. 2 - For a soil, given: D10 = 0.08 mm D30 = 0.22 mm D60...Ch. 2 - For a soil, given: D10 = 0.08 mm D30 = 0.22 mm D60...Ch. 2 - Repeat Problem 2.2 with the following results of a...Ch. 2 - Repeat Problem 2.2 with the following results of a...Ch. 2 - The particle characteristics of a soil are given...Ch. 2 - Redo Problem 2.7 according to the USDA system...Ch. 2 - Redo Problem 2.7 according to the AASHTO system...Ch. 2 - In a hydrometer test, the results are as follows:...
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- The grain-size analysis is for a soil is given as follows: Sieve No. Passing Diameter% (mm) 4.75 2.00 0.850 0.425 0.250 0.150 0.075 # 4 #10 #20 # 40 #60 #100 # 200 94 63 21 10 5. 3. Given that the soil is non plastic, classify the soil by using the Unified Soil Classification System. What is the value of the uniformly coefficient Cu. What is the value of the coefficient of gradation Ce What is the value of the sorting coefficient So. O Classify the type of soilarrow_forwardPROBLEM1 The result of the sieve analysis is shown below: a. What is percentage of the soil is retained in no.200 sieve? b. What is the effective grain size of the soil in mm? c. Determine the uniformity coefficient. Sieve no Diameter (mm) Mass retained grams 4 4.76 25 8. 2.23 80 10 2.00 110 20 0.84 160 40 0.42 180 60 0.25 220 80 0.180 380 100 0.149 590 200 0.074 110 PAN 85arrow_forwardFor a given soil, the following are known: Percentage passing 75 mm sieve = 100 Percentage passing No. 4 sieve = 84 Percentage passing No. 200 sieve 10 Liquid limit = 30 % Plastic limit = 22 % D10 = 0.082 mm, D30 = 0.11 mm, D60 = 0.14 mm Classify this soil using the Unified Soil Classification System. Give group symbol and group name.arrow_forward
- Q3 The results of a particle size analysis of a soil are given in the following Table. No Atterberg limit tests were conducted. Sieve No. Percent finer No.40 No.100 | No.200 49.8 No.4 No.10 No.20 70.2 62.5 9.53 mm 100 89.8 28.6 4.1 a) Would you have conducted Atterberg limit tests on this soil? Justify your answer. b) Classify the soil according to USCS and AASHTO. c) Is this soil a good foundation material? Justify your answerarrow_forwardFor an inorganic soil, the following grain-size analysis is given. Knowing that the liquid limit is 23, and Plastic limit is 19. AASHTO soil classification system. Give the group index. I Unified soil classification system. Give group symbol and group name (specific classification). U.S. sieve no. Percent passing 4 100 10 90 20 64 40 38 80 18 200 13arrow_forward22. For a soil specimen, the following are given: % passing Sieve No. 4 = 92% % passing Sieve No. 10 = 81% % passing Sieve No. 40 = 78% % passing Sieve No. 200 = 65% LL = 48% PI = 32% a. Classify the soil by the AASHTO system. b. Classify the soil by the USCS.arrow_forward
- 6- For an inorganic soil, the following grain-size analysis is given. U.S. Sieve No. Percent passing 4 100 06 64 10 20 40 38 80 200 18 13 For this soil, LL = 23 and PL = 19. Classify the soil by using a. AASHTO soil classification system b. Unified soil classification system Give group names and group symbols.arrow_forwardThe results of the particle-size analysis of the soil are as follows: Percent passing No. 10 sieve = 100; Percent passing No. 40 sieve = 80; Percent passing No. 10 sieve = 58.The LL and PI of minus No. 40 fraction of the soil are 30 and 10 respectively. Classify the soil by USCS system a. CH b. SP-SC c. CL-ML d. CL-MLarrow_forwardFor an inorganic soil, the following grain size analysis is given U.S sieve NO. 4 10 20 40 80 200 percent passing 100 90 64 38 18 13 For this soil , L.L = 23 and PL = 19 classify the soil according to: a- The AASHTO soil classification system. b- The unified soil classification system . Give group names and group symbols.arrow_forward
- 1. From the given soil samples below, (a) compute the effective size, uniformity coefficient, and coefficient of gradation (b) Determine the percent of gravel, sand, silt and clay of soil A using AASHTO Sieve size. 0.425 0.033 0.018 0.01 0.0062 0.0035 0.0018 0.001 Soil A Passing Finer (%) 100 90 80 70 60 50 40 35arrow_forwardSITUATION 1 The sieve analysis of three soils and the liquid and plastic limits of the fraction passing no.40 Classify each soil using AASHTO classification system. ( sieve are given below. each Sieve Analysis Diameter Percent Finer (%) Sieve No. (mm) A 4 4.750 90 100 100 8 2.360 64 90 100 10 2.000 54 77 98 20 0.850 34 59 92 40 0.425 22 51 84 60 0.250 17 42 79 100 0.150 9. 35 70 200 0.075 33 63 Characteristics of fraction passing no.40 sieve LL 35 46 47 PL 29 29 24arrow_forward2. The particle size characteristics of a soil is given at the table below. Classify the soil using Textural Classification System/USDA. Size (mm) Percent Finer 100 0.425 0.100 92 0.052 84 0.020 62 0.010 46 0.004 32 0.001 22arrow_forward
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